C++ 实现计算 [x, y] 范围内满足勾股定理的整数组数量

```cpp #include <iostream> int main() { int x, y; std::cin >> x >> y; int count = 0; for (int a = x; a <= y; ++a) { for (int b = a; b <= y; ++b) { for (int c = b; c <= y; ++c) { if (a * a + b * b == c * c) { ++count; } } } } std::cout << count << std::endl; return 0; } ``` ######[AI问答 | 144点数解答 | 2025-09-15 20:24:54]