SELECT a.stat_date AS "订单日期", a.platform AS "平台", a.platform_user_name AS "店铺账号", a.platform_sku AS "平台sku", a.total_orders AS "订单数", a.total_qty AS "销量", a.total_price AS "销售额", a.total_ship_fee AS "运费", a.total_finalvaluefee AS "交易费", a.total_platformfee AS "手续费", a.currency AS "币种", IFNULL(((a.total_orders - b.total_orders) / b.total_orders) * 100, 0) AS "订单数环比值", IFNULL(((a.total_qty - b.total_qty) / b.total_qty) * 100, 0) AS "销量环比值", I
问题： SELECT a.stat_date AS "订单日期", a.platform AS "平台", a.platform_user_name AS "店铺账号", a.platform_sku AS "平台sku", a.total_orders AS "订单数", a.total_qty AS "销量", a.total_price AS "销售额", a.total_ship_fee AS "运费", a.total_finalvaluefee AS "交易费", a.total_platformfee AS "手续费", a.currency AS "币种", IFNULL(((a.total_orders - b.total_orders) / b.total_orders) * 100, 0) AS "订单数环比值", IFNULL(((a.total_qty - b.total_qty) / b.total_qty) * 100, 0) AS "销量环比值", IFNULL( ( ( CASE WHEN a.currency = 'USD' THEN (a.total_price * IFNULL(i.Number1742806223433,0)) / i.Number1742806223433 WHEN a.currency IN ('GBP', 'EUR') THEN (a.total_price * IFNULL(i.Number1742806223433,0)) / subquery.usd_rate ELSE 0 END - CASE WHEN b.currency = 'USD' THEN (b.total_price * IFNULL(i.Number1742806223433,0)) / i.Number1742806223433 WHEN b.currency IN ('GBP', 'EUR') THEN (b.total_price * IFNULL(i.Number1742806223433,0)) / subquery.usd_rate ELSE 0 END ) / CASE WHEN b.currency = 'USD' THEN (b.total_price * IFNULL(i.Number1742806223433,0)) / i.Number1742806223433 WHEN b.currency IN ('GBP', 'EUR') THEN (b.total_price * IFNULL(i.Number1742806223433,0)) / subquery.usd_rate ELSE 1 END ) * 100, 0 ) AS "销售额环比值", IFNULL(((a.total_orders - c.total_orders) / c.total_orders) * 100, 0) AS "订单数同比值", IFNULL(((a.total_qty - c.total_qty) / c.total_qty) * 100, 0) AS "销量同比值", IFNULL( ( ( CASE WHEN a.currency = 'USD' THEN (a.total_price * IFNULL(i.Number1742806223433,0)) / i.Number1742806223433 WHEN a.currency IN ('GBP', 'EUR') THEN (a.total_price * IFNULL(i.Number1742806223433,0)) / subquery.usd_rate ELSE 0 END - CASE WHEN c.currency = 'USD' THEN (c.total_price * IFNULL(i.Number1742806223433,0)) / i.Number1742806223433 WHEN c.currency IN ('GBP', 'EUR') THEN (c.total_price * IFNULL(i.Number1742806223433,0)) / subquery.usd_rate ELSE 0 END ) / CASE WHEN c.currency = 'USD' THEN (c.total_price * IFNULL(i.Number1742806223433,0)) / i.Number1742806223433 WHEN c.currency IN ('GBP', 'EUR') THEN (c.total_price * IFNULL(i.Number1742806223433,0)) / subquery.usd_rate ELSE 1 END ) * 100, 0 ) AS "销售额同比值", i.ShortText1742806216550 AS "币种名称", i.Number1742806223433 AS "汇率", a.total_price * IFNULL(i.Number1742806223433,0) AS "销售额（RMB）", CASE WHEN a.currency = 'USD' THEN i.Number1742806223433 WHEN a.currency IN ('GBP', 'EUR') THEN subquery.usd_rate ELSE NULL END AS "美元汇率", ROUND( CASE WHEN a.currency = 'USD' THEN (a.total_price * IFNULL(i.Number1742806223433,0)) / i.Number1742806223433 WHEN a.currency IN ('GBP', 'EUR') THEN (a.total_price * IFNULL(i.Number1742806223433,0)) / subquery.usd_rate ELSE 0 END, 3 ) AS "销售额（USD）" FROM ods.yc_daily_sales_by_product a LEFT JOIN ods.yc_daily_sales_by_product b ON a.platform = b.platform AND a.platform_user_name = b.platform_user_name AND a.platform_sku = b.platform_sku AND b.stat_date = DATE_SUB(a.stat_date, INTERVAL 1 DAY) LEFT JOIN ods.yc_daily_sales_by_product c ON a.platform = c.platform AND a.platform_user_name = c.platform_user_name AND a.platform_sku = c.platform_sku AND c.stat_date = DATE_SUB(a.stat_date, INTERVAL 1 YEAR) LEFT JOIN cloudpivot.i03ao_rate i ON YEAR(a.stat_date) = YEAR(i.Date1742805689343) AND MONTH(a.stat_da [2025-03-31 17:37:22 | AI问答 | 1757点数解答]
- [讯飞星火] SELECT a.stat_date AS "订单日期", a.platform AS "平台", a.platform_user_name AS "店铺账号", a.platform_sku AS "平台sku", a.total_orders AS "订单数", a.total_qty AS "销量", a.total_price AS "销售额", a.total_ship_fee AS "运费", a.total_finalvaluefee AS "交易费", a.total_platformfee AS "手续费", a.currency AS "币种", IFNULL(((a.total_orders - b.total_orders) / b.total_orders) * 100, 0) AS "订单数环比值", IFNULL(((a.total_qty - b.total_qty) / b.total_qty) * 100, 0) AS "销量环比值", I（1757点数解答 | 2025-03-31 17:37:22）116
- [字节豆包] 请你补全代码，把数组a的所有元素都赋值为100。 输入: 无 输出: 共二十行，每行一个整数，为数组中的每个数。 输入样例: 无 输出样例: 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100#include <iostream> using namespace std; int main() { int a[20]; for ( ) { } for (int i = 0; i < 20; i++) { cout << a[i] << endl; } return 0; }（164点数解答 | 2025-11-01 19:14:57）37
- [字节豆包] 题目描述 给定m行n列的图像各像素点的灰度值，要求用如下方法对其进行模糊化处理： 1.四周最外侧的像素点灰度值不变； 2.中间各像素点新灰度值为该像素点及其上下左右相邻四个像素点原灰度值的平均值(四舍五入)。 输入格式 第一行包含两个整数n和m，表示图像包含像素点的行数和列数。1<=n<=100，1<=m<=100。 接下来n行，每行m个整数，表示图像的每个像素点灰度。相邻两个整数之间用单个空格隔开，每个元素均在0~255之间。 输出格式 m行，每行n个整数，为模糊处理后的图像。相邻两个整数之间用单个空格隔开。 输入样例1 4 5 100 0 100 0 50 50 100 200 0 0 50 50 100 100 200 100 100 50 50 100 输出样例1 100 0 100 0 50 50 80 100 60 0 50 80 100 90 200 100 100 50 50 100 用c++语言 （670点数解答 | 2025-11-10 18:55:33）38
- [字节豆包] 题目描述 给定m行n列的图像各像素点的灰度值，要求用如下方法对其进行模糊化处理： 1.四周最外侧的像素点灰度值不变； 2.中间各像素点新灰度值为该像素点及其上下左右相邻四个像素点原灰度值的平均值(四舍五入)。 输入格式 第一行包含两个整数n和m，表示图像包含像素点的行数和列数。1<=n<=100，1<=m<=100。 接下来n行，每行m个整数，表示图像的每个像素点灰度。相邻两个整数之间用单个空格隔开，每个元素均在0~255之间。 输出格式 m行，每行n个整数，为模糊处理后的图像。相邻两个整数之间用单个空格隔开。 输入样例 4 5 100 0 100 0 50 50 100 200 0 0 50 50 100 100 200 100 100 50 50 100 输出样例 100 0 100 0 50 50 80 100 60 0 50 80 100 90 200 100 100 50 50 100 说明/提示 用c++（655点数解答 | 2025-12-01 14:24:01）15
- [字节豆包] 样例输入： 1 520021910437 99 100 98 zhang san 1 520021910438 99 100 92 zhang san 1 520021910439 90 100 94 li si 1 520021910440 90 100 94 wang wu 2 520021910437 89 100 94 zhang san 3 520021910430 4 520021910437 5 zhang san 6 7 0 样例输出（此处增加了换行以方便解释）： 520021910437 zhang san 89 100 94 520021910437 zhang san 89 100 94 520021910438 zhang san 99 100 92 520021910437 zhang san 89 100 94 520021910438 zhang san 99 100 92 520021910439 li si 90 100 94 520021910440 wang wu 90 100 94 520021910438 zhang san 99 100（28点数解答 | 2024-12-12 11:56:59）324
- [GPT] 帮我优化一下这个sql, 得到的结果是一样的 select to_char(sysdate, 'yyyymmdd') from dual union select to_char(sysdate-1, 'yyyymmdd') from dual union select to_char(sysdate-2, 'yyyymmdd') from dual union select to_char(sysdate-3, 'yyyymmdd') from dual union select to_char(sysdate-5, 'yyyymmdd') from dual（357点数解答 | 2024-08-14 20:08:27）371
- [GPT] 我想得到最近30天内的日期, 比如这样的sql, 但太冗余了, 有没有简化的办法, oracle库里执行: select to_char(sysdate, 'yyyymmdd') from dual union select to_char(sysdate-1, 'yyyymmdd') from dual union select to_char(sysdate-2, 'yyyymmdd') from dual union select to_char(sysdate-3, 'yyyymmdd') from dual union select to_char(sysdate-5, 'yyyymmdd') from dual（320点数解答 | 2024-08-14 20:11:26）224
- [字节豆包] 用c语言实现一个64位地址— select [0] = (6^11^16^…^51) — select [1] = (7^12^17^…^47) — select [2] = (8^13^18^…^48) — select [3] = (9^14^19^…^49) — select [4] = (10^15^20^…^50)（312点数解答 | 2024-11-19 15:34:19）172
- [字节豆包] ．假设自动售货机出售4种商品，薯片(crisps)、爆米花(popcorn)、巧克力(chocolate)和可乐(cola)，售价分别是每份3.0、2.5、4.0和3.5元。在屏幕上显示以下菜单，用户可以连续查询商品的价格，当查询次数超过5次时，自动退出查询；不到5次时，用户可以选择退出。当用户输入编号1～4，显示相应商品的价格；输入0，退出查询；输入其他编号，显示价格为0。 [1] Select crisps [2] Select popcorn [3] Select chocolate [4] Select cola [0] Exit （403点数解答 | 2025-11-24 00:18:28）11
- [字节豆包] 通过get请求url参数 https://xxx.com/we.php?url=33445566 获得we.php?url=后面的 33445566 参数 构建一个新的url https://www.wegame.com.cn/api/forum/lua/wg_video/get_video_play_info?videoid=han_33445566&upload_type=0&platform=2 再请求链接https://www.wegame.com.cn/api/forum/lua/wg_video/get_video_play_info?videoid=han_33445566&upload_type=0&platform=2 列如获取到内容[{"url_list":["https:\/\/ugc-svp.wegame.com.cn\/_0bc35ybegaacjian37nrkjsyh3wdipxaeq2a.f0.mp4?dis_k=609924090fa95c5b93b8c625c3c6508c&dis_t=1725821351"]后 截取内容https:\/\/ugc（262点数解答 | 2024-09-09 04:47:49）217
- [GPT] 用php写一个通过get请求url参数 https://xxx.com/we.php?url=33445566 获得we.php?url=后面的 33445566 参数 构建一个新的url https://www.wegame.com.cn/api/forum/lua/wg_video/get_video_play_info?videoid=han_33445566&upload_type=0&platform=2 再请求链接https://www.wegame.com.cn/api/forum/lua/wg_video/get_video_play_info?videoid=han_33445566&upload_type=0&platform=2 列如获取到内容[{"url_list":["https:\/\/ugc-svp.wegame.com.cn\/_0bc35ybegaacjian37nrkjsyh3wdipxaeq2a.f0.mp4?dis_k=609924090fa95c5b93b8c625c3c6508c&dis_t=1725821351"]后 截取内容https:（291点数解答 | 2024-09-09 04:49:12）275
- [字节豆包] 用php写一个通过get请求url参数 https://xxx.com/we.php?url=33445566 获得we.php?url=后面的 33445566 参数 构建一个新的url https://www.wegame.com.cn/api/forum/lua/wg_video/get_video_play_info?videoid=han_33445566&upload_type=0&platform=2 再请求链接https://www.wegame.com.cn/api/forum/lua/wg_video/get_video_play_info?videoid=han_33445566&upload_type=0&platform=2 列如获取到内容[{"url_list":["https:\/\/ugc-svp.wegame.com.cn\/_0bc35ybegaacjian37nrkjsyh3wdipxaeq2a.f0.mp4?dis_k=609924090fa95c5b93b8c625c3c6508c&dis_t=1725821351"]后 截取内容https:（312点数解答 | 2024-09-09 04:49:45）385