// Photoshop CS6 Script to Convert an Image to a Hand-Drawn Sketch Style #target photoshop app.bringToFront(); if (app.documents.length > 0) { var doc = app.activeDocument; // Step 1: Duplicate the original layer var originalLayer = doc.activeLayer; var duplicatedLayer = originalLayer.duplicate(); duplicatedLayer.name = "Hand Drawn Sketch Layer"; // Step 2: Desaturate the duplicated layer desaturateLayer(); // Step 3: Duplicate the desaturated layer var d


这段代码整体结构清晰,逻辑较为合理。以下是一些优化和改进的建议: 1. 可以添加更多的错误处理机制,比如在执行某些操作时,若出现错误可以给出更详细的错误提示。 2. 给函数和变量添加更具描述性的注释,以提高代码的可理解性。 3. 考虑将一些重复的代码块提取为单独的函数,以增强代码的复用性。 额外需要注意的逻辑点: 1. 注意不同版本的 Photoshop 对某些函数和操作的支持可能有所不同。 2. 确保在执行操作前,用户对图像有适当的保存和备份。 3. 测试代码在处理复杂或大型图像时的性能和稳定性。 [2025-03-02 23:18:21 | AI写代码神器 | 164点数解答]
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- // Photoshop CS6 Script to Convert an Image to a Hand-Drawn Sketch Style #target photoshop app.bringToFront(); if (app.documents.length > 0) { var doc = app.activeDocument; // Step 1: Duplicate the original layer var originalLayer = doc.activeLayer; var duplicatedLayer = originalLayer.duplicate(); duplicatedLayer.name = "Hand Drawn Sketch Layer"; // Step 2: Desaturate the duplicated layer desaturateLayer(); // Step 3: Duplicate the desaturated layer var d(164点数解答 | 2025-03-02 23:18:21)168
- 错误8800 发生了常规ps错误 该功能可能无法在这个版本的ps中使用. - <没有其他信息可用> function getLayerCenterColor(doc, layer) { var originalVisibility = layer.visible; layer.visible = true; doc.activeLayer = layer; var bounds = layer.bounds; var centerX = (bounds[0].value + bounds[2].value) / 2; var centerY = (bounds[1].value + bounds[3].value) / 2; var colorSampler = app.activeDocument.colorSamplers.add([centerX, centerY]); // Obtain array of RGB values. var rgb = [ colorSampler.col(167点数解答 | 2025-05-05 21:30:45)126
- #target photoshopapp.bringToFront(); if (documents.length == 0) { alert("没有可处理的文档"); } else { var visibility = false; var docRef = activeDocument; var layers = docRef.layers; if (layers.length == 1 && docRef.activeLayer.isBackgroundLayer == 1) { alert("The Background layer can not be hidden when it is the only layer in a document."); } else { for (var i = 0; i < layers.length; i++) { layers[i].name = "pic " + [i]; } } } (161点数解答 | 2025-03-11 23:44:44)131
- skill={ trigger:{ player:"shaBegin", }, direct:true, filter:function (event,player){ return event.target.hp>0&&event.target.countCards('he')>0; }, audio:2, logTarget:"target", content:function (){ 'step 0' player.choosePlayerCard(trigger.target,'he', [1,Math.min(trigger.target.countCards('he'),trigger.target.hp)],get.prompt('pojun',trigger.target)); 'step 1' if(result.bool&&result.links.length){ player.logSkill('xinpojun'); if(trigger.target.storage.xinpojun2){ trigger.target.storage.xinpojun2=t(288点数解答 | 2025-07-06 23:39:34)99
- [@biuem2.com_假人系统私人申明] { ;红尘脚本定制版本修改"qq=23751168 #if checklevelex > 0 #act var integer human 假人安全区序号 var integer human 假人系统计算1 var integer human 假人系统计算2 var integer human 假人系统计算3 var integer human 假人系统计算12 var integer human 假人系统计算13 var integer human 假人系统判断1 var integer human 假人站桩判断1 var integer human 假人安全定点x var integer human 假人安全定点y var integer human 假人安全定点t var integer human 假人安全移动间 var integer human 假人安全移动隔 var integer human 假人安全停留间 var integer human 假人安全停留隔 var integer human 假人下图打怪间 var int(37点数解答 | 2024-07-30 18:26:07)254
- var LayerKind = { **ARTOBJECT: 12 }; function toggleSmartObjectLayer() { var targetLayerName = prompt("请输入目标图层名称:"); if (!targetLayerName) { alert("未输入有效的图层名称!"); return; } var doc = app.activeDocument; // 遍历所有图层 for (var i = 0; i < doc.layers.length; i++) { var smartObj = doc.layers[i]; if (smartObj.kind === LayerKind.**ARTOBJECT) { try { smartObj.editContents(); var contents = app.activeDo(650点数解答 | 2025-02-27 17:48:28)141
- skill={ trigger:{ player:"shaBegin", }, direct:true, filter:function (event,player){ return event.target.hp>0&&event.target.countCards('he')>0; }, audio:2, logTarget:"target", content:function (){ 'step 0' player.choosePlayerCard(trigger.target,'he', [1,Math.min(trigger.target.countCards('he'),trigger.target.hp)],get.prompt('pojun',trigger.target)); 'step 1' if(result.bool&&result.links.length){ (286点数解答 | 2025-07-06 23:35:52)112
- content() { "step 0"; player.loseHp(); event.target = trigger.player; "step 1"; event.addIndex = 0; var list = [], num = target.countCards("h") - player.countCards("h"); event.num = num; if (num > 0 && target.countCards("h") > 0) list.push("令其弃置" + get.cnNumber(num) + "张手牌"); else event.addIndex++; if (target.hp > player.hp) list.push("令其失去" + get.cnNumber(target.hp - player.hp) + "点体力"); if (!lis(313点数解答 | 2025-05-28 16:03:47)135
- 翻译以下代码;skill={ audio:3, trigger:{ player:"phaseUseBegin", }, filter:function(event,player){ return game.hasPlayer(target=>target!=player&&!target.isZhu2()); }, direct:true, content:function(){ 'step 0' player.chooseTarget(get.prompt('sbwusheng'),'选择一名非主公的其他角色,本阶段对其使用【杀】无距离和次数限制,使用【杀】指定其为目标后摸一张牌,对其使用五张【杀】后不能对其使用【杀】',(card,player,target)=>{ return target!=player&&!target.isZhu2(); }).set('ai',target=>{ var (522点数解答 | 2025-05-24 13:13:19)173
- // 名片生成脚本 var doc = app.activeDocument; var page = doc.pages[0]; // 设置出血 doc.documentPreferences.documentBleedTop = "3mm"; doc.documentPreferences.documentBleedBottom = "3mm"; // 背景层 var bg = page.rectangles.add(); bg.geometricBounds = ["-3mm", "-3mm", "57mm", "93mm"]; bg.fillColor = doc.colors.add({ colorValue: ["Gradient/003366-006699-45"], gradientStop: [0,50,100] }); // 顶部区块(完整代码详见模板文件) ...(257点数解答 | 2025-02-13 12:48:59)137
- // 名片生成脚本 var doc = app.activeDocument; var page = doc.pages[0]; // 设置出血 doc.documentPreferences.documentBleedTop = "3mm"; doc.documentPreferences.documentBleedBottom = "3mm"; // 背景层 var bg = page.rectangles.add(); bg.geometricBounds = ["-3mm", "-3mm", "57mm", "93mm"]; bg.fillColor = doc.colors.add({ colorValue: ["Gradient/003366-006699-45"], gradientStop: [0,50,100] }); // 顶部区块(完整代码详见模板文件) ...(86点数解答 | 2025-02-13 12:49:37)127
- 下面①~⑦代码,哪些逻辑表达式为 true,哪些为 false? var a = 3; var b = 2; var c = a>b; var d = a<b; var e = a>=b; var f = a<=b; var g = a != b; var aa = '3'; var bb = 3; var cc = aa==bb; var dd = aa===bb;(294点数解答 | 2024-05-20 22:34:44)245