subroutine vumat &(amat, stress, statev, ddsdde, sse, spd, scd, rpl, &ddsddt, drpl, dt, cmname, nblock, ndir, nshr, nstatev, props, &coords, dvolume, temp, dtemp, predef, nload, lanneal, isw, noel, &const, np, nprops, m, n, nn, mat, nstatec, nconst, ithermal, &tempold, ddsddeold, drplold, dtold, ipredef, ithermalold) implicit none !include 'vaba_param.inc' ! define constants real*8, parameter :: zero = 0.0d0, one = 1.0d0, two = 2.0


Based on the provided subroutine header for `vumat`, it seems you are working with a Finite Element Method (FEM) application, likely in the context of an Abaqus user-defined material model (VUMAT). The subroutine has numerous parameters to define the material behavior under various conditions. Below is a skeleton that includes the complete parameters as well as a potential structure for the implementation that follows the provided header. Here’s a simplified version of the subroutine structure you could start with: ```fortran subroutine vumat(amat, stress, statev, ddsdde, sse, spd, scd, rpl, & ddsddt, drpl, dt, cmname, nblock, ndir, nshr, & nstatev, props, coords, dvolume, temp, dtemp, & predef, nload, lanneal, isw, noel, & const, np, nprops, m, n, nn, mat, nstatec, & nconst, ithermal, tempold, ddsddeold, drplold, & dtold, ipredef, ithermalold) implicit none ! Define constants real*8, parameter :: zero = 0.0d0, one = 1.0d0, two = 2.0d0 ! Input parameters real*8, intent(in) :: amat(*) real*8, intent(in) :: stress(*) real*8, intent(inout) :: statev(*) real*8, intent(out) :: ddsdde(:,:) real*8, intent(out) :: sse, spd, scd, rpl real*8, intent(out) :: ddsddt(:,:) real*8, intent(in) :: drpl, dt character(len=*) :: cmname integer, intent(in) :: nblock, ndir, nshr, nstatev real*8, intent(in) :: props(*) real*8, intent(in) :: coords(*) real*8, intent(in) :: dvolume real*8, intent(in) :: temp, dtemp real*8, intent(in) :: predef(*) integer, intent(in) :: nload integer, intent(in) :: lanneal, isw, noel real*8, intent(in) :: const(*) integer, intent(in) :: np, nprops, m, n, nn, mat integer, intent(in) :: nstatec, nconst, ithermal real*8, intent(in) :: tempold real*8, intent(in) :: ddsddeold(:,:) real*8, intent(in) :: drplold, dtold integer, intent(in) :: ipredef(*) integer, intent(in) :: ithermalold ! Declare variables (if needed) integer :: i, j ! Add your local variables here ! Initialize these outputs sse = zero spd = zero scd = zero rpl = zero ! Example of material behavior logic ! Modify stress, ddsdde and state variables based on the material model being used ! For illustrative purposes do i = 1, nstatev statev(i) = zero ! Initialize or update internal state variable end do ! Compute stress and tangent stiffness stress(1) = stress(1) + one ! Simple example of stress update ddsdde(1,1) = one ! Example of modifying stiffness matrix ! Finalize the outputs return end subroutine vumat ``` Explanation: - Parameters: The `vumat` subroutine takes a variety of input and output parameters. Specifying `intent` (in, out, inout) indicates how each parameter will be used. - Constants: A few basic constants (zero, one, two) are defined for convenience. - Variable Initialization and Updates: Inside the subroutine, variables need to be initialized according to your material model's requirements. The example demonstrated is a very simplistic way to update stress and stiffness, which you will need to replace with actual material behavior calculations based on your specific requirements. - Looping Over State Variables: You may have internal state variables or calculations that need to be updated, and you can loop through them as needed. Next Steps: - Expand the logic of this subroutine based on the material model you are implementing. - Make sure to validate the assumptions and computations to ensure they reflect the physical behavior of the material you are modeling. - Depending on the complexity and the specific behavior of your material, you may need to include additional computations or state variable updates within the body of the subroutine. [2024-08-17 10:19:58 | AI写代码神器 | 2664点数解答]
- subroutine vumat &(amat, stress, statev, ddsdde, sse, spd, scd, rpl, &ddsddt, drpl, dt, cmname, nblock, ndir, nshr, nstatev, props, &coords, dvolume, temp, dtemp, predef, nload, lanneal, isw, noel, &const, np, nprops, m, n, nn, mat, nstatec, nconst, ithermal, &tempold, ddsddeold, drplold, dtold, ipredef, ithermalold) implicit none !include 'vaba_param.inc' ! define constants real*8, parameter :: zero = 0.0d0, one = 1.0d0, two = 2.0(2664点数解答 | 2024-08-17 10:19:58)165
- 以读、二进制方式打开c盘temp文件夹下abc.txt文件的代码是()[测3] a. f=open(c:/temp/abc.txt,'bt') b. f=open('c://temp//abc.txt','rb') c. f=open('c:\temp\abc.txt','rb') d. f=open('c:/temp/abc.txt','wb') e. f=open('c:\\temp\\abc.txt','rb') f. f=open('c:/temp/abc.txt','rb') g. f=open('c://temp//abc.txt':'rb') h. f=open('c:\\temp\\abc.txt','ab')(15点数解答 | 2024-06-06 13:53:37)289
- 使用下列代码创建数据框,完成以下的填空题。 import numpy as np import pandas as pd index = pd.Index(data=["Tom", "Bob", "Mary", "James", "Andy", "Alice"], name="name") data = { "age": [18, 30, np.nan, 40, np.nan, 30], "city": ["Bei Jing ", "Shang Hai ", "Guang Zhou", "Shen Zhen", np.nan, " "], "income": [None, 11, 22,33, np.nan, 55], "sex": [None, "male", "female", "male", np.nan, "male"], "birth": ["2000-02-10", "1988-10-17", None, "1978-08-08", np.nan, "1988-10-17"] } (1)使用data为数据,ind(563点数解答 | 2025-04-14 18:30:52)100
- ```python import numpy as np import matplotlib.pyplot as plt from matplotlib.animation import FuncAnimation from mpl_toolkits.mplot3d import Axes3D # 设置图形 fig = plt.figure(figsize=(10, 8)) ax = fig.add_subplot(111, projection='3d') ax.set_facecolor('black') fig.patch.set_facecolor('black') # 爱心参数方程 def heart(t): x = 16 * np.sin(t) 3 y = 13 * np.cos(t) - 5 * np.cos(2*t) - 2 * np.cos(3*t) - np.cos(4*t) return x, y # 生成爱心形状的点 t = np.linspace(0, 2*np.pi, 1000) x, y = heart(t) z = np.(1487点数解答 | 2025-08-07 11:24:56)62
- ```python import numpy as np import matplotlib.pyplot as plt from matplotlib.animation import FuncAnimation from mpl_toolkits.mplot3d import Axes3D # 设置图形 fig = plt.figure(figsize=(10, 8)) ax = fig.add_subplot(111, projection='3d') ax.set_facecolor('black') fig.patch.set_facecolor('black') # 爱心参数方程 def heart(t): x = 16 * np.sin(t) 3 y = 13 * np.cos(t) - 5 * np.cos(2*t) - 2 * np.cos(3*t) - np.cos(4*t) return x, y # 生成爱心形状的点 t = np.linspace(0, 2*np.pi, 1000) x, y = heart(t) z = np.(130点数解答 | 2025-08-29 21:24:33)52
- #include<stdio.h> #include<malloc.h>//动态存储分配函数头文件 #include<math.h>//包含数学函数的文件 #include<string.h>//一个和字符串处理相关的头文件 #include<process.h>//包含用于和宏指令的作用声明 #define error 0 //宏定义 #define ok 1 #define over -2 #define listinitsize 20 #define listincrement 5 #define namelen 8 #define majorlen 20 #define init_n 3 typedef int status; //自定义类型语句 status i 等价于 int i typedef char statusc; typedef struct{ statusc number[10]; //学号 statusc name[namelen+1]; //姓名 statusc gender; //性别 statusc telephone[12]; //电话 st(1142点数解答 | 2024-11-07 19:08:54)175
- #include "stm32f10x.h" // 有问题和需求的,可以联系VX:lwfw********* #include <stdio.h> #include <string.h> #include "sys.h" #include "delay.h" #include "OLED.h" #include "dht11.h" //温湿度传感器 #include "Key.h" #include "jidianqi.h" #include "OLED.h" #include "Serial.h" #include "LED.h" #include "Buzzer.h" #include "Motor.h" #include "CountSensor.h" #include "AD.h" uint16_t AD0; //存储ADC的值 uint8_t KeyNum; //存储按键值 uint8_t RxData; //蓝牙接收到的数据 u8 temp, humi; //存储温湿度 float temp1; //(25点数解答 | 2025-05-06 01:13:43)100
- #define USE_FC16_HW 1 #include <MD_MAX72xx.h> #include <SPI.h> #define FC16_HW 1 #define HARDWARE_TYPE FC16_HW #define MAX_DEVICES 1 #define CS_PIN 12 // D8 对应 GPIO15 MD_MAX72XX mx = MD_MAX72XX(HARDWARE_TYPE, CS_PIN, MAX_DEVICES); // 蛇定义 #define WIDTH 8 #define HEIGHT 8 int snakeX[64], snakeY[64]; int snakeLength = 3; int dirX = 1, dirY = 0; int foodX = 3, foodY = 3; // 按键 A0 #define KEY_PIN A0 void setup() { mx.begin(); mx.clear(); randomSeed(analogRead(0)); // 初始化蛇身体 for (int i(1917点数解答 | 2025-07-23 14:49:18)83
- // #define USE_FC16_HW 1 // #include <MD_MAX72xx.h> // #include <SPI.h> // #define FC16_HW 1 // #define HARDWARE_TYPE FC16_HW // #define MAX_DEVICES 1 // #define CS_PIN 12 // D8 对应 GPIO15 // MD_MAX72XX mx = MD_MAX72XX(HARDWARE_TYPE, CS_PIN, MAX_DEVICES); // // 蛇定义 // #define WIDTH 8 // #define HEIGHT 8 // int snakeX[64], snakeY[64]; // int snakeLength = 3; // int dirX = 1, dirY = 0; // int foodX = 3, foodY = 3; // // 按键 A0 // #define KEY_PIN A0 // void setup() { // mx.begin(); // mx.cle(1329点数解答 | 2025-07-23 15:07:45)86
- import numpy as np a=np.zeros(10) a[4]=1 b=np.append(a,2) print(b) c=np.array.random.randint(0,100,20) print(c) # d=np.where((c>=60 | c==0),1,c) print(np.where((c>=60 | c==0),1,c)) #n1=np.zeros(10)(286点数解答 | 2025-03-06 20:23:41)176
- 题目描述 给定一个长为 nn 的序列 a_1, a_2,a_3, \dots ,a_na 1 ,a 2 ,a 3 ,…,a n ,你需要执行 kk 次操作使这个序列为空。 每次操作可以执行下列内容之一: 选择两个数 i, ji,j,交换 a_i, a_ja i ,a j (需要满足 1 \le i < j \le n1≤i<j≤n)。 选择两个数 i, ji,j,删除 a_i,a_{i+1}, \dots ,a_ja i ,a i+1 ,…,a j (需要满足 1 \le i \le j \le n1≤i≤j≤n,且 a_i = a_ja i =a j )。 请输出最小的操作数 kk。 输入格式 第一行输入一个正整数 tt(1 \le t \le 51≤t≤5),表示有 tt 个测试数据。 对于每个测试数据: 第一行输入一个正整数 nn(1 \le n \le 10^51≤n≤10 5 ),表示序列长度为 nn。 第二行输入 nn 个正整数 a_1,a_2 \dots a_na 1 ,a 2 …a n (0 \le a_i \le 10^90≤a i ≤10 9 )。 输出格式 对于每个测试数据输出一个正整数 kk,表示最少的操作次数。 输入输出样例 输入 #1 复制 2 5 1 2 3 2 3 3 1000000000 1000000000 99999999 输出 #1 复制 2 2 说明/提示 数据范围 子任务 分值 限制 11 1010 n\le 3n≤3 22 2020 n\le 10n≤10 33 2020 a_i\le 2a i ≤2 44 1010 保证所有 a_ia i 相等 55 4040 - 对于 100\%100% 的数据,1\le t \le 51≤t≤5,1\le n\le 10^51≤n≤10 5 ,0\le a_i\le 10^90≤a i ≤10 9 。,语言方向:C++,系统环境:Windows(462点数解答 | 2024-12-21 17:35:25)318
- 题目描述 给定一个长为 nn 的序列 a_1, a_2,a_3, \dots ,a_na 1 ,a 2 ,a 3 ,…,a n ,你需要执行 kk 次操作使这个序列为空。 每次操作可以执行下列内容之一: 选择两个数 i, ji,j,交换 a_i, a_ja i ,a j (需要满足 1 \le i < j \le n1≤i<j≤n)。 选择两个数 i, ji,j,删除 a_i,a_{i+1}, \dots ,a_ja i ,a i+1 ,…,a j (需要满足 1 \le i \le j \le n1≤i≤j≤n,且 a_i = a_ja i =a j )。 请输出最小的操作数 kk。 输入格式 第一行输入一个正整数 tt(1 \le t \le 51≤t≤5),表示有 tt 个测试数据。 对于每个测试数据: 第一行输入一个正整数 nn(1 \le n \le 10^51≤n≤10 5 ),表示序列长度为 nn。 第二行输入 nn 个正整数 a_1,a_2 \dots a_na 1 ,a 2 …a n (0 \le a_i \le 10^90≤a i ≤10 9 )。 输出格式 对于每个测试数据输出一个正整数 kk,表示最少的操作次数。 输入输出样例 输入 #1 复制 2 5 1 2 3 2 3 3 1000000000 1000000000 99999999 输出 #1 复制 2 2 说明/提示 数据范围 子任务 分值 限制 11 1010 n\le 3n≤3 22 2020 n\le 10n≤10 33 2020 a_i\le 2a i ≤2 44 1010 保证所有 a_ia i 相等 55 4040 - 对于 100\%100% 的数据,1\le t \le 51≤t≤5,1\le n\le 10^51≤n≤10 5 ,0\le a_i\le 10^90≤a i ≤10 9 。,语言方向:C++,系统环境:Windows(812点数解答 | 2024-12-21 17:36:14)374