import numpy as np import math from datetime import datetime, timedelta from pymoo.core.problem import elementwiseproblem k_legal = 0.0005624701263657791 b=6371 b=7371 phi=30.35 pi=3.1415926 standard_meridian=120 mean1=9.38167 dev1=0.22401 mean2=4816.70238 dev2=164.0126 def calculate_length(phi, delta, omega, b, b): phi_rad = np.radians(phi) delta_rad = np.radians(delta) omega_rad = np.radians(omega) r_prime = b * np.sin(phi_rad - delta_rad) r_double_prime = b * np.cos(phi_
请问您是希望我为您解释这段代码的作用、优化它,还是基于这段代码为您补充一些相关的内容呢? [2024-08-04 10:23:08 | AI写代码神器 | 30点数解答]
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- [字节豆包] import numpy as np import math from datetime import datetime, timedelta from pymoo.core.problem import elementwiseproblem k_legal = 0.0005624701263657791 b=6371 b=7371 phi=30.35 pi=3.1415926 standard_meridian=120 mean1=9.38167 dev1=0.22401 mean2=4816.70238 dev2=164.0126 def calculate_length(phi, delta, omega, b, b): phi_rad = np.radians(phi) delta_rad = np.radians(delta) omega_rad = np.radians(omega) r_prime = b * np.sin(phi_rad - delta_rad) r_double_prime = b * np.cos(phi_(30点数解答 | 2024-08-04 10:23:08)227
- [字节豆包] #include <stdio.h> #include <math.h> #define pi 3.14159265358979323846 double meridianarclength(double b) { double a = 6378140.0; double e2 = 0.00669438002290; double m = a * (1 - e2) * (1 - e2 * sin(b) * sin(b)) * pow(1 - e2 * sin(b) * sin(b), 1.5); double n = a / sqrt(1 - e2 * sin(b) * sin(b)); return m + n * sin(b) * cos(b) * pow(tan(b),2) /2 + n * sin(b) * pow(cos(b), 3) * (5 - pow(tan(b), 2) + 9 * e2 * pow(cos(b), 2)) * pow(tan(b), 4) / 24; } double calculatebaselatitude(double x,(48点数解答 | 2024-11-21 13:05:21)193
- [阿里通义] #include <stdio.h> #include <math.h> #define pi 3.14159265358979323846 double meridianarclength(double b) { double a = 6378140.0; double e2 = 0.00669438002290; double m = a * (1 - e2) * (1 - e2 * sin(b) * sin(b)) * pow(1 - e2 * sin(b) * sin(b), 1.5); double n = a / sqrt(1 - e2 * sin(b) * sin(b)); return m + n * sin(b) * cos(b) * pow(tan(b),2) /2 + n * sin(b) * pow(cos(b), 3) * (5 - pow(tan(b), 2) + 9 * e2 * pow(cos(b), 2)) * pow(tan(b), 4) / 24; } double calculatebaselatitude(double x, double y)(565点数解答 | 2024-11-21 13:08:38)198
- [字节豆包] ```python import numpy as np import matplotlib.pyplot as plt from matplotlib.animation import FuncAnimation from mpl_toolkits.mplot3d import Axes3D # 设置图形 fig = plt.figure(figsize=(10, 8)) ax = fig.add_subplot(111, projection='3d') ax.set_facecolor('black') fig.patch.set_facecolor('black') # 爱心参数方程 def heart(t): x = 16 * np.sin(t) 3 y = 13 * np.cos(t) - 5 * np.cos(2*t) - 2 * np.cos(3*t) - np.cos(4*t) return x, y # 生成爱心形状的点 t = np.linspace(0, 2*np.pi, 1000) x, y = heart(t) z = np.(1487点数解答 | 2025-08-07 11:24:56)90
- [DeepSeek] ```python import numpy as np import matplotlib.pyplot as plt from matplotlib.animation import FuncAnimation from mpl_toolkits.mplot3d import Axes3D # 设置图形 fig = plt.figure(figsize=(10, 8)) ax = fig.add_subplot(111, projection='3d') ax.set_facecolor('black') fig.patch.set_facecolor('black') # 爱心参数方程 def heart(t): x = 16 * np.sin(t) 3 y = 13 * np.cos(t) - 5 * np.cos(2*t) - 2 * np.cos(3*t) - np.cos(4*t) return x, y # 生成爱心形状的点 t = np.linspace(0, 2*np.pi, 1000) x, y = heart(t) z = np.(130点数解答 | 2025-08-29 21:24:33)82
- [字节豆包] package com.bjrl.matrix.controller; import com.bjrl.common.annotation.Log; import com.bjrl.common.core.controller.BaseController; import com.bjrl.common.core.domain.AjaxResult; import com.bjrl.common.core.domain.entity.AccountNumberInfo; import com.bjrl.common.core.domain.entity.MatrixAncestors; import com.bjrl.common.core.page.TableDataInfo; import com.bjrl.common.enums.BusinessType; import com.bjrl.common.utils.poi.ExcelUtil; import com.bjrl.matrix.domain.PrintConfig; import com.bjrl.matrix.d(698点数解答 | 2025-09-15 10:13:12)65
- [阿里通义] import math class ball: def __init__(self, radius): """ 初始化球体对象,设置半径。 """ self.radius = radius def surface_area(self): """ 计算并返回球的表面积。 表面积公式:4 * pi * r^2 """ return 4 * math.pi * self.radius ** 2 def volume(self): """ 计算并返回球的体积。 体积公式:(4/3) * pi * r^3 """ return (4/3) * math.pi * self.radius ** 3 # 在评测文件中将这样调用这个类 ball = ball(eval(input())) print("球的半径:{:.2f}".format(ball(297点数解答 | 2024-11-28 21:18:01)195
- [DeepSeek] import os import datetime from flask import Flask, request, jsonify import requests from flask_cors import CORS import re import matplotlib matplotlib.use('Agg') import matplotlib.pyplot as plt import numpy as np import base64 from io import BytesIO import pandas as pd import traceback # 添加traceback以获取详细错误信息 plt.rcParams["font.sans-serif"] = ["SimHei"] app = Flask(__name__) CORS(app) FASTGPT_API_URL = 'http://localhost:3000/api/v1/chat/completions' FASTGPT_API_KEY = 'fastgpt-gWzitHpBa8XRr0q(713点数解答 | 2025-06-18 16:00:34)145
- [阿里通义] 使用下列代码创建数据框,完成以下的填空题。 import numpy as np import pandas as pd index = pd.Index(data=["Tom", "Bob", "Mary", "James", "Andy", "Alice"], name="name") data = { "age": [18, 30, np.nan, 40, np.nan, 30], "city": ["Bei Jing ", "Shang Hai ", "Guang Zhou", "Shen Zhen", np.nan, " "], "income": [None, 11, 22,33, np.nan, 55], "sex": [None, "male", "female", "male", np.nan, "male"], "birth": ["2000-02-10", "1988-10-17", None, "1978-08-08", np.nan, "1988-10-17"] } (1)使用data为数据,ind(563点数解答 | 2025-04-14 18:30:52)127
- [字节豆包] import pygame import numpy as np import math import random # 初始化pygame pygame.init() # 获取屏幕尺寸并设置全屏 info = pygame.display.Info() WIDTH, HEIGHT = info.current_w, info.current_h screen = pygame.display.set_mode((WIDTH, HEIGHT), pygame.FULLSCREEN) pygame.display.set_caption("3D爱心粒子跳动") # 颜色定义 RED = (255, 50, 50) PINK = (255, 100, 200) WHITE = (255, 255, 255) # 粒子类 class Particle: def __init__(self): # 3D爱心参数方程 t = random.uniform(0, 2 * math.pi) size = random.uniform(2(1111点数解答 | 2025-07-28 22:34:46)89
- [字节豆包] import pygame import numpy as np import math import random # 初始化pygame pygame.init() # 获取屏幕尺寸并设置全屏 info = pygame.display.Info() WIDTH, HEIGHT = info.current_w, info.current_h screen = pygame.display.set_mode((WIDTH, HEIGHT), pygame.FULLSCREEN) pygame.display.set_caption("3D爱心粒子跳动") #颜色定义 RED = (255, 50, 50) PINK = (255,100, 200) WHITE = (255, 255,255) # 粒子类 class Particle: def __init__(self): # 3D爱心参数方程 t = random.uniform(0, 2 * math.pi) size = random.uniform(2, 5) # 爱心形状参数 # 修正此处的语法错误,添加 *(1142点数解答 | 2025-07-28 22:36:37)87
- [字节豆包] matlab绘制三维曲线。 x=(2+cos t/2)cos t y=(2+cos t/2)sin t,o≤t≤2π z=sin t/2(189点数解答 | 2024-10-25 08:50:55)154