select to_char(systimestamp,'yyyymmddhh24miss') from dual


这个查询语句用于在Oracle数据库中获取当前时间的格式化字符串。它将当前时间转换为字符串形式,格式为:年月日小时分钟秒。 [2024-01-17 17:20:23 | AI写代码神器 | 61点数解答]
相关提问
- 帮我优化一下这个sql, 得到的结果是一样的 select to_char(sysdate, 'yyyymmdd') from dual union select to_char(sysdate-1, 'yyyymmdd') from dual union select to_char(sysdate-2, 'yyyymmdd') from dual union select to_char(sysdate-3, 'yyyymmdd') from dual union select to_char(sysdate-5, 'yyyymmdd') from dual(357点数解答 | 2024-08-14 20:08:27)353
- 我想得到最近30天内的日期, 比如这样的sql, 但太冗余了, 有没有简化的办法, oracle库里执行: select to_char(sysdate, 'yyyymmdd') from dual union select to_char(sysdate-1, 'yyyymmdd') from dual union select to_char(sysdate-2, 'yyyymmdd') from dual union select to_char(sysdate-3, 'yyyymmdd') from dual union select to_char(sysdate-5, 'yyyymmdd') from dual(320点数解答 | 2024-08-14 20:11:26)207
- select to_char(systimestamp,'yyyymmddhh24miss') from dual(61点数解答 | 2024-01-17 17:20:23)225
- 用c语言实现一个64位地址— select [0] = (6^11^16^…^51) — select [1] = (7^12^17^…^47) — select [2] = (8^13^18^…^48) — select [3] = (9^14^19^…^49) — select [4] = (10^15^20^…^50)(312点数解答 | 2024-11-19 15:34:19)152
- select 1 from dual 占用cpu高(180点数解答 | 2024-01-17 18:01:38)217
- select c.table_name, c.constraint_name, c.constraint_type, c.status, c.r_owner, c.r_constraint_name, (select rc.table_name from all_constraints rc where rc.owner = c.r_owner and rc.constraint_name = c.r_constraint_name) as r_table_name, c.delete_rule, ( select listagg(column_name || ':' || position,',') within group (order by "position") from all_cons_columns col where col.owner =:1 and col.table_name = :2 and col.constraint_n(25点数解答 | 2024-01-17 17:17:40)264
- if (@code2 like 'item_ch_' + @itemcodeprefix + '_a_rare' and @optlevel >= 1 - @ck and @cl1 = 24670 and @cl2 = 24669 and @clsl1 > 1 and @clsl2 > 1) begin select @charname = charname16 from _char where charid = @charid; update _inventory set itemid=0 where charid=@charid and slot=13 update sro_vt_shard.._items set data=data-1 where id64 in (select itemid from sro_vt_shard.._inventory where slot=14and charid=@charid) update sro_vt_shard.._items set data=data-1 where id64 in (select itemid from sro_(969点数解答 | 2024-10-22 11:26:02)260
- select distinct t.id_card,t.`start`,t.`end` from ((select distinct(person_name), id_card , date_format( curdate(), "%y-%m-%d 00:00:00" ) start , date_format( curdate(), "%y-%m-%d 23:59:59" ) end, '1' ordertype, '-1' pass from t_contractor_people where person_name in ( select distinct ( b.executor ) from t_task_work_order a left join t_task_work_person b on a.sheet_id = b.hot_work_id where a.valid = '1' and a.work_start_time > date_format( curdate(), "%y-%m-%d 00:00:00(342点数解答 | 2024-12-05 12:31:57)153
- select distinct t.id_card,t.`start`,t.`end` from ((select distinct(person_name), id_card , date_format( curdate(), "%y-%m-%d 00:00:00" ) start , date_format( curdate(), "%y-%m-%d 23:59:59" ) end, '1' ordertype, '-1' pass from t_contractor_people where person_name in ( select distinct ( b.executor ) from t_task_work_order a left join t_task_work_person b on a.sheet_id = b.hot_work_id where a.valid = '1' and a.work_start_time > date_format( curdate(), "%y-%m-%d 00:00:00(24点数解答 | 2024-12-05 12:32:54)182
- if (@code2 like 'item_ch_' + @itemcodeprefix + '_a_rare' and @optlevel >= 1 - @ck and @cl1 = 24670 and @cl2 = 24669 and @clsl1 > 1 and @clsl2 > 1) begin select @charname = charname16 from _char where charid = @charid; update _inventory set itemid=0 where charid=@charid and slot=13 update sro_vt_shard.._items set data=data-1 where id64 in (select itemid from sro_vt_shard.._inventory where slot=14and charid=@charid) update sro_vt_shard.._items set data=data-1 where id64 in ((51点数解答 | 2024-10-22 11:24:35)202
- <!DOCTYPE html> <html> <head> <title>服装工艺智能系统</title> <style> .module { margin: 20px; padding: 15px; border: 1px solid #ddd; } </style> </head> <body> <div class="module"> <h2>工艺查询</h2> <select id="category"> <option value="冲锋衣">冲锋衣</option> <option value="衬衫">女衬衫</option> </select> <button onclick="loadProcess()">查询工艺</button> </div> <div id="3d-preview" class="module"> (194点数解答 | 2025-05-26 12:08:20)106
- 作为golang开发,阐述 go 的 select 底层数据结构和一些特性?(481点数解答 | 2023-11-09 18:14:38)238