<!doctype html public "-//w3c//dtd xhtml 1.0 transitional//en" "http://www.w3.org/tr/xhtml1/dtd/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="content-type" content="text/html; charset=utf-8" /> <title>无标题文档</title> <script> function getnowdate(){ var today=new date(); var d=new array("星期日","星期一","星期二","星期三","星期四","星期五","星期六"); var nowdate= ""; nowdate = showlocale();// 获取当前时间 年月日 时分秒 nowdate = nowdate+ " "+ d[today.ge
这段代码存在一些错误。以下是修正后的代码： ```html <!doctype html public "-//w3c//dtd xhtml 1.0 transitional//en" "http://www.w3.org/tr/xhtml1/dtd/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="content-type" content="text/html; charset=utf-8" /> <title>无文档</title> <script> function getnowdate(){ var today = new Date(); var d = ["星期日","星期一","星期二","星期三","星期四","星期五","星期六"]; var nowdate = ""; nowdate = today.toLocaleString(); // 获取当前时间 年月日 时分秒 nowdate = nowdate + " " + d[today.getDay()]; } </script> </head> <body> </body> </html> ``` 在上述修正后的代码中： - 将 `new array` 修正为 `[]` 来创建数组。 - 使用 `toLocaleString` 方法获取本地格式的日期时间字符串。 - 通过 `getDay` 方法获取星期几的索引，并从数组 `d` 中获取对应的星期字符串。 [2024-08-06 13:24:39 | AI写代码神器 | 284点数解答]
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