因数之和奇偶性判断：C++代码实现

```cpp #include <iostream> #include <cmath> using namespace std; // 计算单个数字的因数之和 int sumOfDivisors(int num) { int sum = 1; // 1是任何数的因数 int sqrtNum = sqrt(num); for (int i = 2; i <= sqrtNum; i++) { if (num % i == 0) { sum += i; int pair = num / i; if (pair != i) { sum += pair; } } } return sum; } int main() { int m, n; cin >> m >> n; bool allEven = true; for (int i = m; i <= n; i++) { int sum = sumOfDivisors(i); if (sum % 2 != 0) { allEven = false; break; } } cout << (allEven ? "Safe" : "Trap") << endl; return 0; } ``` ######[AI问答 | 237点数解答 | 2026-06-20 20:13:31]