C语言实现：求a+aa+aaa+...+aa...a（n个a）之和的代码解析

#include <stdio.h> int main() { int a, n; int sum = 0; int term = 0; // 输入a和n scanf("%d %d", &a, &n); // 计算各项的和 for (int i = 0; i < n; i++) { term = term * 10 + a; sum += term; } // 输出结果 printf("s = %d\n", sum); return 0; } ######[AI写代码神器 | 214点数解答 | 2024-11-13 16:07:25]