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Python ```python n = int(input()) while n != 1: if n % 2 == 0: print(f"{n}/2={n // 2}") n //= 2 else: print(f"{n}*3+1={n * 3 + 1}") n = n * 3 + 1 ``` Pascal ```pascal program Hailstone; var n: longint; begin readln(n); while n <> 1 do begin if n mod 2 = 0 then begin writeln(n, '/2=', n div 2); n := n div 2; end else begin writeln(n, '*3+1=', n * 3 + 1); n := n * 3 + 1; end; end; end. ``` C++ ```cpp #include <iostream> using namespace std; int main() { int n; cin >> n; while (n != 1) { if (n % 2 == 0) { cout << n << "/2=" << n / 2 << endl; n /= 2; } else { cout << n << "*3+1=" << n * 3 + 1 << endl; n = n * 3 + 1; } } return 0; } ``` C ```c #include <stdio.h> int main() { int n; scanf("%d", &n); while (n != 1) { if (n % 2 == 0) { printf("%d/2=%d\n", n, n / 2); n /= 2; } else { printf("%d*3+1=%d\n", n, n * 3 + 1); n = n * 3 + 1; } } return 0; } ``` Java ```java import java.util.Scanner; public class Main { public static void main(String[] args) { Scanner scanner = new Scanner(System.in); int n = scanner.nextInt(); while (n != 1) { if (n % 2 == 0) { System.out.println(n + "/2=" + (n / 2)); n /= 2; } else { System.out.println(n + "*3+1=" + (n * 3 + 1)); n = n * 3 + 1; } } } } ``` ######[AI问答 | 562点数解答 | 2025-12-27 19:49:58]