C++实现：求解 1!+2!+3!+…+n!（n≤50）的代码解析

```cpp #include <iostream> using namespace std; int main() { int n; cin >> n; long long factorial = 1; long long sum = 0; for (int i = 1; i <= n; i++) { factorial *= i; sum += factorial; } cout << sum << endl; return 0; } ``` ######[AI问答 | 99点数解答 | 2025-09-26 19:32:04]