阅读以下代码 /* * copyright 2016 google inc. all rights reserved. * * licensed under the apache license, version 2.0 (the "license"); * you may not use this file except in compliance with the license. * you may obtain a copy of the license at * * http://www.apache.org/licenses/license-2.0 * * unless required by applicable law or agreed to in writing, software * distributed under the license is distributed on an "as is" basis, * without warranties or conditions of any kind, either expres
这段代码看起来是一段版权声明和关于许可证的说明。它指出版权归 2016 年的谷歌公司所有,并提到了软件的使用遵循 Apache 许可证 2.0 版本。但后续的说明似乎不完整,可能缺失了一些关键信息。请问您是希望我对这段代码的格式、内容含义做更详细的解释,还是基于这段代码为您提供一些相关的拓展内容? [2024-11-11 19:53:55 | AI写代码神器 | 93点数解答]
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- [DeepSeek] //+------------------------------------------------------------------+ //| ZigZagBollingerEA.mq4 | //| Copyright 2024, MetaQuotes Software Corp. | //| https://www.mql5.com | //+------------------------------------------------------------------+ #property copyright "Copyright 2024, MetaQuotes Software Corp." #property link "https://www.mql5.com" #property version "1.00" #pro(504点数解答 | 2025-04-23 10:56:16)169
- [DeepSeek] //+------------------------------------------------------------------+ //| ZigZagBollingerEA.mq4 | //| Copyright 2024, MetaQuotes Software Corp. | //| https://www.mql5.com | //+------------------------------------------------------------------+ #property copyright "Copyright 2024, MetaQuotes Software Corp." #property link "https://www.mql5.com" #property version "1.00" #pro(446点数解答 | 2025-04-23 10:57:55)160
- java.sql.sqlsyntaxerrorexception: you have an error in your sql syntax; check the manual that corresponds to your mariadb server version for the right syntax to use near '*) from o_outorder_detail where pid= 397' at line 1 ### the error may exist in file [f:\gtkj\2024\yywmsccglxt\code\wms\tdt-vip-main\target\classes\com\tdt\modular\outstore\mapper\mapping\outorderdetailmapper.xml] ### the error may involve defaultparametermap ### the error occurred while setting parameters ### sql: select count(350点数解答 | 2024-04-25 08:26:19)356
- [GPT] // // main.cpp // step1 // // created by ljpc on 2018/8/31. // copyright © 2018年 ljpc. all rights reserved. // #include <iostream> #include <stack> #include <cstring> #include <algorithm> using namespace std; int main(int argc, const char * argv[]) { // 请在这里补充代码,完成本关任务 /********* begin *********/ stack<char> s1; stack<char> s2; char s[200]; fgets(s,200,stdin); int len=strlen(s); if(s[len-1]=='\n'){ s[len-1]='\0'; len--; } char(518点数解答 | 2024-10-25 17:28:04)220
- [字节豆包] 题目描述 输出 <math xmlns="http://www.w3.org/1998/Math/MathML"> <mi>n</mi> <mo>!</mo> </math> 的不同因子的个数? 输入 一个整数<math xmlns="http://www.w3.org/1998/Math/MathML"> <mi>n</mi> </math> 输出 输出<math xmlns="http://www.w3.org/1998/Math/MathML"> <mi>n</mi> <mo>!</mo> </math> 的因子个数 样例输入 复制 3 样例输出 复制 4 提示<math xmlns="http://www.w3.org/1998/Math/MathML"> <mn>1</mn> <mo><=</mo> <mi>n</mi> <mo><=</mo> <msup> <mn>10</mn> <mrow data-mjx-texclass="ORD"> <mn>5</mn> </mrow> <(731点数解答 | 2026-01-12 12:15:34)83
- [DeepSeek] 题目描述 通常,人们习惯将所有<math xmlns="http://www.w3.org/1998/Math/MathML"> <mi>n</mi> </math> 位二进制串按照字典序排列,例如所有 2 位二进制串按字典序从小到大排列为:00,01,10,11。 格雷码(Gray Code)是一种特殊的 <math xmlns="http://www.w3.org/1998/Math/MathML"> <mi>n</mi> </math> 位二进制串排列法,它要求相邻的两个二进制串间**恰好**有一位**不同**,特别地,第一个串与最后一个串也算作相邻。 所有 2 位二进制串按格雷码排列的一个例子为:00,01,11,10。 <math xmlns="http://www.w3.org/1998/Math/MathML"> <mi>n</mi> </math>位格雷码不止一种,下面给出其中一种格雷码的生成算法: 1. 1 位格雷码由两个 1 位二进制串组成,顺序为:0,1。 2.<math xmlns="http://www.w3.org/1998/Mat(726点数解答 | 2026-01-13 12:31:37)31
- [GPT] # [ROIR 2016 Day 1] 奖品 ## 题目背景 翻译自 [ROIR 2016 D1T1](https://neerc.ifmo.ru/school/archive/2015-2016/ru-olymp-regional-2016-day1.pdf)。 ## 题目描述 Petya 参加了一个比赛,在这个比赛中将会抽取 $n$ 个奖品。奖品编号从 $1$ 到 $n$。 根据比赛结果,参赛者可以获得 $2$ 到 $n$ 之间的分数。如果参赛者获得了 $k$ 分,那么他将从编号 $1$ 到 $k$ 的奖品中获得一个奖品。比赛主持人在参赛者选择奖品之前,会从奖品列表中删除一个奖品。然后,参赛者可以从剩下的 $k - 1$ 个奖品中选择一个。 Petya 知道所有奖品的价值,第 $i$ 个奖品的价值为 $a_i$。 对于每个 $2\le k\le n$,你需要求出如果 Petya 获得了 $k$ 分,他一定能得到的最大奖品价值是多少。 ## 输入格式 第一行输入一个整数 $n$($2 \le n \le 100000$)。 第二行输入 $n$ 个整数 $a_1,a(389点数解答 | 2025-01-10 11:15:31)285
- [字节豆包] // __multiversion__ // this signals the loading code to prepend either #version 100 or #version 300 es as apropriate. // to use centroid sampling we need to have version 300 es shaders, which requires changing: // attribute to in // varying to out when in vertex shaders or in when in fragment shaders // defining an out vec4 fragcolor and replacing uses of gl_fragcolor with fragcolor // texture2d to texture #if __version__ >= 300 // version 300 code #define varying in #define texture2d texture(45点数解答 | 2024-12-14 17:33:30)210
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