C语言搞定分段函数：输入x值精准计算y值的实用程序

```c #include <stdio.h> int main() { double x, y; printf("请输入自变量x的值: "); scanf("%lf", &x); if (x <= -2) { y = -6 * x + 5; } else if (x > -2 && x <= 8) { y = 0; } else { y = x / 6 - 9; } printf("函数值y为: %lf\n", y); return 0; } ``` ######[AI写代码神器 | 206点数解答 | 2024-10-28 19:10:24]