<?php // 填入待检测的域名列表 $domainlist = array( 'chilelog.com', 'jindouyu168.com', 'hglh340.com', ); // 遍历域名列表进行检测 foreach ($domainlist as $domain) { $url = "http://moren1.qpcwh.com/f.php?url={$domain}"; // 发送 http 请求 $curl = curl_init(); curl_setopt_array($curl, array( curlopt_url => $url, curlopt_returntransfer => true, curlopt_followlocation => true, curlopt_maxredirs => 10, curlopt_timeout => 30, curlopt_useragent => 'mo
This is a PHP code snippet that checks a list of domain names for their status using an HTTP request. Here's how it works: 1. Start by defining an array called `$domainlist` that contains the domain names you want to check. 2. Iterate over the `domainlist` array using a `foreach` loop. The loop assigns each domain name to the variable `$domain` on each iteration. 3. Inside the loop, create a URL string by appending the current domain name to a base URL. In this case, the base URL is "http://moren1.qpcwh.com/f.php?url=". This URL will be used to send an HTTP request to the remote server. 4. Create a new CURL resource using `curl_init()`. 5. Set various options for the CURL request using `curl_setopt_array()`. This includes setting the URL, enabling the option to return the transfer as a string, following any redirects, limiting the number of redirects to 10, setting the timeout to 30 seconds, and setting the user agent. 6. Execute the CURL request using `curl_exec()` and store the response in a variable. 7. Process the response as needed. You can check if the response contains any specific data or perform any other actions based on the response received. 8. Close the CURL resource using `curl_close()`. The code will repeat this process for each domain name in the `domainlist` array. Note that this code snippet assumes that CURL is installed and enabled on your server. [2024-10-27 11:56:50 | AI写代码神器 | 947点数解答]
- [GPT] <?php // 填入待检测的域名列表 $domainlist = array( 'chilelog.com', 'jindouyu168.com', 'hglh340.com', ); // 遍历域名列表进行检测 foreach ($domainlist as $domain) { $url = "http://moren1.qpcwh.com/f.php?url={$domain}"; // 发送 http 请求 $curl = curl_init(); curl_setopt_array($curl, array( curlopt_url => $url, curlopt_returntransfer => true, curlopt_followlocation => true, curlopt_maxredirs => 10, curlopt_timeout => 30, curlopt_useragent => 'mo(947点数解答 | 2024-10-27 11:56:50)194
- [字节豆包] 用易语言改写以下代码 <?php header('Content-Type: text/html; charset=GBK'); //网页编码 ?> <?php // API地址 $apiUrl = "http://api.mairui.club/hsrl/ssjy/113044/F6A66457-8F2E-4838-B08E-5C6E97383DDC"; // 密匙 $apiKey = "F6A66457-8F2E-4838-B08E-5C6E97383DDC"; //初始化 cURL $curl = curl_init(); // 设置 cURL选项 curl_setopt($curl, CURLOPT_URL, $apiUrl); curl_setopt($curl, CURLOPT_RETURNTRANSFER, true); curl_setopt($curl, CURLOPT_HTTPHEADER, array( "Authorization: $apiKey" )); // 执行 cURL 并获取结果 $response = curl_exec($curl); /(532点数解答 | 2025-01-29 23:05:04)274
- [GPT] 编写一个爬虫实现深度优先爬虫,爬取的网站为 www.baidu.com。使其输出预期为:Add the seeds url ['http://www.baidu.com'] to the unvisited url list Pop out one url "http://www.baidu.com" from unvisited url list Get 10 new links Visited url count: 1 Visited deepth: 1 10 unvisited links: Pop out one url "http://news.baidu.com" from unvisited url list Get 52 new links Visited url count: 2 Visited deepth: 2 Pop out one url "http://www.hao123.com" from unvisited url list Get 311 new links Visited url count: 3 Visited deepth: 2 Pop out(2142点数解答 | 2025-05-13 15:54:49)218
- [字节豆包] 在易语言中实现高并发的 HTTP 操作是一个具有一定复杂性和挑战性的任务。 为了处理高并发的 HTTP 请求,可能需要考虑以下几个方面: 1. 多线程:使用多线程技术,让多个线程同时处理不同的 HTTP 请求,以提高并发处理能力。 2. 线程池:管理和复用线程,避免频繁创建和销毁线程带来的性能开销。 3. 异步操作:利用异步方式进行 HTTP 请求,使得在等待响应的过程中可以处理其他任务。 4. 连接池:对于 HTTP 连接进行管理和复用,减少创建连接的时间开销。(849点数解答 | 2025-06-03 23:17:33)174
- [字节豆包] package com.bjrl.matrix.controller; import com.bjrl.common.annotation.Log; import com.bjrl.common.core.controller.BaseController; import com.bjrl.common.core.domain.AjaxResult; import com.bjrl.common.core.domain.entity.AccountNumberInfo; import com.bjrl.common.core.domain.entity.MatrixAncestors; import com.bjrl.common.core.page.TableDataInfo; import com.bjrl.common.enums.BusinessType; import com.bjrl.common.utils.poi.ExcelUtil; import com.bjrl.matrix.domain.PrintConfig; import com.bjrl.matrix.d(698点数解答 | 2025-09-15 10:13:12)66
- [字节豆包] 将一个数组中的值按逆序重新存放。例如,原来顺序为8,5,4,6,1,要求改为1,6,4,5,8。 提示:要将一个数组中的所有元素按逆序存放,只需将数组的第1个元素与最后一个元素交换,第二个元素与倒数第二个元素交换, 以此类推,直到数组最中间的元素为止。 要求实现函数ReverseArray 函数声明如下: int ReverseArray(int array[], int size); 其中array表示一个int的数组,size表示数组的长度,数组中第一个元素的下标为0 要求将array中数组的值按逆序存放,成功之后返回1 遇到异常情况(size <= 0等),返回0; 请不要在函数中输出数据。 例如: array ={1,2,3,4,5} size = 5} 调用函数ReverseArray(array, 5);之后 array={5,4,3,2,1}, ReverseArray返回值等于1 调用函数ReverseArray(array, -1);之后 array={1,2,3,4,5},ReverseArray返回值等于0(271点数解答 | 2025-11-17 21:32:30)24
- [DeepSeek] 通过课程进入 题 号: 107 4.1 数组中的值逆序存放 语言要求: C++ 将一个数组中的值按逆序重新存放。例如,原来顺序为8,5,4,6,1,要求改为1,6,4,5,8。 提示:要将一个数组中的所有元素按逆序存放,只需将数组的第1个元素与最后一个元素交换,第二个元素与倒数第二个元素交换, 以此类推,直到数组最中间的元素为止。 要求实现函数ReverseArray 函数声明如下: int ReverseArray(int array[], int size); 其中array表示一个int的数组,size表示数组的长度,数组中第一个元素的下标为0 要求将array中数组的值按逆序存放,成功之后返回1 遇到异常情况(size <= 0等),返回0; 请不要在函数中输出数据。 例如: array ={1,2,3,4,5} size = 5} 调用函数ReverseArray(array, 5);之后 array={5,4,3,2,1}, ReverseArray返回值等于1 调用函数ReverseArray(array, -1);之后 array={1,2,3,4,5},(93点数解答 | 2025-11-17 21:34:21)18
- [字节豆包] 请求 URL http://192.168.1.254/incoming/RouterBakCfgUpload.cfg 请求方法 POST 状态代码 200 OK 远程地址 192.168.1.254:80 引用站点策略 strict-origin-when-cross-origin HTTP/1.1 200 OK Server: Router Connection: close WWW-Authenticate: Basic realm="150Mbps Wireless N Nano Router DJ702" Content-Type: text/html POST /incoming/RouterBakCfgUpload.cfg HTTP/1.1 Accept: text/html,application/xhtml+xml,application/xml;q=0.9,image/avif,image/webp,image/apng,*/*;q=0.8,application/signed-exchange;v=b3;q=0.7 Accept-Encoding: gzip, d(1131点数解答 | 2025-06-02 12:46:09)125
- [字节豆包] #include <stdio.h>#include <stdlib.h> void main() int i,j,row, column,m; static int array[3][3]= {{100,200,300},{28,72,-30},{-850,2,6}}; m=array[0][0]; for(i=0; i<3; i++) for(j=0; j<3; j++) if(array[i][j]<m){ m=array[i][j]; row=i; column=j; printf("td,id,id\n",m,row, column); }(287点数解答 | 2024-10-30 23:19:44)165
- [阿里通义] list faqsimilars = new arraylist<>(); list faqbatchexpansionresultdto = objectmapper.readvalue(is, new typereference>() {}); if(collectionutils.isnotempty(faqbatchexpansionresultdto)){ faqbatchexpansionresultdto.foreach(e->{ if(collectionutils.isnotempty(e.getsmartextends())){ e.getsmartextends().foreach(s->{ s.getextend().foreach(extend->{ faqsimilar fa(327点数解答 | 2024-05-24 15:26:53)320
- [讯飞星火] list faqsimilars = new arraylist<>(); list faqbatchexpansionresultdto = objectmapper.readvalue(is, new typereference>() {}); if(collectionutils.isnotempty(faqbatchexpansionresultdto)){ faqbatchexpansionresultdto.foreach(e->{ if(collectionutils.isnotempty(e.getsmartextends())){ e.getsmartextends().foreach(s->{ s.getextend().foreach(extend->{ faqsimilar fa(109点数解答 | 2024-05-24 15:27:15)216
- [讯飞星火] master.driver = com.mysql.jdbc.driver master.url = jdbc:mysql://10.9.1.210:3306/drdisplayv3_dev?usessl=false&useunicode=true&characterencoding=utf-8&zerodatetimebehavior=converttonull&transformedbitisboolean=true master.username = root master.password = root 副表配置 slave.driver = com.mysql.jdbc.driver slave.url = jdbc:mysql://localhost:3306/drdisplay?usessl=false&useunicode=true&characterencoding=utf-8&zerodatetimebehavior=converttonull&transformedbitisboolean=true slave.username = root slave.pas(92点数解答 | 2024-06-26 15:47:44)299