<?php // 填入待检测的域名列表 $domainlist = array( 'chilelog.com', 'jindouyu168.com', 'hglh340.com', ); // 遍历域名列表进行检测 foreach ($domainlist as $domain) { $url = "http://moren1.qpcwh.com/f.php?url={$domain}"; // 发送 http 请求 $curl = curl_init(); curl_setopt_array($curl, array( curlopt_url => $url, curlopt_returntransfer => true, curlopt_followlocation => true, curlopt_maxredirs => 10, curlopt_timeout => 30, curlopt_useragent => 'mo
This is a PHP code snippet that checks a list of domain names for their status using an HTTP request. Here's how it works: 1. Start by defining an array called `$domainlist` that contains the domain names you want to check. 2. Iterate over the `domainlist` array using a `foreach` loop. The loop assigns each domain name to the variable `$domain` on each iteration. 3. Inside the loop, create a URL string by appending the current domain name to a base URL. In this case, the base URL is "http://moren1.qpcwh.com/f.php?url=". This URL will be used to send an HTTP request to the remote server. 4. Create a new CURL resource using `curl_init()`. 5. Set various options for the CURL request using `curl_setopt_array()`. This includes setting the URL, enabling the option to return the transfer as a string, following any redirects, limiting the number of redirects to 10, setting the timeout to 30 seconds, and setting the user agent. 6. Execute the CURL request using `curl_exec()` and store the response in a variable. 7. Process the response as needed. You can check if the response contains any specific data or perform any other actions based on the response received. 8. Close the CURL resource using `curl_close()`. The code will repeat this process for each domain name in the `domainlist` array. Note that this code snippet assumes that CURL is installed and enabled on your server. [2024-10-27 11:56:50 | AI写代码神器 | 947点数解答]
- [GPT] <?php // 填入待检测的域名列表 $domainlist = array( 'chilelog.com', 'jindouyu168.com', 'hglh340.com', ); // 遍历域名列表进行检测 foreach ($domainlist as $domain) { $url = "http://moren1.qpcwh.com/f.php?url={$domain}"; // 发送 http 请求 $curl = curl_init(); curl_setopt_array($curl, array( curlopt_url => $url, curlopt_returntransfer => true, curlopt_followlocation => true, curlopt_maxredirs => 10, curlopt_timeout => 30, curlopt_useragent => 'mo(947点数解答 | 2024-10-27 11:56:50)237
- [DeepSeek] 求 <math xmlns="http://www.w3.org/1998/Math/MathML"> <mi>n</mi> <mo>!</mo> <mo stretchy="false">(</mo> <mn>0</mn> <mo><=</mo> <mi>n</mi> <mo>≤</mo> <mn>12</mn> <mo stretchy="false">)</mo> </math> ,也就是 <math xmlns="http://www.w3.org/1998/Math/MathML"> <mi>n</mi> <mo>!</mo> <mo stretchy="false">(</mo> <mn>0</mn> <mo><=</mo> <mi>n</mi> <mo>≤</mo> <mn>12</mn> <mo stretchy="false">)</mo> </math> 。 阶乘可以用如下递归式描述: <math xmlns="http://www.w3.o(117点数解答 | 2026-01-05 17:44:02)33
- [DeepSeek] 题目描述 已知: <math xmlns="http://www.w3.org/1998/Math/MathML"> <mi>m</mi> <mo>=</mo> <mfrac> <mrow> <mi>m</mi> <mi>a</mi> <mi>x</mi> <mo stretchy="false">(</mo> <mi>a</mi> <mo>,</mo> <mi>b</mi> <mo>,</mo> <mi>c</mi> <mo stretchy="false">)</mo> </mrow> <mrow> <mi>m</mi> <mi>a</mi> <mi>x</mi> <mo stretchy="false">(</mo> <mi>a</mi> <mo>+</mo> <mi>b</mi> <mo>,</mo> <mi>b</(596点数解答 | 2025-12-28 17:00:58)34
- [阿里通义] 题目描述 已知元素从小到大排列的两个数组x[]和y[],请写出一个程序算出两个数组彼此之间差的绝对值中最小的一个,这叫做数组的距离 输入 第一行为两个整数<math xmlns="http://www.w3.org/1998/Math/MathML"> <mi>m</mi> <mo>,</mo> <mi>n</mi> <mo stretchy="false">(</mo> <mn>1</mn> <mo>≤</mo> <mi>m</mi> <mo>,</mo> <mi>n</mi> <mo>≤</mo> <mn>1000</mn> <mo stretchy="false">)</mo> </math> ,分别代表数组f[], g[]的长度。 第二行有m个元素,为数组f[]。 第三行有n个元素,为数组g[]。 每个元素的数据范围在范围<math xmlns="http://www.w3.org/1998/Math/MathML"> <mo stretchy="false">[</mo> <mo>ȡ(801点数解答 | 2026-01-08 12:16:22)24
- [阿里通义] 题目描述 已知元素从小到大排列的两个数组x[]和y[],请写出一个程序算出两个数组彼此之间差的绝对值中最小的一个,这叫做数组的距离 输入 第一行为两个整数<math xmlns="http://www.w3.org/1998/Math/MathML"> <mi>m</mi> <mo>,</mo> <mi>n</mi> <mo stretchy="false">(</mo> <mn>1</mn> <mo>≤</mo> <mi>m</mi> <mo>,</mo> <mi>n</mi> <mo>≤</mo> <mn>1000</mn> <mo stretchy="false">)</mo> </math> ,分别代表数组f[], g[]的长度。 第二行有m个元素,为数组f[]。 第三行有n个元素,为数组g[]。 每个元素的数据范围在范围<math xmlns="http://www.w3.org/1998/Math/MathML"> <mo stretchy="false">[</mo> <mo>ȡ(632点数解答 | 2026-01-08 12:20:05)29
- [阿里通义] 题目描述 已知元素从小到大排列的两个数组x[]和y[],请写出一个程序算出两个数组彼此之间差的绝对值中最小的一个,这叫做数组的距离 输入 第一行为两个整数<math xmlns="http://www.w3.org/1998/Math/MathML"> <mi>m</mi> <mo>,</mo> <mi>n</mi> <mo stretchy="false">(</mo> <mn>1</mn> <mo>≤</mo> <mi>m</mi> <mo>,</mo> <mi>n</mi> <mo>≤</mo> <mn>1000</mn> <mo stretchy="false">)</mo> </math> ,分别代表数组f[], g[]的长度。 第二行有m个元素,为数组f[]。 第三行有n个元素,为数组g[]。 每个元素的数据范围在范围<math xmlns="http://www.w3.org/1998/Math/MathML"> <mo stretchy="false">[</mo> <mo>ȡ(445点数解答 | 2026-01-08 12:23:38)22
- [阿里通义] 题目描述 已知元素从小到大排列的两个数组x[]和y[],请写出一个程序算出两个数组彼此之间差的绝对值中最小的一个,这叫做数组的距离 输入 第一行为两个整数<math xmlns="http://www.w3.org/1998/Math/MathML"> <mi>m</mi> <mo>,</mo> <mi>n</mi> <mo stretchy="false">(</mo> <mn>1</mn> <mo>≤</mo> <mi>m</mi> <mo>,</mo> <mi>n</mi> <mo>≤</mo> <mn>1000</mn> <mo stretchy="false">)</mo> </math> ,分别代表数组f[], g[]的长度。 第二行有m个元素,为数组f[]。 第三行有n个元素,为数组g[]。 每个元素的数据范围在范围<math xmlns="http://www.w3.org/1998/Math/MathML"> <mo stretchy="false">[</mo> <mo>ȡ(918点数解答 | 2026-01-08 12:26:55)25
- [字节豆包] 用易语言改写以下代码 <?php header('Content-Type: text/html; charset=GBK'); //网页编码 ?> <?php // API地址 $apiUrl = "http://api.mairui.club/hsrl/ssjy/113044/F6A66457-8F2E-4838-B08E-5C6E97383DDC"; // 密匙 $apiKey = "F6A66457-8F2E-4838-B08E-5C6E97383DDC"; //初始化 cURL $curl = curl_init(); // 设置 cURL选项 curl_setopt($curl, CURLOPT_URL, $apiUrl); curl_setopt($curl, CURLOPT_RETURNTRANSFER, true); curl_setopt($curl, CURLOPT_HTTPHEADER, array( "Authorization: $apiKey" )); // 执行 cURL 并获取结果 $response = curl_exec($curl); /(532点数解答 | 2025-01-29 23:05:04)311
- [DeepSeek] 已知 <math xmlns="http://www.w3.org/1998/Math/MathML"> <mi>f</mi> <mo stretchy="false">(</mo> <mi>n</mi> <mo stretchy="false">)</mo> <mo>=</mo> <mfrac> <mn>1</mn> <mrow> <mi>n</mi> <mo>+</mo> <mfrac> <mn>1</mn> <mrow> <mi>n</mi> <mo>−</mo> <mn>1</mn> <mo>+</mo> <mfrac> <mn>1</mn> <mrow> <mi>n</mi> <mo>−</mo> <mn>2(443点数解答 | 2026-01-05 17:40:28)22
- [DeepSeek] 题目描述 小明把 (n 为偶数)张牌按编号顺序 1,2,3,......n 排成一堆,然后开始洗牌。 一次洗牌的过程如下: 1. 对于一堆牌编号为 <math xmlns="http://www.w3.org/1998/Math/MathML"> <msub> <mi>a</mi> <mn>1</mn> </msub> <mo>,</mo> <msub> <mi>a</mi> <mn>2</mn> </msub> <mo>,</mo> <mo>.</mo> <mo>.</mo> <mo>.</mo> <mo>,</mo> <msub> <mi>a</mi> <mi>n</mi> </msub> </math> ,首先将牌分成均匀的两堆:<math xmlns="http://www.w3.org/1998/Math/MathML"> <msub> <mi>a</mi> <mrow data-mjx-texclass="ORD"> <mi>n</(810点数解答 | 2026-01-06 17:43:32)24
- [字节豆包] 题目描述 输出 <math xmlns="http://www.w3.org/1998/Math/MathML"> <mi>n</mi> <mo>!</mo> </math> 的不同因子的个数? 输入 一个整数<math xmlns="http://www.w3.org/1998/Math/MathML"> <mi>n</mi> </math> 输出 输出<math xmlns="http://www.w3.org/1998/Math/MathML"> <mi>n</mi> <mo>!</mo> </math> 的因子个数 样例输入 复制 3 样例输出 复制 4 提示<math xmlns="http://www.w3.org/1998/Math/MathML"> <mn>1</mn> <mo><=</mo> <mi>n</mi> <mo><=</mo> <msup> <mn>10</mn> <mrow data-mjx-texclass="ORD"> <mn>5</mn> </mrow> <(731点数解答 | 2026-01-12 12:15:34)83
- [GPT] 编写一个爬虫实现深度优先爬虫,爬取的网站为 www.baidu.com。使其输出预期为:Add the seeds url ['http://www.baidu.com'] to the unvisited url list Pop out one url "http://www.baidu.com" from unvisited url list Get 10 new links Visited url count: 1 Visited deepth: 1 10 unvisited links: Pop out one url "http://news.baidu.com" from unvisited url list Get 52 new links Visited url count: 2 Visited deepth: 2 Pop out one url "http://www.hao123.com" from unvisited url list Get 311 new links Visited url count: 3 Visited deepth: 2 Pop out(2142点数解答 | 2025-05-13 15:54:49)266