C语言：计算 e 近似值，精确到最后一项小于 10⁻⁵ 并统计项数

```c #include <stdio.h> int main() { int n = 1; double e = 1.0, item = 1.0; while (item >= 1e-5) { int factorial = 1; for (int i = 1; i <= n; i++) { factorial *= i; } item = 1.0 / factorial; e += item; n++; } printf("%f,%d\n", e, n-1); return 0; } ``` ######[AI写代码神器 | 229点数解答 | 2024-10-16 14:42:13]