C语言：计算 e 近似值，精确到最后一项绝对值小于 10⁻⁵ 并统计项数

```c #include <stdio.h> double factorial(int n) { double result = 1; for (int i = 1; i <= n; i++) { result *= i; } return result; } int main() { double e = 1; double term; int n = 1; int count = 1; do { term = 1.0 / factorial(n); e += term; n++; count++; } while (term >= 0.00001); printf("%f,%d\n", e, count); return 0; } ``` ######[AI写代码神器 | 161点数解答 | 2024-10-16 14:38:11]