FPGA实现：6位数码管显示时间、LCD屏显温度，可设闹钟且蜂鸣器提醒1分钟的主程序揭秘

下面是一个基于FPGA的电子闹钟设计的主程序的示例： ```vhdl library IEEE; use IEEE.STD_LOGIC_1164.ALL; use IEEE.NUMERIC_STD.ALL; entity AlarmClock is Port ( clk : in STD_LOGIC; reset : in STD_LOGIC; sw : in STD_LOGIC_VECTOR(3 downto 0); btn : in STD_LOGIC_VECTOR(1 downto 0); seg : out STD_LOGIC_VECTOR(6 downto 0); led : out STD_LOGIC_VECTOR(3 downto 0); buzzer : out STD_LOGIC; lcd : out STD_LOGIC_VECTOR(15 downto 0)); end AlarmClock; architecture Behavioral of AlarmClock is signal counter : integer range 0 to 59999; signal buzzer_on : STD_LOGIC; signal alarmTime : STD_LOGIC_VECTOR(5 downto 0); signal currentTime: STD_LOGIC_VECTOR(5 downto 0); signal temperature: STD_LOGIC_VECTOR(15 downto 0); component BCDto7Segment Port ( bcd : in STD_LOGIC_VECTOR(6 downto 0); seg : out STD_LOGIC_VECTOR(6 downto 0)); end component; component TemperatureSensor Port ( clk : in STD_LOGIC; temperature: out STD_LOGIC_VECTOR(15 downto 0)); end component; begin BCDto7 : BCDto7Segment Port map (bcd => currentTime, seg => seg); Temperature : TemperatureSensor Port map (clk => clk, temperature => temperature); process (clk, reset) begin if reset = '1' then counter <= 0; currentTime <= "000000"; buzzer_on <= '0'; alarmTime <= "000000"; elsif rising_edge(clk) then if counter = 59999 then counter <= 0; else counter <= counter + 1; end if; if counter = 59999 then currentTime <= std_logic_vector(unsigned(currentTime) + 1); end if; end if; end process; process (clk, sw, btn, currentTime, alarmTime) begin if rising_edge(clk) then if btn(1) = '1' then buzzer_on <= '0'; buzzer <= '0'; alarmTime <= sw(3 downto 0) & sw(3 downto 0); if currentTime = alarmTime then buzzer_on <= '1'; end if; else buzzer <= buzzer_on; end if; end if; end process; lcd <= temperature; end Behavioral; ``` ######[AI写代码神器 | 1620点数解答 | 2024-06-16 10:09:27]