c语言中用于结构化程序设计的3种基本结构是（ ） a. 顺序结构、选择结构、循环结构 b. if、switch、break c. for、while、do-while d. if、for、continue
a. 顺序结构、选择结构、循环结构 [2024-05-28 19:45:05 | AI写代码神器 | 21点数解答]
相关提问
- [GPT] c语言中用于结构化程序设计的3种基本结构是（ ） a. 顺序结构、选择结构、循环结构 b. if、switch、break c. for、while、do-while d. if、for、continue（21点数解答 | 2024-05-28 19:45:05）187
- [GPT] // 主函数功能菜单 void menu() { printf("二叉树操作菜单：\n"); printf("1. 按顺序法创建二叉树的链式存储结构\n"); printf("2. 前序遍历二叉树\n"); printf("3. 中序遍历二叉树\n"); printf("4. 后序遍历二叉树\n"); printf("5. 退出\n"); } int main() { treenode *root = null; int choice; do { menu(); printf("请输入你的选择："); scanf("%d", &choice); switch (choice) { case 1: root = createtreebysequence(); break; case 2: printf("前序遍历结果："); preordertraversal(root); printf("\n"); break; case 3: printf("中序遍历结果："); inordertraversal(root); printf("\n"); break; case 4: prin（132点数解答 | 2024-11-13 09:28:34）227
- [字节豆包] 给以下代码进行注释： for i=0 to selection.count do ( if i!=0 then ( if superclassof selection[i]==geometryclass do ( tomesh = snapshotasmesh selection[i]; if tomesh.numverts!=0 then ( sz=calculatevolumeandcenterofmass selection[i]; for j=1 to cdsz.count do ( xlc = xlx.application.cells (i+1) j; cdsy=finditem quansz cdsz[j];--菜单索引 xlc.value=sz[cdsy]; ) ) ) ) else( for j=1 to cdsz.count do ( xlc = xlx.application（386点数解答 | 2024-10-16 19:29:32）254
- [百度文心] 给以下代码进行注释： for i=0 to selection.count do ( if i!=0 then ( if superclassof selection[i]==geometryclass do ( tomesh = snapshotasmesh selection[i]; if tomesh.numverts!=0 then ( sz=calculatevolumeandcenterofmass selection[i]; for j=1 to cdsz.count do ( xlc = xlx.application.cells (i+1) j; cdsy=finditem quansz cdsz[j];--菜单索引 xlc.value=sz[cdsy]; ) ) ) ) else( for j=1 to cdsz.count do ( xlc = xlx.application（698点数解答 | 2024-10-16 19:33:34）285
- [DeepSeek] rollout arcFilletRollout "弧形编辑器" width:300 height:150 ( local obj local activeSegment = 0 spinner spn_radius "弧线高度: " type:#float range:[-10000,10000,10] scale:0.1 button btn_apply "应用修改" width:100 height:30 on spn_radius changed val do ( if activeSegment == 0 do return undo "Adjust Arc" on ( try ( -- 增强对象验证 if not (isValidNode obj) do throw "对象无效或已被删除" if classOf obj != Editable_Spline do t（656点数解答 | 2025-02-24 21:43:38）192
- [字节豆包] <script> let currentStage = 1; let btnSequence = []; function check(stage) { let correct = false; switch(stage) { case 1: correct = [...document.getElementById('input1').value].reverse().join('') === '3168'; break; case 3: correct = document.getElementById('input3').value === '②'; break; case 4: correct = document.getElementById('input4').value === "不存在的时间"; break; case 5: （207点数解答 | 2025-03-05 11:16:49）197
- [字节豆包] #include<stdio.h> int copystring(int str1[], int str2[], int n); int main() { int str1[100],str2[100]; int i=0,num,n=0; // 使用 getchar() 来读取字符，检查是否是换行符 while (i < 100) { if (scanf_s("%d", &num) != 1) { while (getchar() != '\n'); break; } str1[i] = num; i++; if (getchar() == '\n') { n = i; break; } } int m = copystring(str1, str2, n); for(i=0;i<m;i++) printf("%d", str2[i]); return 0; } int copystring(int str1[], int str2[], int n) { int j,i; int count = 0; f（392点数解答 | 2024-12-08 15:18:09）243
- [百度文心] #include<easyx.h> #include <stdio.h> #include <graphics.h> int main() { initgraph(800, 600); setbkcolor(WHITE); cleardevice(); ExMessage msg; while (1) { msg = getmessage(EX_MOUSE); switch (msg.message) { case WM_MOUSEMOVE://鼠标移动，半径2黑色圆点 setfillcolor(BLACK); solidcircle(msg.x, msg.y, 2); break; case WM_LBUTTONDOWN://鼠标左键，半径10红色圆点 setfillcolor(RED); solidcircle(msg.x, msg.y, 10); //if (GetKeyState(VK_CONTROL) < 0) { //solidrectangle(msg.x, msg.y, 20); //}（770点数解答 | 2025-04-22 21:45:53）166
- [DeepSeek] #include<stdio.h> void get_char(); int position(char ch); int main() { get_char(); return 0; } void get_char() { char ch; printf("请输入字符:"); while((ch=getchar())!=EOF) { if((ch=getchar())=='\n') { continue; } if((ch=getchar())!=-1) { printf("%c在字母表中的位置是%d\n",ch,position(ch)); } else printf("%c不是字母表中的",ch); } } int position(char ch) { if(ch>='A'&&ch<='Z') return ch-'A'+1; if(ch>='a'&&ch<='z') return ch-'a'+1; else return -1; } 查错 （519点数解答 | 2025-02-07 12:41:36）213
- [百度文心] 以下代码的运行结果是()。 for numberin range(5): if number ==2: continue 答题卡819 if number ==3: break print(number)（277点数解答 | 2024-05-13 22:03:56）222
- [DeepSeek] #include <iostream> using namespace std; int main() { int x,y,a,b; cin>>x>>y>>a>>b; for(int i=x;i<=y;) { if(i==a) { continue; } cout<<i; if(i>=b) { break; } cout<<" "; } return 0; }（256点数解答 | 2025-07-31 22:46:12）69
- [字节豆包] 写出enter your name. alice hello alice, do you want to repeat this program? yes enter your name. bob hello bob, do you want to repeat this program? yes enter your name. charlie hello charlie, do you want to repeat this program? no goodbye, charlie! 的c++代码（267点数解答 | 2024-10-22 08:36:28）223