编写一个java应用程序,该程序中有两个类,vehicle(机动车类)和user,具体实现如下功能:(各类属性值和功能体 vehicle 类有一个 double 类型的变量 speed, 用于刻画机动车的速度,一个int 型变量 power,用于刻画机动车的功率。方法定义了 speedup(int s)方法,体现机动车有减速功能。定义了 speeddown)方法,体現机动车有减速功能。方法定义了 setpower(int p)方法,用于设置机动车的功率。定义了 getpower)方法,用于获取机动车的功率 ·在主类user 的 main)方法中用 vehicle 类创建对象 该对象调用方法设置功率,演示加速和减递功能


可以使用以下代码来实现上述功能: ```java class Vehicle { private double speed; private int power; public Vehicle(){ this.speed = 0; this.power = 0; } public void speedUp(int s) { this.speed += s; System.out.println("加速" + s + ",当前速度为" + this.speed); } public void speedDown(int s) { this.speed -= s; System.out.println("减速" + s + ",当前速度为" + this.speed); } public void setPower(int p) { this.power = p; } public int getPower() { return this.power; } } public class User { public static void main(String[] args) { Vehicle vehicle = new Vehicle(); vehicle.setPower(100); vehicle.speedUp(20); vehicle.speedDown(10); System.out.println("当前功率为" + vehicle.getPower()); } } ``` 在主类`User`中,我们创建了一个`Vehicle`对象`vehicle`,并调用其方法进行演示。首先使用`setPower`方法设置功率为100,然后调用`speedUp`方法加速20,最后调用`speedDown`方法减速10。同时使用`getPower`方法获取当前功率并打印输出。 [2024-03-12 11:26:25 | AI写代码神器 | 968点数解答]
- 编写一个java应用程序,该程序中有两个类,vehicle(机动车类)和user,具体实现如下功能:(各类属性值和功能体 vehicle 类有一个 double 类型的变量 speed, 用于刻画机动车的速度,一个int 型变量 power,用于刻画机动车的功率。方法定义了 speedup(int s)方法,体现机动车有减速功能。定义了 speeddown)方法,体現机动车有减速功能。方法定义了 setpower(int p)方法,用于设置机动车的功率。定义了 getpower)方法,用于获取机动车的功率 ·在主类user 的 main)方法中用 vehicle 类创建对象 该对象调用方法设置功率,演示加速和减递功能(968点数解答 | 2024-03-12 11:26:25)450
- #include<iostream> using namespace std; class shizheng { private: int speed; static int shitime; public: shizheng() { speed = 0; shitime = 0; } shizheng(int newspeed, int newshitime) { speed = newspeed; shitime = newshitime; } void shizhengmove() { cout << "shizheng moved" << endl; } void setshizheng() { speed = 0; shitime = 0; } int showshitime() { return shitime+speed; } }; class fenzheng { private: int speed; int fentime; public: fenzheng() { speed = 0; fentime = 0; } fenzheng(int(493点数解答 | 2024-11-11 23:52:44)133
- dim caizhi1 as string dim caizhi2 as string dim caizhi as string dim dianzulv1 as double dim dianzulv2 as double dim midu1 as double dim midu2 as double dim zhijing as double dim jiejubi as double dim jiemianji as double dim zhouchang as double dim dianzusichangdu as double dim zhongliang as double dim quanshu as double dim jieju as double dim dianzulv as double dim midu as double dim zuzhi as double private sub command1_click() dim xlapp as object dim xlworkbook as object dim xlworkshee(32点数解答 | 2024-10-31 15:19:51)206
- // rod6.cpp : defines the entry point for the console application. // #include "stdafx.h" // consoleapplication2.cpp : 此文件包含 "main" 函数。程序执行将在此处开始并结束。 // #include <stdio.h> #include <math.h> #include <iostream> #include <conio.h> #include <cstdlib> using namespace std; double ro[10001]; double th[10001]; double e[10001]; double a[10001]; double b[10001]; double y[10001]; double x[10001]; double d[10001]; double d[10001]; double da[10001]; double db[10001]; double dc[10001]; double z[10001]; d(55点数解答 | 2024-08-16 15:22:27)217
- #include <iostream> #include<cstring> using namespace std; class vehicle{ public: void run(); string getname(); vehicle(string name); string name; }; vehicle::vehicle(string name){ this->name = name; } void vehicle::run(){ cout<<"出发"<<endl; } string vehicle::getname(){ return name; } class car:public vehicle{ public: void break(); void display(); car(int seats,string color,string type,int power,string name); en(65点数解答 | 2024-05-26 17:01:16)266
- #include <iostream> #include<cstring> using namespace std; class vehicle{ public: void run(); string getname(); vehicle(string name); string name; }; vehicle::vehicle(string name){ this->name = name; } void vehicle::run(){ cout<<"出发"<<endl; } string vehicle::getname(){ return name; } class car:public vehicle{ public: void break(); void display(); car(int seats,string color,string type,int power,string name); en(373点数解答 | 2024-05-26 17:02:18)256
- #define _crt_secure_no_warnings #include <iostream> #include <cstdlib> #include <cmath> #include <vector> #include <cstdio> using namespace std; // 你的代码... const int nx = 784, nb = 500, ny = 10;//输入层x,隐藏层b,输出层y节点数 const double eta = 0.1;//学习率 struct node { double val{}; double bias{}; vector<double> weight; } x[nx], b[nb], y[ny];//输入层x,隐藏层b,输出层y double g[ny], e[nb];//用于反向传播 double trainx[nx], trainy[ny];//训练数据 double sigmoid(double x) { return 1.0 / (1.0 + exp(-x)); } double(34点数解答 | 2024-09-06 08:43:52)269
- #define _crt_secure_no_warnings #include <iostream> #include <cstdlib> #include <cmath> #include <vector> #include <cstdio> using namespace std; // 你的代码... const int nx = 784, nb = 500, ny = 10;//输入层x,隐藏层b,输出层y节点数 const double eta = 0.1;//学习率 struct node { double val{}; double bias{}; vector<double> weight; } x[nx], b[nb], y[ny];//输入层x,隐藏层b,输出层y double g[ny], e[nb];//用于反向传播 double trainx[nx], trainy[ny];//训练数据 double sigmoid(double x) { return 1.0 / (1.0 + exp(-x)); } double(1309点数解答 | 2024-09-06 08:46:09)281
- #include <stdio.h> #include <math.h> #define pi 3.14159265358979323846 double meridianarclength(double b) { double a = 6378140.0; double e2 = 0.00669438002290; double m = a * (1 - e2) * (1 - e2 * sin(b) * sin(b)) * pow(1 - e2 * sin(b) * sin(b), 1.5); double n = a / sqrt(1 - e2 * sin(b) * sin(b)); return m + n * sin(b) * cos(b) * pow(tan(b),2) /2 + n * sin(b) * pow(cos(b), 3) * (5 - pow(tan(b), 2) + 9 * e2 * pow(cos(b), 2)) * pow(tan(b), 4) / 24; } double calculatebaselatitude(double x, double y)(565点数解答 | 2024-11-21 13:08:38)169
- #include <stdio.h> #include <math.h> #define pi 3.14159265358979323846 double meridianarclength(double b) { double a = 6378140.0; double e2 = 0.00669438002290; double m = a * (1 - e2) * (1 - e2 * sin(b) * sin(b)) * pow(1 - e2 * sin(b) * sin(b), 1.5); double n = a / sqrt(1 - e2 * sin(b) * sin(b)); return m + n * sin(b) * cos(b) * pow(tan(b),2) /2 + n * sin(b) * pow(cos(b), 3) * (5 - pow(tan(b), 2) + 9 * e2 * pow(cos(b), 2)) * pow(tan(b), 4) / 24; } double calculatebaselatitude(double x,(48点数解答 | 2024-11-21 13:05:21)167
- #include<stdio.h> int main() { double r, h; //定义变量r(半径)和h(高度) const double pi = 3.1415926; //定义常量pi // 输入半径r和高度h printf("请输入圆的半径 r 和圆柱的高 h (例如: 5 10): "); scanf("%lf %lf", &r, &h); // 计算各项值 double circumference = 2 * pi * r; //圆的周长 double circle_area = pi * r * r; // 圆的面积 double sphere_surface_area = 4 * pi * r * r; // 圆球的表面积 double sphere_volume = (4.0 / 3) * pi * r * r * r; //圆球的体积 double cylinder_volume = circle_area * h; // 圆柱的体积 // 输出结果,保留两位小数 printf("圆的周长: %.2f\n", circumference); prin(668点数解答 | 2024-10-19 10:58:06)197
- #include <stdio.h> int main() { double r, h; // 定义变量r(半径)和h(高度) const double pi =3.1415926; //定义常量pi // 输入半径r和高度h printf("请输入圆的半径 r 和圆柱的高 h (例如: 5 10): "); scanf("%lf %lf", &r, &h); // 计算各项值 double circumference = 2 * pi * r; // 圆的周长 double circle_area = pi * r * r; // 圆的面积 double sphere_surface_area =4 * pi * r * r; // 圆球的表面积 double sphere_volume = (4.0 / 3) * pi * r * r * r; //圆球的体积 double cylinder_volume = circle_area * h; // 圆柱的体积 // 输出结果,保留两位小数 printf("圆的周长: %.2f\n", circumference); pri(542点数解答 | 2024-10-19 11:00:12)174