- com.mongodb.mongobulkwriteexception: bulk write operation error on server 172.17.134.159:3717. write errors: [bulkwriteerror{index=0, code=11000, message='e11000 duplicate key error collection: imlaw_analyst.qtf_test_question index: _id_ dup key: { : objectid('65d41c36f57700003b004d21') }', details={ }}]. 2024-02-20 11:43:55 [analysisstatistics.analysisstatisticslog-53] at com.mongodb.connection.bulkwritebatchcombiner.geterror(bulkwritebatchcombiner.java:176)


The error message you're encountering is from MongoDB and indicates a "Duplicate Key Error." Specifically, it's related to the `_id` field in the `imlaw_analyst.qtf_test_question` collection. In MongoDB, each document within a collection must have a unique `_id` field by default. The error code `11000` corresponds to "E11000 duplicate key error" which means that while attempting a bulk write operation (insertion or update), there was an attempt to insert a document with an `_id` value (`ObjectId('65d41c36f57700003b004d21')`) that already exists in the specified collection. To resolve this issue: 1. If you're inserting: Make sure your data source doesn't contain duplicates for `_id`. If the `_id` is auto-generated (like ObjectId), ensure that new documents are being correctly created with unique IDs. 2. If you're updating: Check your update query to ensure it isn't accidentally trying to insert a new document with the same `_id`. 3. Check Indexes: Verify that the unique index on `_id` is as intended and not conflicting with your operations. 4. Handle Duplicates: In situations where duplicates may occur, catch this exception in your application logic and handle it accordingly – perhaps by ignoring, updating existing records, or generating a new unique ID before re-attempting the insertion. Here's a snippet of how you might handle this in Java: ```java try { // Your bulk write operation here } catch (MongoBulkWriteException e) { if (e.getWriteErrors().get(0).getCode() == 11000) { // Handle duplicate _id situation } else { throw e; } } ``` Remember that managing uniqueness of `_id` is critical to maintain data integrity in MongoDB collections. [2024-02-20 11:59:10 | AI写代码神器 | 405点数解答]
- mongodb - com.mongodb.mongobulkwriteexception: bulk write operation error on server 172.17.134.159:3717. write errors: [bulkwriteerror{index=0, code=11000, message='e11000 duplicate key error collection: imlaw_analyst.qtf_test_question index: _id_ dup key: { : objectid('65d41c36f57700003b004d21') }', details={ }}]. 2024-02-20 11:43:55 [analysisstatistics.analysisstatisticslog-53] at com.mongodb.connection.bulkwritebatchcombiner.geterror(bulkwritebatchcombiner.java:176)(397点数解答 | 2024-02-20 11:59:14)266
- datax mongodb - com.mongodb.mongobulkwriteexception: bulk write operation error on server 172.17.134.159:3717. write errors: [bulkwriteerror{index=0, code=11000, message='e11000 duplicate key error collection: imlaw_analyst.qtf_test_question index: _id_ dup key: { : objectid('65d41c36f57700003b004d21') }', details={ }}]. 2024-02-20 11:43:55 [analysisstatistics.analysisstatisticslog-53] at com.mongodb.connection.bulkwritebatchcombiner.geterror(bulkwritebatchcombiner.java:176)(134点数解答 | 2024-02-20 11:59:27)287
- - com.mongodb.mongobulkwriteexception: bulk write operation error on server 172.17.134.159:3717. write errors: [bulkwriteerror{index=0, code=11000, message='e11000 duplicate key error collection: imlaw_analyst.qtf_test_question index: _id_ dup key: { : objectid('65d41c36f57700003b004d21') }', details={ }}]. 2024-02-20 11:43:55 [analysisstatistics.analysisstatisticslog-53] at com.mongodb.connection.bulkwritebatchcombiner.geterror(bulkwritebatchcombiner.java:176)(405点数解答 | 2024-02-20 11:59:10)240
- 实现哈希表创建及查找算法,哈希函数使用除余法,用线性探测法处理冲突。 函数接口定义: void createhash(hashtable ht[],int n); //输入不大于m的n个不为0(0表示空值)的数,用线性探查法解决冲突构造散列表 int searchhash(hashtable ht[],int key); //输入一个值key,在散列表中查找key位置 其中 ht 表示哈希表, n表示记录数,key要查找的关键字 裁判测试程序样例: #include<iostream> using namespace std; #define m 16 #define nullkey 0 //单元为空的标记 struct hashtable{ int key; }; void createhash(hashtable ht[],int n); int searchhash(hashtable ht[],int key); int main() { int value,key; int result; int i,j,n; hashtable ht[m]; for(i=0;i<m;i++) ht[i].key=0; cin >> n; if(n>m) return 0; createhash(ht,n); cin >> key; result=searchhash(ht,key); if(result!=-1) cout << "search success,the key is located in "<< result+1; else cout << "search failed"; return 0; } /* 请在这里填写答案 */ 输入样例: 12 19 14 23 1 68 20 84 27 55 11 10 79 55 输出样例: 输出拓扑序列。 search success,the key is located in 6(504点数解答 | 2024-12-21 16:14:58)177
- 实现哈希表创建及查找算法,哈希函数使用除余法,用线性探测法处理冲突。 函数接口定义: void createhash(hashtable ht[],int n); //输入不大于m的n个不为0(0表示空值)的数,用线性探查法解决冲突构造散列表 int searchhash(hashtable ht[],int key); //输入一个值key,在散列表中查找key位置 其中 ht 表示哈希表, n表示记录数,key要查找的关键字 裁判测试程序样例: #include<iostream> using namespace std; #define m 16 #define nullkey 0 //单元为空的标记 struct hashtable{ int key; }; void createhash(hashtable ht[],int n); int searchhash(hashtable ht[],int key); int main() { int value,key; int result; int i,j,n; hashtable ht[m]; for(i=0;i<m;i++) ht[i].key=0; cin >> n; if(n>m) return 0; createhash(ht,n); cin >> key; result=searchhash(ht,key); if(result!=-1) cout << "search success,the key is located in "<< result+1; else cout << "search failed"; return 0; } /* 请在这里填写答案 */ 输入样例: 12 19 14 23 1 68 20 84 27 55 11 10 79 55 输出样例: 输出拓扑序列。 search success,the key is located in 6(328点数解答 | 2024-12-21 16:15:59)236
- 实现哈希表创建及查找算法,哈希函数使用除余法,用线性探测法处理冲突。 函数接口定义: void createhash(hashtable ht[],int n); //输入不大于m的n个不为0(0表示空值)的数,用线性探查法解决冲突构造散列表 int searchhash(hashtable ht[],int key); //输入一个值key,在散列表中查找key位置 其中 ht 表示哈希表, n表示记录数,key要查找的关键字 裁判测试程序样例: #include<iostream> using namespace std; #define m 16 #define nullkey 0 //单元为空的标记 struct hashtable{ int key; }; void createhash(hashtable ht[],int n); int searchhash(hashtable ht[],int key); int main() { int value,key; int result; int i,j,n; hashtable ht[m]; for(i=0;i<m;i++) ht[i].key=0; cin >> n; if(n>m) return 0; createhash(ht,n); cin >> key; result=searchhash(ht,key); if(result!=-1) cout << "search success,the key is located in "<< result+1; else cout << "search failed"; return 0; } /* 请在这里填写答案 */ 输入样例: 12 19 14 23 1 68 20 84 27 55 11 10 79 55 输出样例: 输出拓扑序列。 search success,the key is located in 6(282点数解答 | 2024-12-21 16:16:03)209
- 题目描述 输入四个整数 x , y , a , b x,y,a,b,请你按照要求输出 x ∼ y x∼y 之间的所有数。 要求: 不要输出数字 a a。 不要输出大于等于数字 b b 的数。 输入格式 输入包括一行,包含四个整数 x , y , a , b x,y,a,b,数字之间用空格隔开。 输出格式 输出包括一行,为 x ∼ y x∼y 之间符合要求的数字。 input1 复制 10 20 13 17 output1 复制 10 11 12 14 15 16 input2 复制 50 55 52 100 output2 复制 50 51 53 54 55 样例解释 对于样例 1 1: 样例要求输出 10 ∼ 20 10∼20 之间不是 13 13, 且小于 17 17 的数,故有 10 , 11 , 12 , 14 , 15 , 16 10,11,12,14,15,16。 数据规模与约定 对于 100 % 100% 的数据, 1 ≤ x ≤ y ≤ 100 1≤x≤y≤100, x ≤ a ≤ y x≤a≤y, x ≤ b x≤b。 C++程序(138点数解答 | 2025-07-19 20:44:46)174
- ```python # 置换表等相关常量 ip = [58, 50, 42, 34, 26, 18, 10, 2, 60, 52, 44, 36, 28, 20, 12, 4, 62, 54, 46, 38, 30, 22, 14, 6, 64, 56, 48, 40, 32, 24, 16, 8, 57, 49, 41, 33, 25, 17, 9, 1, 59, 51, 43, 35, 27, 19, 11, 3, 61, 53, 45, 37, 29, 21, 13, 5, 63, 55, 47, 39, 31, 23, 15, 7] # 其他置换表和函数定义 def des_encrypt(plaintext, key): # 加密流程实现 #... def des_decrypt(ciphertext, key): # 解密流程实现 #... # 测试代码 plaintext = 0x0*********abcdef key = 0x1f1f1f1f0e0e0e0e ciphertext = des_encrypt(plaintext, key) decrypted(1523点数解答 | 2024-10-30 12:18:51)201
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- [volcengine_maas] Error: PluginInvokeError: {"args":{},"error_type":"ArkBadRequestError","message":"Error code: 400 - {'error': {'code': 'InvalidParameter.UnsupportedImageFormat', 'message': 'The request failed because the image format is not supported by the API(459点数解答 | 2025-06-11 13:08:03)202