C++判断偶数且十位为5的简单实现

```cpp #include <iostream> using namespace std; int main() { int x; cin >> x; // 判断是否为偶数且十位数字为5 if (x % 2 == 0 && (x / 10) % 10 == 5) { cout << "yes" << endl; } else { cout << "no" << endl; } return 0; } ``` ######[AI问答 | 112点数解答 | 2026-07-16 19:20:42]