简化版奇偶输出程序的实现

```cpp #include <iostream> using namespace std; int n, a[105]; int main() { cin >> n; for (int i = 0; i < n; i++) cin >> a[i]; for (int i = 0; i < n; i++) if (a[i] % 2) cout << a[i] << " "; cout << endl; for (int i = 0; i < n; i++) if (a[i] % 2 == 0) cout << a[i] << " "; return 0; } ``` ######[AI问答 | 153点数解答 | 2026-05-16 19:27:21]