C++实现空间扭曲装置最终密码计算

```cpp #include <iostream> using namespace std; int main() { int password[10]; // 读取第一行的10个密码 for (int i = 0; i < 10; i++) { cin >> password[i]; } int operations[5]; // 读取第二行的5次操作 for (int i = 0; i < 5; i++) { cin >> operations[i]; } // 执行操作 for (int i = 0; i < 5; i++) { if (operations[i] == 1) { for (int j = 0; j < 10; j++) { password[j] += 10; } } else if (operations[i] == 2) { for (int j = 0; j < 10; j++) { password[j] *= 2; } } } // 计算最终密码总和 int finalPassword = 0; for (int i = 0; i < 10; i++) { finalPassword += password[i]; } // 输出最终密码 cout << finalPassword << endl; return 0; } ``` ######[AI问答 | 319点数解答 | 2026-05-01 15:52:36]