用C++找出能挪动冰箱的最小力量值

```cpp #include <iostream> #include <climits> using namespace std; int main() { int n; cin >> n; int strength[100000]; for (int i = 0; i < n; i++) { cin >> strength[i]; } int k; cin >> k; int minStrength = INT_MAX; for (int i = 0; i < n; i++) { if (strength[i] >= k && strength[i] < minStrength) { minStrength = strength[i]; } } if (minStrength == INT_MAX) { cout << "没有人能挪动冰箱" << endl; } else { cout << minStrength << endl; } return 0; } ``` ######[AI问答 | 211点数解答 | 2026-04-11 20:47:14]