C++ 仅用 <iostream> 求 1 至 n（n<=100）各数不含 1 和自身的因子个数

```cpp #include <iostream> int main() { int n; std::cin >> n; for (int i = 1; i <= n; ++i) { int count = 0; for (int j = 2; j < i; ++j) { if (i % j == 0) { ++count; } } std::cout << count << std::endl; } return 0; } ``` ######[AI问答 | 117点数解答 | 2025-12-28 19:34:48]