C++ 实现：找出 2 到 n 之间所有完全数的程序解析

```cpp #include <iostream> using namespace std; int main() { int n; cin >> n; for (int num = 2; num <= n; num++) { int sum = 0; for (int i = 1; i <= num / 2; i++) { if (num % i == 0) { sum += i; } } if (sum == num) { cout << num << endl; } } return 0; } ``` ######[AI问答 | 112点数解答 | 2025-12-20 14:49:05]