C++ 实现：依输入正整数奇偶性求 1~n 偶数和或 n 约数和

```cpp #include <iostream> using namespace std; int main() { int n; cin >> n; if (n % 2 == 1) { int sum = 0; for (int i = 2; i <= n; i += 2) { sum += i; } cout << sum << endl; } else { int sum = 0; for (int i = 1; i <= n; i++) { if (n % i == 0) { sum += i; } } cout << sum << endl; } return 0; } ``` ######[AI问答 | 141点数解答 | 2025-12-05 23:54:55]