SSD_SEND(0xDF,0x91,0x68,0xF9); SSD_SEND(0xDE,0x00); SSD_SEND(0xB2,0x00,0x7E); SSD_SEND(0xB3,0x00,0x7E); SSD_SEND(0xC1,0x00,0x08,0x00,0x00,0x00,0x00); SSD_SEND(0xBB,0x02,0x24,0x07,0x61,0x19,0x44,0x44);//00 SSD_SEND(0xBE,0x1A,0xF2); SSD_SEND(0x36,0xC0);// SSD_SEND(0xC3,0x10,0x17,0x5A,0x17,0x5A,0x05,0x05,0x05,0x05,0x15,0x15,0x31,0x05,0xDF); SSD_SEND(0xC4,0x11,0x80,0x00,0xDF,0x09,0x06,0x14); SSD_SEND(0xCE,0x00,0x03,0x
下面是将原代码转换为 `sunxi_lcd_dsi_dcs_write_1para` 函数调用的示例代码,假设 `sunxi_lcd_dsi_dcs_write_1para` 函数的功能是向 DSI 发送数据,第一个参数是命令,第二个参数是数据。 ```c // 假设 sunxi_lcd_dsi_dcs_write_1para 函数的原型 // 该函数用于向 DSI 发送命令和数据 // 参数 cmd 是命令字节 // 参数 data 是数据字节 void sunxi_lcd_dsi_dcs_write_1para(uint8_t cmd, uint8_t data); // 定义一个辅助函数,用于发送多个字节的数据 // 该函数会循环调用 sunxi_lcd_dsi_dcs_write_1para 函数 // 参数 cmd 是命令字节 // 参数 data 是数据数组 // 参数 len 是数据数组的长度 void send_multi_bytes(uint8_t cmd, uint8_t *data, uint8_t len) { for (int i = 0; i < len; i++) { sunxi_lcd_dsi_dcs_write_1para(cmd, data[i]); } } int main() { // 示例调用,将原代码转换为 sunxi_lcd_dsi_dcs_write_1para 调用 // SSD_SEND(0xDF,0x91,0x68,0xF9); uint8_t data1[] = {0x91, 0x68, 0xF9}; send_multi_bytes(0xDF, data1, sizeof(data1)); // SSD_SEND(0xDE,0x00); sunxi_lcd_dsi_dcs_write_1para(0xDE, 0x00); // SSD_SEND(0xB2,0x00,0x7E); uint8_t data2[] = {0x00, 0x7E}; send_multi_bytes(0xB2, data2, sizeof(data2)); // SSD_SEND(0xB3,0x00,0x7E); uint8_t data3[] = {0x00, 0x7E}; send_multi_bytes(0xB3, data3, sizeof(data3)); // SSD_SEND(0xC1,0x00,0x08,0x00,0x00,0x00,0x00); uint8_t data4[] = {0x00, 0x08, 0x00, 0x00, 0x00, 0x00}; send_multi_bytes(0xC1, data4, sizeof(data4)); // SSD_SEND(0xBB,0x02,0x24,0x07,0x61,0x19,0x44,0x44); uint8_t data5[] = {0x02, 0x24, 0x07, 0x61, 0x19, 0x44, 0x44}; send_multi_bytes(0xBB, data5, sizeof(data5)); // SSD_SEND(0xBE,0x1A,0xF2); uint8_t data6[] = {0x1A, 0xF2}; send_multi_bytes(0xBE, data6, sizeof(data6)); // SSD_SEND(0x36,0xC0); sunxi_lcd_dsi_dcs_write_1para(0x36, 0xC0); // SSD_SEND(0xC3,0x10,0x17,0x5A,0x17,0x5A,0x05,0x05,0x05,0x05,0x15,0x15,0x31,0x05,0xDF); uint8_t data7[] = {0x10, 0x17, 0x5A, 0x17, 0x5A, 0x05, 0x05, 0x05, 0x05, 0x15, 0x15, 0x31, 0x05, 0xDF}; send_multi_bytes(0xC3, data7, sizeof(data7)); // SSD_SEND(0xC4,0x11,0x80,0x00,0xDF,0x09,0x06,0x14); uint8_t data8[] = {0x11, 0x80, 0x00, 0xDF, 0x09, 0x06, 0x14}; send_multi_bytes(0xC4, data8, sizeof(data8)); // SSD_SEND(0xCE,0x00,0x03,0x03,0x03,0x03,0x03,0x03,0x03,0x03,0x03,0x03,0x03,0x03,0x03,0x03,0x03,0x03,0x03,0x03,0x03,0x03,0x0F,0x03); uint8_t data9[] = {0x00, 0x03, 0x03, 0x03, 0x03, 0x03, 0x03, 0x03, 0x03, 0x03, 0x03, 0x03, 0x03, 0x03, 0x03, 0x03, 0x03, 0x03, 0x03, 0x03, 0x03, 0x03, 0x0F, 0x03}; send_multi_bytes(0xCE, data9, sizeof(data9)); // SSD_SEND(0xCF,0x00,0x01,0x40,0x01,0xCA,0x01,0xCA,0x01,0xCA); uint8_t data10[] = {0x00, 0x01, 0x40, 0x01, 0xCA, 0x01, 0xCA, 0x01, 0xCA}; send_multi_bytes(0xCF, data10, sizeof(data10)); // SSD_SEND(0xD0,0x00,0x1F,0x1F,0x1F,0x1F,0x1F,0x1F,0x1F,0x1F,0x1F,0x1F,0x03,0x01,0x05,0x07,0x09,0x0B,0x1E,0x15,0x1F,0x1F,0x15,0x1F); uint8_t data11[] = {0x00, 0x1F, 0x1F, 0x1F, 0x1F, 0x1F, 0x1F, 0x1F, 0x1F, 0x1F, 0x1F, 0x1F, 0x03, 0x01, 0x05, 0x07, 0x09, 0x0B, 0x1E, 0x15, 0x1F, 0x1F, 0x15, 0x1F}; send_multi_bytes(0xD0, data11, sizeof(data11)); // SSD_SEND(0xD1,0x00,0x1F,0x1F,0x1F,0x1F,0x1F,0x1F,0x1F,0x1F,0x1F,0x1F,0x02,0x00,0x04,0x06,0x08,0x0A,0x1E,0x15,0x1F,0x1F,0x15,0x1F); uint8_t data12[] = {0x00, 0x1F, 0x1F, 0x1F, 0x1F, 0x1F, 0x1F, 0x1F, 0x1F, 0x1F, 0x1F, 0x1F, 0x02, 0x00, 0x04, 0x06, 0x08, 0x0A, 0x1E, 0x15, 0x1F, 0x1F, 0x15, 0x1F}; send_multi_bytes(0xD1, data12, sizeof(data12)); // SSD_SEND(0xD2,0x00,0x1F,0x1F,0x1F,0x1F,0x1F,0x1F,0x1F,0x1F,0x1F,0x1F,0x00,0x02,0x0A,0x08,0x06,0x04,0x1F,0x15,0x1F,0x1F,0x15,0x1E); uint8_t data13[] = {0x00, 0x1F, 0x1F, 0x1F, 0x1F, 0x1F, 0x1F, 0x1F, 0x1F, 0x1F, 0x1F, 0x1F, 0x00, 0x02, 0x0A, 0x08, 0x06, 0x04, 0x1F, 0x15, 0x1F, 0x1F, 0x15, 0x1E}; send_multi_bytes(0xD2, data13, sizeof(data13)); // SSD_SEND(0xD3,0x00,0x1F,0x1F,0x1F,0x1F,0x1F,0x1F,0x1F,0x1F,0x1F,0x1F,0x01,0x03,0x0B,0x09,0x07,0x05,0x1F,0x15,0x1F,0x1F,0x15,0x1E); uint8_t data14[] = {0x00, 0x1F, 0x1F, 0x1F, 0x1F, 0x1F, 0x1F, 0x1F, 0x1F, 0x1F, 0x1F, 0x1F, 0x01, 0x03, 0x0B, 0x09, 0x07, 0x05, 0x1F, 0x15, 0x1F, 0x1F, 0x15, 0x1E}; send_multi_bytes(0xD3, data14, sizeof(data14)); // SSD_SEND(0xD4,0x30,0x00,0x00,0x04,0x00,0x06,0x00,0x00,0x00,0x00,0x00,0x03,0x03,0x00,0x11,0x00,0x01,0xC0,0x04,0x01,0x01,0x11,0x80,0x01,0xC0,0x05,0x01,0x01,0x00,0x00,0x00,0x04,0x00,0x06,0x18,0x02,0xE3); uint8_t data15[] = {0x30, 0x00, 0x00, 0x04, 0x00, 0x06, 0x00, 0x00, 0x00, 0x00, 0x00, 0x03, 0x03, 0x00, 0x11, 0x00, 0x01, 0xC0, 0x04, 0x01, 0x01, 0x11, 0x80, 0x01, 0xC0, 0x05, 0x01, 0x01, 0x00, 0x00, 0x00, 0x04, 0x00, 0x06, 0x18, 0x02, 0xE3}; send_multi_bytes(0xD4, data15, sizeof(data15)); // SSD_SEND(0xD5,0x68,0x73,0x00,0x08,0x08,0x00,0x03,0x00); uint8_t data16[] = {0x68, 0x73, 0x00, 0x08, 0x08, 0x00, 0x03, 0x00}; send_multi_bytes(0xD5, data16, sizeof(data16)); // SSD_SEND(0xB7,0x00,0xD8,0x00,0x00,0xD8,0x00); uint8_t data17[] = {0x00, 0xD8, 0x00, 0x00, 0xD8, 0x00}; send_multi_bytes(0xB7, data17, sizeof(data17)); // SSD_SEND(0xC8,0x7F,0x69,0x5A,0x4E,0x4A,0x3B,0x40,0x2A,0x44,0x43,0x44,0x63,0x51,0x59,0x4C,0x48,0x3A,0x28,0x0F,0x7F,0x69,0x5A,0x4E,0x4A,0x3B,0x40,0x2A,0x44,0x43,0x44,0x63,0x51,0x59,0x4C,0x48,0x3A,0x28,0x0F); uint8_t data18[] = {0x7F, 0x69, 0x5A, 0x4E, 0x4A, 0x3B, 0x40, 0x2A, 0x44, 0x43, 0x44, 0x63, 0x51, 0x59, 0x4C, 0x48, 0x3A, 0x28, 0x0F, 0x7F, 0x69, 0x5A, 0x4E, 0x4A, 0x3B, 0x40, 0x2A, 0x44, 0x43, 0x44, 0x63, 0x51, 0x59, 0x4C, 0x48, 0x3A, 0x28, 0x0F}; send_multi_bytes(0xC8, data18, sizeof(data18)); // SSD_SEND(0xDE,0x02); sunxi_lcd_dsi_dcs_write_1para(0xDE, 0x02); // SSD_SEND(0xBB,0x00,0x5B,0x5C,0x41); uint8_t data19[] = {0x00, 0x5B, 0x5C, 0x41}; send_multi_bytes(0xBB, data19, sizeof(data19)); // SSD_SEND(0xC6,0x22); sunxi_lcd_dsi_dcs_write_1para(0xC6, 0x22); // SSD_SEND(0xD7,0x12); sunxi_lcd_dsi_dcs_write_1para(0xD7, [2025-10-15 16:25:31 | AI写代码神器 | 4096点数解答]
- [字节豆包] SSD_SEND(0xDF,0x91,0x68,0xF9); SSD_SEND(0xDE,0x00); SSD_SEND(0xB2,0x00,0x7E); SSD_SEND(0xB3,0x00,0x7E); SSD_SEND(0xC1,0x00,0x08,0x00,0x00,0x00,0x00); SSD_SEND(0xBB,0x02,0x24,0x07,0x61,0x19,0x44,0x44);//00 SSD_SEND(0xBE,0x1A,0xF2); SSD_SEND(0x36,0xC0);// SSD_SEND(0xC3,0x10,0x17,0x5A,0x17,0x5A,0x05,0x05,0x05,0x05,0x15,0x15,0x31,0x05,0xDF); SSD_SEND(0xC4,0x11,0x80,0x00,0xDF,0x09,0x06,0x14); SSD_SEND(0xCE,0x00,0x03,0x(4096点数解答 | 2025-10-15 16:25:31)42
- [字节豆包] ssd_send(0x11,ff,03,98,81,03); //gip_1 ssd_send(0x11,01,01,00); ssd_send(0x11,02,01,00); ssd_send(0x11,03,01,53); ssd_send(0x11,04,01,13); ssd_send(0x11,05,01,00); ssd_send(0x11,06,01,04); ssd_send(0x11,07,01,00); ssd_send(0x11,08,01,00); ssd_send(0x11,09,01,22); ssd_send(0x11,0a,01,22); ssd_send(0x11,0b,01,00); ssd_send(0x11,0c,01,01); ssd_send(0x11,0d,01,00); ssd_send(0x11,0e,01,00); ssd_send(0x11,0f,01,25);(64点数解答 | 2024-11-06 16:52:19)296
- [字节豆包] ssd_send(0x11,ff,03,98,81,03); //gip_1 ssd_send(0x11,01,01,00); ssd_send(0x11,02,01,00); ssd_send(0x11,03,01,53); ssd_send(0x11,04,01,13); ssd_send(0x11,05,01,00); ssd_send(0x11,06,01,04); ssd_send(0x11,07,01,00); ssd_send(0x11,08,01,00); ssd_send(0x11,09,01,22); ssd_send(0x11,0a,01,22); ssd_send(0x11,0b,01,00); ssd_send(0x11,0c,01,01); ssd_send(0x11,0d,01,00); ssd_send(0x11,0e,01,00); ssd_send(0x11,0f,01,25); 转换为sunxi_lcd_dsi_dcs_write_1para(657点数解答 | 2025-10-15 16:21:12)46
- [字节豆包] SSD_SEND(0xBB,0x02,0x24,0x07,0x61,0x19,0x44,0x44);//00 SSD_SEND(0xBE,0x1A,0xF2); SSD_SEND(0x36,0xC0);// SSD_SEND(0xC3,0x10,0x17,0x5A,0x17,0x5A,0x05,0x05,0x05,0x05,0x15,0x15,0x31,0x05,0xDF); SSD_SEND(0xC4,0x11,0x80,0x00,0xDF,0x09,0x06,0x14); SSD_SEND(0xCE,0x00,0x03,0x03,0x03,0x03,0x03,0x03,0x03,0x03,0x03,0x03,0x03,0x03,0x03,0x03,0x03,0x03,0x03,0x03,0x03,0x03,0x0F,0x03); SSD_SEND(0xCF,0x00,0x01,0x40,0x01,0xCA,0x01,0xCA,0x01(2484点数解答 | 2025-10-15 16:23:26)32
- [字节豆包] function optimalCuttingPlan() % 最优切割方案计算函数(已测试通过) % 作者:数学建模助手 % 最后修改:2023-10-15 %% 数据准备(使用硬编码数据避免文件读取问题) % 原材料数据 [ID, 长度, 缺陷位置, 缺陷长度, 单价] raw_data = [ 1 5.5 1 0.3 17 1 5.5 3 0.2 17.33 2 6.2 2 0.4 20.59 3 7 1.5 0.2 24.41 3 7 4 0.3 24.05 4 5.8 1.2 0.5 17.33 5 6.5 2.3 0.3 22 6 7.5 1 0.6 24.77 7 6 2.8 0.4 19.83 8 8.2 1.3 0.5 27.64 9 6.8 2.1 0.3 23.32 9 6.8 5 0.2 23.69 10 5.6 1.1 0.2 17.66 11 7.3 3.1 0.4 24.77 12 6.1 1.7 0.5 19.83 13 8 2.5 0.3 27.64 14 5.9 3 0.4 18 15 6.3 1.9 0.3 21.27 16 7.8 1.2 0.(3226点数解答 | 2025-06-18 20:59:55)140
- [阿里通义] aug 28 10:10:47 yalaw-oa-online-nginx-02 kernel: in=ens192 out= mac=00:0c:29:5d:43:5e:98:44:ce:95:e6:10:08:00 src=47.116.84.195 dst=192.168.51.22 len=40 tos=0x00 prec=0x00 ttl=47 id=22583 df proto=tcp spt=443 dpt=35812 window=10108 res=0x00 ack urgp=0 iptables日志分析(665点数解答 | 2024-08-28 10:18:51)241
- [字节豆包] aug 28 16:11:41 yalaw-oa-online-nginx-02 kernel: in=ens192 out= mac=00:0c:29:5d:43:5e:98:44:ce:95:e6:10:08:00 src=47.102.52.8 dst=192.168.51.22 len=40 tos=0x00 prec=0x00 ttl=47 id=49529 df proto=tcp spt=443 dpt=46618 window=10108 res=0x00 ack urgp=0 iptables怎么屏蔽spt=443的日志记录(189点数解答 | 2024-08-28 16:12:16)216
- [阿里通义] aug 28 16:11:41 yalaw-oa-online-nginx-02 kernel: in=ens192 out= mac=00:0c:29:5d:43:5e:98:44:ce:95:e6:10:08:00 src=47.102.52.8 dst=192.168.51.22 len=40 tos=0x00 prec=0x00 ttl=47 id=49529 df proto=tcp spt=443 dpt=46618 window=10108 res=0x00 ack urgp=0 iptables怎么屏蔽spt=443的日志记录(469点数解答 | 2024-08-28 16:13:03)211
- [讯飞星火] aug 28 16:11:41 yalaw-oa-online-nginx-02 kernel: in=ens192 out= mac=00:0c:29:5d:43:5e:98:44:ce:95:e6:10:08:00 src=47.102.52.8 dst=192.168.51.22 len=40 tos=0x00 prec=0x00 ttl=47 id=49529 df proto=tcp spt=443 dpt=46618 window=10108 res=0x00 ack urgp=0 iptables怎么屏蔽spt=443的日志记录(129点数解答 | 2024-08-28 16:13:37)235
- [百度文心] aug 28 16:11:41 yalaw-oa-online-nginx-02 kernel: in=ens192 out= mac=00:0c:29:5d:43:5e:98:44:ce:95:e6:10:08:00 src=47.102.52.8 dst=192.168.51.22 len=40 tos=0x00 prec=0x00 ttl=47 id=49529 df proto=tcp spt=443 dpt=46618 window=10108 res=0x00 ack urgp=0 iptables怎么屏蔽spt=443的日志记录(542点数解答 | 2024-08-28 16:15:03)213
- [字节豆包] aug 28 16:11:41 yalaw-oa-online-nginx-02 kernel: in=ens192 out= mac=00:0c:29:5d:43:5e:98:44:ce:95:e6:10:08:00 src=47.102.52.8 dst=192.168.51.22 len=40 tos=0x00 prec=0x00 ttl=47 id=49529 df proto=tcp spt=443 dpt=46618 window=10108 res=0x00 ack urgp=0 iptables怎么屏蔽spt=443的日志记录(149点数解答 | 2024-08-28 16:15:21)215
- [字节豆包] 救援争先 内存限制: 256 Mb时间限制: 1000 ms 题目描述 某地出现了灾害,各地派出了 n n 只救援队。这些救援队是在同一天出发的,但出发时间不一样,路程也有长有短,所以达到时间有先有后。 给定每个队伍的出发时间,以及每只队伍的路程,请按照到达时间为这些队伍排序,如果多只队伍的到达时间正好相等,则出发时间靠前的队伍排在前列,如果出发时间仍然相等,则编号较小的队伍排在前列。 输入格式 第一行:单个整数 n n,表示救援队数量。 第二行到第 n + 1 n+1 行:在第 i + 1 i+1 行,有两个时间,表示第 i i 只救援队的出发时间和路程,数据格式均为 hh:mm: hh 表示小时,在 00 到 23 之间; mm 表示分钟,在 00 到 59 之间。 输出格式 共 n n 行,每行一个整数,按救援队到达的先后顺序输出它们的编号。 数据范围 1 ≤ n ≤ 1000 1≤n≤1000。 样例数据 输入: 3 19:00 01:00 15:00 05:00 15:00 05:00 输出: 2 3 1 说明: 3只队伍同时到达,2号和3号出发较早,所(693点数解答 | 2025-08-07 10:56:54)153