用C++高精度算法求解 0 到 100 范围内 2 的 n 次方！附完整代码

```cpp #include <iostream> #include <vector> using namespace std; vector<int> multiplyByTwo(vector<int> num) { int carry = 0; for (int i = 0; i < num.size(); i++) { int prod = num[i] * 2 + carry; num[i] = prod % 10; carry = prod / 10; } while (carry) { num.push_back(carry % 10); carry /= 10; } return num; } void print(vector<int> num) { for (int i = num.size() - 1; i >= 0; i--) { cout << num[i]; } cout << endl; } int main() { int n; cin >> n; vector<int> result(1, 1); for (int i = 0; i < n; i++) { result = multiplyByTwo(result); } print(result); return 0; } ``` ######[AI问答 | 253点数解答 | 2025-09-26 19:41:27]