输入一个正整数a，按口诀“奇数平方写连续，偶数半方加减1”计算勾股数组合(a, b, c)中的另外两个数b, c，a<b<c。c++,要加using namespace std;,不要注释

```cpp #include <iostream> using namespace std; int main() { int a; cin >> a; int b, c; if (a % 2 == 1) { b = (a * a - 1) / 2; c = b + 1; } else { b = a * a / 4 - 1; c = b + 2; } cout << b << " " << c << endl; return 0; } ``` [2025-09-15 20:26:23 | AI问答 | 127点数解答]