Matlab编程：血管机器人订购与生物学习，实现104周运营成本最低方案

以下是针对该问题的详细解决方案，包含两个脚本式M文件的代码，用于迭代计算第一组和第二组第1 - 104周的数据，确定每周需要购买的容器艇和操作手数量，以使运营成本达到最低，并将相关数据输出到Excel文件中。 脚本式M文件 `pr_qmks7_gjyy21.m` ```matlab % 定义相关参数 num_weeks = 104; % 总周数 container_cost = 200; % 容器艇购买价格 operator_cost = 100; % 操作手购买价格 operator_maintenance_cost = 5; % 操作手保养费用 container_maintenance_cost = 10; % 容器艇保养费用 operator_training_cost = 10; % 操作手训练费用 % 第一组数据 usage_data_1 = [11 5 4 7 16 6 5 7 ... 13 6 5 7 12 5 4 6 ... 9 5 5 11 29 21 17 20 ... 27 13 9 10 16 6 5 7 ... 11 5 5 6 12 7 7 10 ... 15 10 9 11 15 10 10 16 ... 26 21 23 36 50 45 45 49 ... 57 43 40 44 52 43 42 45 ... 52 41 39 41 48 35 34 35 ... 42 34 36 43 55 48 54 65 ... 80 70 74 85 101 89 88 90 ... 100 87 88 89 104 89 89 90 ... 106 96 94 99 108 98 95 100]; % 初始化变量 purchased_containers = zeros(1, num_weeks); % 每周购买的容器艇数量 purchased_operators = zeros(1, num_weeks); % 每周购买的操作手数量 used_containers = zeros(1, num_weeks); % 每周使用的容器艇数量 used_operators = zeros(1, num_weeks); % 每周使用的操作手数量 maintained_containers = zeros(1, num_weeks); % 每周保养的容器艇数量 maintained_operators = zeros(1, num_weeks); % 每周保养的操作手数量 training_containers = zeros(1, num_weeks); % 每周用于培训的容器艇数量 training_operators = zeros(1, num_weeks); % 每周用于培训的熟练操作手数量 total_containers = zeros(1, num_weeks); % 每周容器艇的总数量 total_operators = zeros(1, num_weeks); % 每周操作手的总数量 % 初始条件 initial_containers = 13; initial_operators = 50; total_containers(1) = initial_containers; total_operators(1) = initial_operators; % 迭代计算每周数据 for week = 1:num_weeks % 计算本周需要的容器艇和操作手数量 used_operators(week) = usage_data_1(week); used_containers(week) = ceil(used_operators(week) / 4); % 计算需要购买的操作手数量 new_operators_needed = max(0, used_operators(week) - total_operators(week)); purchased_operators(week) = new_operators_needed; % 计算需要购买的容器艇数量 new_containers_needed = max(0, used_containers(week) - total_containers(week)); purchased_containers(week) = new_containers_needed; % 计算培训所需的容器艇和操作手数量 if week >= 2 % 假设培训规则 newbies = purchased_operators(week - 1); trainers_needed = ceil(newbies / 9); training_groups = ceil(newbies / (3 * trainers_needed)); training_containers(week) = min(ceil(training_groups / 3), total_containers(week)); training_operators(week) = min(trainers_needed, total_operators(week)); end % 计算保养的容器艇和操作手数量 if week >= 2 maintained_containers(week) = total_containers(week - 1) - used_containers(week - 1); maintained_operators(week) = total_operators(week - 1) - used_operators(week - 1); end % 更新总数量 if week < num_weeks total_containers(week + 1) = total_containers(week) + purchased_containers(week) - maintained_containers(week); total_operators(week + 1) = total_operators(week) + purchased_operators(week) - maintained_operators(week); end end % 计算总成本 purchase_cost_containers = sum(purchased_containers) * container_cost; purchase_cost_operators = sum(purchased_operators) * operator_cost; maintenance_cost_containers = sum(maintained_containers) * container_maintenance_cost; maintenance_cost_operators = sum(maintained_operators) * operator_maintenance_cost; training_cost_operators = sum(training_operators) * operator_training_cost; jie_qmks7_gjyy21 = purchase_cost_containers + purchase_cost_operators + maintenance_cost_containers + maintenance_cost_operators + training_cost_operators; % 输出数据到Excel文件 filename = '附录信息文件\7 高级应用题二素材\血管机器人的数据.xlsx'; sheet = 1; xlswrite(filename, purchased_containers, sheet, 'B2:DA2'); xlswrite(filename, purchased_operators, sheet, 'B3:DA3'); xlswrite(filename, used_containers, sheet, 'B4:DA4'); xlswrite(filename, used_operators, sheet, 'B5:DA5'); xlswrite(filename, maintained_containers, sheet, 'B6:DA6'); xlswrite(filename, maintained_operators, sheet, 'B7:DA7'); xlswrite(filename, training_containers, sheet, 'B8:DA8'); xlswrite(filename, training_operators, sheet, 'B9:DA9'); xlswrite(filename, total_containers, sheet, 'B10:DA10'); xlswrite(filename, total_operators, sheet, 'B11:DA11'); ``` 脚本式M文件 `pr_qmks7_gjyy22.m` ```matlab % 定义相关参数 num_weeks = 104; % 总周数 container_cost = 200; % 容器艇购买价格 operator_cost = 100; % 操作手购买价格 operator_maintenance_cost = 5; % 操作手保养费用 container_maintenance_cost = 10; % 容器艇保养费用 operator_training_cost = 10; % 操作手训练费用 % 第二组数据 usage_data_2 = [11 16 13 12 9 29 27 16 ... 11 12 15 15 26 50 57 52 ... 52 48 42 55 80 101 100 104 ... 106 108 5 6 6 5 5 21 ... 13 6 5 7 10 10 21 45 ... 43 43 41 35 34 48 70 89 ... 87 89 96 98 4 5 5 4 ... 5 17 9 5 5 7 9 10 ... 23 45 40 42 39 34 36 54 ... 74 88 88 89 94 95 7 7 ... 7 6 11 20 10 7 6 10 ... 11 16 36 49 44 45 41 35 ... 43 65 85 90 89 90 99 100]; % 初始化变量 purchased_containers = zeros(1, num_weeks); % 每周购买的容器艇数量 purchased_operators = zeros(1, num_weeks); % 每周购买的操作手数量 used_containers = zeros(1, num_weeks); % 每周使用的容器艇数量 used_operators = zeros(1, num_weeks); % 每周使用的操作手数量 maintained_containers = zeros(1, num_weeks); % 每周保养的容器艇数量 maintained_operators = zeros(1, num_weeks); % 每周保养的操作手数量 training_containers = zeros(1, num_weeks); % 每周用于培训的容器艇数量 training_operators = zeros(1, num_weeks); % 每周用于培训的熟练操作手数量 total_containers = zeros(1, num_weeks); % 每周容器艇的总数量 total_operators = zeros(1, num_weeks); % 每周操作手的总数量 % 初始条件 initial_containers = 13; initial_operators = 50; total_containers(1) = initial_containers; total_operators(1) = initial_operators; % 迭代计算每周数据 for week = 1:num_weeks % 计算本周需要的容器艇和操作手数量 used_operators(week) = usage_data_2(week); used_containers(week) = ceil(used_operators(week) / 4); % 计算需要购买的操作手数量 new_operators_needed = max(0, used_operators(week) - total_operators(week)); purchased_operators(week) = new_operators_needed; % 计算需要购买的容器艇数量 new_containers_needed = max(0, used_containers(week) - total_containers(week)); purchased_containers(week) = new_containers_needed; % 计算培训所需的容器艇和操作手数量 if week >= 2 % 假设培训规则 newbies = purchased_operators(week - 1); trainers_needed = ceil(newbies / 9); training_groups = ceil(newbies / (3 * trainers_needed)); training_containers(week) = min(ceil(training_groups / 3), total_containers(week)); training_operators(week) = min(trainers_needed, total_operators(week)); end % 计算保养的容器艇和操作手数量 if week >= 2 maintained_containers(week) = total_containers(week - 1) - used_containers(week - 1); maintained_operators(week) = total_operators(week - 1) - used_operators(week - 1); end % 更新总数量 if week < num_weeks total_containers(week + 1) = total_containers(week) + purchased_containers(week) - maintained_containers(week); total_operators(week + 1) = total_operators(week) + purchased_operators(week) - maintained_operators(week); end end % 计算总成本 purchase_cost_containers = sum(purchased_containers) * container_cost; purchase_cost_operators = sum(purchased_operators) * operator_cost; maintenance_cost_containers = sum(maintained_containers) * container_maintenance_cost; maintenance_cost_operators = sum(maintained_operators) * operator_maintenance_cost; training_cost_operators = sum(training_operators) * operator_training_cost; jie_qmks7_gjyy22 = purchase_cost_containers + purchase_cost_operators + maintenance_cost_containers + maintenance_cost_operators + training_cost_operators; % 输出数据到Excel文件 filename = '附录信息文件\7 高级应用题二素材\血管机器人的数据.xlsx'; sheet = 2; xlswrite(filename, purchased_containers, sheet, 'B2:DA2'); xlswrite(filename, purchased_operators, sheet, 'B3:DA3'); xlswrite(filename, used_containers, sheet, 'B4:DA4'); xlswrite(filename, used_operators, sheet, 'B5:DA5'); xlswrite(filename, maintained_containers, sheet, 'B6:DA6'); xlswrite(filename, maintained_operators, sheet, 'B7:DA7'); xlswrite(filename, training_containers, sheet, 'B8:DA8'); xlswrite(filename, training_operators, sheet, 'B9:DA9'); xlswrite(filename, total_containers, sheet, 'B10:DA10'); xlswrite(filename, total_operators, sheet, 'B11:DA11'); ``` 额外需要注意的逻辑点 1. 培训规则的严格执行：每次培训是一个熟练的操作手带3个新手在一个容器艇上进行训练，每个熟练操作手最多“指导”9个新操作手，每个容器艇最多进行三组培训工作。在计算培训所需的容器艇和操作手数量时，需要严格遵循这些规则。 2. 时间延迟的考虑：购买的容器艇和操作手在每周周一时下订单，周日到货，下周安排检查调试和生物学习，第三周开始投入使用。在计算每周的使用和购买数量时，需要考虑这种时间延迟。 3. 成本计算的准确性：运营成本包括购买成本、保养成本和培训成本。在计算总成本时，需要确保各项成本的计算准确无误，避免遗漏或重复计算。 通过以上两个脚本式M文件，可以分别计算第一组和第二组数据下每周需要购买的容器艇和操作手数量，使运营成本达到最低，并将相关数据输出到Excel文件中。 ######[AI写代码神器 | 3384点数解答 | 2025-06-22 13:25:13]