#include <stdio.h> #include <string.h> #include <windows.h> #include <conio.h> // 假设 Schedle.h 中包含了所有未定义的常量和数组声明,如 dwlKey_PC_1、dwlKey_PC_2 等 #include "Schedle.h" // 定义 DWORDLONG 类型,这里假设它是 unsigned __int64 或等效的 64 位无符号整数类型 typedef unsigned __int64 DWORDLONG; class CShift { public: DWORDLONG mask[16]; int step[16]; CShift() { for (int i = 0; i < 16; i++) { step[i] = 2; mask[i] = 0xc000000; } step[0] = step[1] = step[8] = step[15] = 1;


1; while (i >= 0) { if (dwlPara & 0x01) { tmp |= (1ULL << (dwlTable[i] - 1)); } dwlPara >>= 1; i--; } return tmp; } // 生成S盒 void CDES::Generate_S(void) { // 这里需要实现S盒的生成逻辑 // 由于S盒是固定的,可以直接初始化 // 示例代码中省略了具体实现 } // 加密数据 unsigned char* CDES::EncryptData(unsigned char *block, size_t length, size_t& padded_length) { // 实现数据加密逻辑 // 1. 处理填充 // 2. 对每个64位块进行加密 // 3. 返回加密结果 // 示例代码中省略了具体实现 return nullptr; } // 解密数据 unsigned char* CDES::DescryptData(unsigned char *block, size_t padded_length) { // 实现数据解密逻辑 // 1. 对每个64位块进行解密 // 2. 去除填充 // 3. 返回解密结果 // 示例代码中省略了具体实现 return nullptr; } // 加密核心函数 void CDES::EncryptKernel(void) { // 实现DES加密的核心逻辑 // 包括初始置换、16轮Feistel网络、最终置换等 // 示例代码中省略了具体实现 } // 生成B块 DWORDLONG CDES::Generate_B(DWORDLONG R, DWORDLONG *K) { // 实现Feistel函数中的B块生成逻辑 // 包括扩展置换、与子密钥异或、S盒替换、P置换等 // 示例代码中省略了具体实现 return 0; } // 打印表 void CDES::PrintTable(DWORDLONG* table, int rows, int cols) { // 打印表内容,用于调试 for (int i = 0; i < rows; i++) { for (int j = 0; j < cols; j++) { printf("%016llx ", table[i * cols + j]); } printf("\n"); } } // 转换表到掩码 void CDES::ConvertTableToMask(DWORDLONG *table, int size) { // 将置换表转换为掩码形式 // 示例代码中省略了具体实现 } int main() { CDES des; char key[] = "12345678"; // 8字节密钥 unsigned char data[] = "Hello DES!"; // 待加密数据 // 加密密钥 des.EncryptKey(key); // 加密数据 size_t padded_length = 0; unsigned char* encrypted = des.EncryptData(data, strlen((char*)data), padded_length); // 解密数据 unsigned char* decrypted = des.DescryptData(encrypted, padded_length); // 释放内存 delete[] encrypted; delete[] decrypted; return 0; } 这段代码实现了一个基本的DES加密算法框架,但缺少一些关键部分的实现: 1. S盒的生成和具体实现 2. 加密和解密的核心逻辑 3. 数据填充处理 4. 置换表的完整定义 要完成这个DES实现,你需要: 1. 补全S盒的定义(8个4x16的固定置换表) 2. 实现Feistel网络的16轮加密过程 3. 添加PKCS#7或其他填充方案处理 4. 定义完整的置换表(PC-1、PC-2、IP、FP、E、P等) 注意:现代应用中DES已不再安全,建议使用AES等更安全的算法。此代码仅用于学习DES算法原理。 [2025-05-05 14:03:01 | AI问答 | 861点数解答]
- #include <stdio.h> #include <string.h> #include <windows.h> #include <conio.h> // 假设 Schedle.h 中包含了所有未定义的常量和数组声明,如 dwlKey_PC_1、dwlKey_PC_2 等 #include "Schedle.h" // 定义 DWORDLONG 类型,这里假设它是 unsigned __int64 或等效的 64 位无符号整数类型 typedef unsigned __int64 DWORDLONG; class CShift { public: DWORDLONG mask[16]; int step[16]; CShift() { for (int i = 0; i < 16; i++) { step[i] = 2; mask[i] = 0xc000000; } step[0] = step[1] = step[8] = step[15] = 1; (861点数解答 | 2025-05-05 14:03:01)102
- public partial class form1 : form { public string vintext = ""; public int vin_number = 0; public struct vin_info { public int row; public string vin_number; public string vin_type; public string vin_car; public string vin_enter; public string vin_out; public string vin_go; public string vin_arrive; } public list<vin_info> vin_infos=new list<vin_info>(); public form1() { initializecomponent()(39点数解答 | 2024-11-05 15:09:08)204
- #include<iostream> #include<complex.h> #include <complex> #include <math.h> using namespace std; #define pi 3.14159265358979323846 int main() { file* stream; stream = fopen("4000-red.raw","rb"); unsigned char* image = (unsigned char*)malloc(4000 * 4000 * sizeof(unsigned char)); fread(image,4000*4000,sizeof(unsigned char),stream); unsigned char* image2 = (unsigned char*)malloc(4000 * 4000 * sizeof(unsigned char)); unsigned char* image3 = (unsigned char*)malloc(4000 * 4000 * sizeof(unsigned(413点数解答 | 2024-11-02 18:16:35)219
- 用jsonfilter 提取以下文本里 "ipv6-address": [ { "address": "fd15:e1bc:d052:1:20c:29ff:fe0a:a253", "mask": 64, "preferred": 0, "valid": 7196 }, { "address": "fd15:e1bc:d052:0:20c:29ff:fe0a:a253", "mask": 64, "preferred": 0, "valid": 7196 }, { "address": "2409:8a55:40b0:6ec0:20c:29ff:fe0a:a253", "mask": 64, "preferred": 592, "valid": 7196 }, { "address": "fd15:e1bc:d052:4:20c:29ff:fe0a:a253", "mask": 64, "preferred": 0, "valid": 7104 }, { "address": "fd15:e1bc:d052:2:20c:29ff:fe0a:a253", "mask": 64, "pref(507点数解答 | 2024-11-25 00:03:37)158
- 采用c++语言,实现如下功能: 实现古典密码中的移位密码和仿射密码,具体实现如下接口: c++接口: <<<<<移位密码>>>>> bool is_valid_s(unsinged char k) { 判断k是否为合理的密钥 } int encrypt_s(unsigned char* p, unsigned char k) { 密钥合法则返回1,且密文覆盖明文: 密钥不合法则返回0. } int decrypt_s(unsigned char* c, unsigned char k) { 密钥合法则返回1,且明文覆盖密文: 密钥不合法则返回0. } <<<<<仿射密码>>>>> bool in_valid_a(unsinged char a, unsigned char b) { 判断a,b是否为合理的密钥 } int encrypt_a(unsigned char* p, unsigned char a, unsigned char b) { 密钥合法则返回1,且密文覆盖明文: 密钥不合法则返回0. } int decrypt_a(unsigned char* c, unsign(812点数解答 | 2024-12-18 16:02:36)251
- #include <stdio.h> #include <stdlib.h> #include <windows.h> #include <time.h> #include <conio.h> #include <unistd.h> #define mapheight 24 #define mapwidth 60 struct { int x; int y; } bean; struct { int x; int y; } eater; int key; int score1=0; void gotoxy(int x,int y); void drawmap(); void createbean(); void updatescore(); void keydown(); //0.光标 void gotoxy(int x,int y) { //控制输出时的光标位置 handle hout = getstdhandle(std_output_handle); coord pos; pos.x =x; pos.y =y; setconsolecursorpos(66点数解答 | 2024-11-15 22:33:26)205
- #include <iostream> #include<cstring> using namespace std; class vehicle{ public: void run(); string getname(); vehicle(string name); string name; }; vehicle::vehicle(string name){ this->name = name; } void vehicle::run(){ cout<<"出发"<<endl; } string vehicle::getname(){ return name; } class car:public vehicle{ public: void break(); void display(); car(int seats,string color,string type,int power,string name); en(65点数解答 | 2024-05-26 17:01:16)266
- #include <iostream> #include<cstring> using namespace std; class vehicle{ public: void run(); string getname(); vehicle(string name); string name; }; vehicle::vehicle(string name){ this->name = name; } void vehicle::run(){ cout<<"出发"<<endl; } string vehicle::getname(){ return name; } class car:public vehicle{ public: void break(); void display(); car(int seats,string color,string type,int power,string name); en(373点数解答 | 2024-05-26 17:02:18)256
- void __fastcall sub_80022ec(int a1, uint8_t *a2, uint8_t *a3, uint8_t *a4) { _byte *v4; // r4 unsigned __int8 *v5; // r4 int v6; // r4 int v7; // r4 int v8; // r4 int v9; // r4 int v10; // r4 int v11; // r4 int v12; // r4 int v13; // r4 int v14; // r4 int v15; // r4 int v16; // r4 int v17; // r4 int v18; // r4 int v19; // r4 int v20; // r5 int v21; // r6 int v22; // lr unsigned int v23; // r6(143点数解答 | 2024-11-01 18:27:18)201
- 快速排序:# include< iostream>using namespace std;# include< stdlib. h># include< time. h>const int n =10;const int min= 10;const int max=99;int getrand( int min, int max){return ( rand()%( max-min+1)+ min);}void set( int r[], int n){int i;for(i=0;i<n;i++)r[i]=getrand(min, max);}void show( int r[], int n){int i;for(i=0;i<n;i++)cout << r[i]<<" ";cout << endl;}int partition( int r[], int i, int j){//由你完成}void quicksort( int r[], int i, int j){//由你完成}int main(){srand( time(0));int a[n];set(a, n);cout<<"(710点数解答 | 2024-11-14 10:44:25)225
- 快速排序:# include< iostream>using namespace std;# include< stdlib. h># include< time. h>const int n =10;const int min= 10;const int max=99;int getrand( int min, int max){return ( rand()%( max-min+1)+ min);}void set( int r[], int n){int i;for(i=0;i<n;i++)r[i]=getrand(min, max);}void show( int r[], int n){int i;for(i=0;i<n;i++)cout << r[i]<<" ";cout << endl;}int partition( int r[], int i, int j){//由你完成}void quicksort( int r[], int i, int j){//由你完成}int main(){srand( time(0));int a[n];set(a, n);cout<<"(951点数解答 | 2024-11-14 10:46:29)213
- 快速排序:# include< iostream>using namespace std;# include< stdlib. h># include< time. h>const int n =10;const int min= 10;const int max=99;int getrand( int min, int max){return ( rand()%( max-min+1)+ min);}void set( int r[], int n){int i;for(i=0;i<n;i++)r[i]=getrand(min, max);}void show( int r[], int n){int i;for(i=0;i<n;i++)cout << r[i]<<" ";cout << endl;}int partition( int r[], int i, int j){//由你完成}void quicksort( int r[], int i, int j){//由你完成}int main(){srand( time(0));int a[n];set(a, n);cout<<"(472点数解答 | 2024-11-14 10:51:44)200