把这个代码修改正确#include<reg52.h> sbit key = p3^0; // 按键连接到p3.0 unsigned char code seg_code[] = {0x3f, 0x06, 0x5b, 0x4f, 0x66, 0x6d, 0x7d, 0x07, 0x7f, 0x6f}; // 数码管段码 unsigned char code dash_code = 0x40; // 横杠段码 unsigned int second =0; // 秒表计数 bit running = 0; // 秒表运行状态 void timer0_isr() interrupt 1 { static unsigned int count =0; th0 = (65536 - 1000) / 256; tl0 = (65536 - 1000) %256; count++; if (count >= 1000) { count = 0; if (running) { second++; } } } void delay(unsigned int ms) { unsigned int i


你的代码有一些小问题,我将帮助你修正并完善它。以下是修改后的代码: ```c #include <reg52.h> sbit key = P3^0; // 按键连接到P3.0 unsigned char code seg_code[] = {0x3f, 0x06, 0x5b, 0x4f, 0x66, 0x6d, 0x7d, 0x07, 0x7f, 0x6f}; // 数码管段码 unsigned char code dash_code = 0x40; // 横杠段码 unsigned int second = 0; // 秒表计数 bit running = 0; // 秒表运行状态 void timer0_isr() interrupt 1 { static unsigned int count = 0; TH0 = (65536 - 1000) / 256; TL0 = (65536 - 1000) % 256; count++; if (count >= 1000) { count = 0; if (running) { second++; } } } void delay(unsigned int ms) { unsigned int i, j; for (i = 0; i < ms; i++) { for (j = 0; j < 123; j++); } } void main() { TMOD = 0x01; // 设置定时器0为模式1(16位定时器) TH0 = (65536 - 1000) / 256; TL0 = (65536 - 1000) % 256; TR0 = 1; // 启动定时器0 ET0 = 1; // 使能定时器0中断 EA = 1; // 使能全局中断 while (1) { if (key == 0) { // 检测按键是否按下 delay(10); // 去抖动 if (key == 0) { running = !running; // 切换秒表运行状态 while (key == 0); // 等待按键释放 } } // 显示当前秒数 unsigned char sec = second % 100; // 取最后两位秒数 P1 = seg_code[sec / 10]; // 显示十位 P2 = seg_code[sec % 10]; // 显示个位 } } ``` 主要修改点: 1. 按键去抖动:在检测到按键按下后,增加一个 `delay(10)` 去抖动,并且在按键释放后再进行操作。 2. 显示秒数:在主循环中,通过 `P1` 和 `P2` 端口显示当前的秒数。 3. 定时器初始化:在 `main` 函数中初始化定时器0,并启动定时器和中断。 说明: - `seg_code` 数组用于将数字转换为数码管的段码。 - `P1` 和 `P2` 端口用于控制数码管的显示。 - `delay` 函数用于延时,去抖动和等待按键释放。 希望这些修改能帮助你实现秒表功能。如果有任何问题或需要进一步的帮助,请告诉我! [2024-10-23 22:51:51 | AI写代码神器 | 776点数解答]
- 把这个代码修改正确#include<reg52.h> sbit key = p3^0; // 按键连接到p3.0 unsigned char code seg_code[] = {0x3f, 0x06, 0x5b, 0x4f, 0x66, 0x6d, 0x7d, 0x07, 0x7f, 0x6f}; // 数码管段码 unsigned char code dash_code = 0x40; // 横杠段码 unsigned int second =0; // 秒表计数 bit running = 0; // 秒表运行状态 void timer0_isr() interrupt 1 { static unsigned int count =0; th0 = (65536 - 1000) / 256; tl0 = (65536 - 1000) %256; count++; if (count >= 1000) { count = 0; if (running) { second++; } } } void delay(unsigned int ms) { unsigned int i(776点数解答 | 2024-10-23 22:51:51)203
- 完善代码#include<reg51.h> #include <intrins.h> code unsigned char tab[] = {0x3f,0x06,0x5b,0x4f,0x66,0x6d,0x7d,0x07,0x7f,0x6f,0x40}; unsigned char dspbuf[8] = {0,0,10,0,0,10,0,0}; unsigned char i,j,k; unsigned char dspbuf1[8] = {0,0,10,0,0,10,0,0}; code unsigned int yindiao[]={0,120,106,94,89,79,71,62,59, 56, 53, 50, 47, 44, 41, 38}; code unsigned int jiepai[]={0,523,587,659,698,784,880,988};(334点数解答 | 2024-11-25 18:12:57)160
- 告诉我那里错误#include<reg51.h> #include <intrins.h> code unsigned char tab[] = {0x3f,0x06,0x5b,0x4f,0x66,0x6d,0x7d,0x07,0x7f,0x6f,0x40}; unsigned char dspbuf[8] = {0,0,10,0,0,10,0,0}; unsigned char i,j,k; unsigned char dspbuf1[8] = {0,0,10,0,0,10,0,0}; code unsigned int yindiao[]={0,120,106,94,89,79,71,62,59, 56, 53, 50, 47, 44, 41, 38}; code unsigned int jiepai[]={0,523,587,659,698,784,880,988(78点数解答 | 2024-11-25 18:13:58)162
- #include<iostream> #include<complex.h> #include <complex> #include <math.h> using namespace std; #define pi 3.14159265358979323846 int main() { file* stream; stream = fopen("4000-red.raw","rb"); unsigned char* image = (unsigned char*)malloc(4000 * 4000 * sizeof(unsigned char)); fread(image,4000*4000,sizeof(unsigned char),stream); unsigned char* image2 = (unsigned char*)malloc(4000 * 4000 * sizeof(unsigned char)); unsigned char* image3 = (unsigned char*)malloc(4000 * 4000 * sizeof(unsigned(413点数解答 | 2024-11-02 18:16:35)219
- 采用c++语言,实现如下功能: 实现古典密码中的移位密码和仿射密码,具体实现如下接口: c++接口: <<<<<移位密码>>>>> bool is_valid_s(unsinged char k) { 判断k是否为合理的密钥 } int encrypt_s(unsigned char* p, unsigned char k) { 密钥合法则返回1,且密文覆盖明文: 密钥不合法则返回0. } int decrypt_s(unsigned char* c, unsigned char k) { 密钥合法则返回1,且明文覆盖密文: 密钥不合法则返回0. } <<<<<仿射密码>>>>> bool in_valid_a(unsinged char a, unsigned char b) { 判断a,b是否为合理的密钥 } int encrypt_a(unsigned char* p, unsigned char a, unsigned char b) { 密钥合法则返回1,且密文覆盖明文: 密钥不合法则返回0. } int decrypt_a(unsigned char* c, unsign(812点数解答 | 2024-12-18 16:02:36)251
- #include <reg51.h> sbit LED = P1^0; sbit KEY = P1^1; void delay(unsigned int ms) { unsigned int i; for(; ms>0; ms--) for(i=0; i<120; i++); } void main() { while(1) { if(KEY == 0) { delay(20); if(KEY == 0) { LED = ~LED; while(KEY == 0); } } } } (326点数解答 | 2025-06-22 23:19:40)99
- #include <stc15f2k60s2.h> // 数码管段选码 unsigned char code seg_code[] = { 0xc0, 0xf9, 0xa4, 0xb0, 0x99, 0x92, 0x82, 0xf8, 0x80, 0x90, 0x88, 0x83, 0xc6, 0xa1, 0x86, 0x8e }; // 数码管位选码 unsigned char code bit_code[] = { 0xfe, 0xfd, 0xfb, 0xf7, 0xef, 0xdf, 0xbf, 0x7f }; void delay(unsigned int t) { while (t--) ; } void initadc() { p1asf = 0xff; // 将 p1 口设置为模拟输入口 adc_contr = 0x80; // 打开 adc 电源 delay(2); // 适当延时等待 adc 电源稳定 } unsigned int getadcresult() { adc_con(939点数解答 | 2024-11-07 17:31:31)191
- #include <reg51.h> 1 2 3 sbit button=p1^0; 4 sbit led=p1^1; 5 bit led state=0; 6 7 8日void delay(unsigned int ms){ 9 unsigned int i,j; 10 for(i=ms;i>0;i--) 11 for(j=110;j>0;j--); 1213 14 void main()【 15 while(1){ 16 if (button==0){ 17 delay(20); 18 if (button==0){ 19 1ed=0; 20 21 } 做详细注释(830点数解答 | 2024-10-29 15:29:41)216
- #include <reg51.h> 1 2 3 sbit button=p1^0; 4 sbit led=p1^1; 5 bit led state=0; 6 7 8日void delay(unsigned int ms){ 9 unsigned int i,j; 10 for(i=ms;i>0;i--) 11 for(j=110;j>0;j--); 1213 14 void main()【 15 while(1){ 16 if (button==0){ 17 delay(20); 18 if (button==0){ 19 1ed=0; 20 21 } 做注释(693点数解答 | 2024-10-29 15:31:00)333
- #include <reg51.h> 1 2 3 sbit button=p1^0; 4 sbit led=p1^1; 5 bit led state=0; 6 7 8日void delay(unsigned int ms){ 9 unsigned int i,j; 10 for(i=ms;i>0;i--) 11 for(j=110;j>0;j--); 1213 14 void main()【 15 while(1){ 16 if (button==0){ 17 delay(20); 18 if (button==0){ 19 1ed=0; 20 21 }(570点数解答 | 2024-10-29 15:32:29)180
- #include <reg51.h> 3 sbit button=p1^0; 4 sbit led=pl^1; 5 6 bit led_state=0; 7 8日void delay(unsigned int ms){ 9 unsigned int i,j: 10 for(i=ms;i>0;i--) 11 for(j=110;j>0;j--); 12 } 13 14日void main(){ 15 while(1){ 16 白 if (button==0){ 17 delay(20); 18 if (button-=0){ 19 while (button==ah; 20 led state=~led state; 21 led=led state; 22 } 写详细注释(697点数解答 | 2024-10-29 14:54:31)221
- 实现哈希表创建及查找算法,哈希函数使用除余法,用线性探测法处理冲突。 函数接口定义: void createhash(hashtable ht[],int n); //输入不大于m的n个不为0(0表示空值)的数,用线性探查法解决冲突构造散列表 int searchhash(hashtable ht[],int key); //输入一个值key,在散列表中查找key位置 其中 ht 表示哈希表, n表示记录数,key要查找的关键字 裁判测试程序样例: #include<iostream> using namespace std; #define m 16 #define nullkey 0 //单元为空的标记 struct hashtable{ int key; }; void createhash(hashtable ht[],int n); int searchhash(hashtable ht[],int key); int main() { int value,key; int result; int i,j,n; hashtable ht[m]; for(i=0;i<m;i++) ht[i].key=0; cin >> n; if(n>m) return 0; createhash(ht,n); cin >> key; result=searchhash(ht,key); if(result!=-1) cout << "search success,the key is located in "<< result+1; else cout << "search failed"; return 0; } /* 请在这里填写答案 */ 输入样例: 12 19 14 23 1 68 20 84 27 55 11 10 79 55 输出样例: 输出拓扑序列。 search success,the key is located in 6(504点数解答 | 2024-12-21 16:14:58)177