C++ 实现：根据给定序列与条件计算满足要求的整数对数量

以下是用 C++ 实现上述问题的代码： ```cpp #include <iostream> using namespace std; int main() { int N, M; cin >> N >> M; int L[N], R[N]; for (int i = 0; i < N; i++) { cin >> L[i] >> R[i]; } int count = 0; for (int l = 1; l <= M; l++) { for (int r = l; r <= M; r++) { bool valid = true; for (int i = 0; i < N && valid; i++) { if ((l >= L[i] && r <= R[i]) || (l <= L[i] && r >= R[i])) { valid = false; } } if (valid) { count++; } } } cout << count << endl; return 0; } ``` ######[AI问答 | 232点数解答 | 2025-04-23 17:33:20]