C 语言实现：位示图管理 8*8 块存储器，精准输出进程页面对应块号

```c #include <stdio.h> // 定义位示图的大小 #define BLOCK_SIZE 64 // 位示图数组 int bitmap[BLOCK_SIZE]; // 初始化位示图 void initBitmap() { for (int i = 0; i < BLOCK_SIZE; i++) { bitmap[i] = 0; } } // 标记已占用的块 void markOccupiedBlocks(int occupiedBlocks[]) { for (int i = 0; i < sizeof(occupiedBlocks) / sizeof(occupiedBlocks[0]); i++) { bitmap[occupiedBlocks[i]] = 1; } } // 计算页面对应的块号 int getBlockNumber(int processNumber, int pageNumber) { int requestedBlocks = 0; switch (processNumber) { case 1: requestedBlocks = 1; break; case 2: requestedBlocks = 2; break; case 3: requestedBlocks = 3; break; case 4: requestedBlocks = 4; break; } if (pageNumber < 0 || pageNumber >= 54) { return -1; } int startBlock = -1; int found = 0; for (int i = 0; i < BLOCK_SIZE &&!found; i++) { if (bitmap[i] == 0) { if (startBlock == -1) { startBlock = i; } if (i - startBlock + 1 == requestedBlocks) { found = 1; for (int j = startBlock; j < i + 1; j++) { bitmap[j] = 1; } return startBlock + pageNumber; } } else { startBlock = -1; } } return -1; } int main() { initBitmap(); int occupiedBlocks[] = {1, 3, 5, 7, 9, 11, 13, 15, 17, 19}; markOccupiedBlocks(occupiedBlocks); int processRequests[4]; printf("请输入四个进程所申请的内存块数，以空格分隔：\n"); for (int i = 0; i < 4; i++) { scanf("%d", &processRequests[i]); } int processNumber, pageNumber; printf("请输入进程编号和页面编号，以空格分隔：\n"); scanf("%d %d", &processNumber, &pageNumber); int blockNumber = getBlockNumber(processNumber, pageNumber); if (blockNumber == -1) { printf("wait\n"); } else if (blockNumber < 0) { printf("error\n"); } else { printf("%d\n", blockNumber); } return 0; } ``` 额外需要注意的逻辑点： 1. 输入的进程编号和页面编号的有效性检查要严谨。 2. 在位示图的扫描和标记过程中，要注意边界情况和逻辑的完整性。 3. 对于进程申请内存空间不足的处理，要清晰明确。 ######[AI写代码神器 | 768点数解答 | 2024-12-02 10:56:18]