在文本框内输入内容,点击“问AI”即可获得参考结果
"酷代码AI"是一家去中心化AI发财平台,旨在共享AI低成本地处理文案类、代码类的工作,提升学习、工作的效率与质量。一次注册,畅游多家AI产品!
最新免费问AI
- [字节豆包] def jc(n): if n == 0 and n == 1: return 1 else: return n* a=int(input("起始数:")) b=int(input("终止数:")) s = ③ for i in range(a, ④): s = s+⑤ print("[", a, ",", b, "]区间各数阶乘和s=", s)(642点数解答 | 2026-01-08 16:13:55)17
- [字节豆包] total = 0 days = int(input("这个月有多少天?")) for i in range(days): ex= float(input(f"第{i+1}天的花费:")) total += days ave=total/days print("月总开支:",total,"元") print("日均花费:",ave,"元") (373点数解答 | 2026-01-08 16:12:03)26
- [字节豆包] import time import os for i in range(10, ①, ②): print(③) time.④(1) # 暂停1秒 os.system("cls") # 清屏(679点数解答 | 2026-01-08 16:03:20)18
- [字节豆包] def f(m, n): # 递归定义函数,求m和n的最大公约数 if n%m == 0: # m可以被n整除 return n # 求得最大公约数 else: q = m % n return f(n, q) a = int(input('请输入第一个正整数:')) b = int(input('请输入第二个正整数:')) print(def()) (452点数解答 | 2026-01-08 15:56:44)14
- [字节豆包] count = 0 numbers = ① # 初始化列表 for i in range(1, 101): if i % 2 == 0 ② i % 3 == 0: # 判断是否既能被2整除又能被3整除 count += ③ numbers.④(i) print("1-100既能被2整除又能被3整除的数字有",count,"个") print(⑤)(483点数解答 | 2026-01-08 15:56:29)19
- [字节豆包] count = 0 numbers = 0 # 初始化列表 for i in range(1, 101): if i % 2 == 0 and i % 3 == 0: # 判断是否既能被2整除又能被3整除 count += count+1 numbers.count(i) print("1-100既能被2整除又能被3整除的数字有",count,"个") print(numbers)(499点数解答 | 2026-01-08 15:54:05)21
- [字节豆包] card = input("请输入18位身份证号码:") count = 0 for i in count: if i == : count = count+1 if ④: print("恭喜",card, "的用户获得幸运礼物!") ⑤: print("很遗憾",card, "的用户未能获得礼物!") (391点数解答 | 2026-01-08 15:46:59)19
- [字节豆包] x = int(input("请输入一个正整数:")) if : print(x, "是偶数。") else: print(x, "是奇数。")(361点数解答 | 2026-01-08 15:44:40)21
- [字节豆包] import random #导入随机模块 m = random.randint(1, 100) # 产生一个1~100的正整数 for i in range(5): t = int(input("请输入你猜的数:")) if t > m: print("数偏大") ② t < m: print("数偏小") else: print("猜中了!") ③ # 退出循环 if t != m: print("这个数是:", m) print("5次没有猜中,很遗憾,游戏结束")(453点数解答 | 2026-01-08 15:21:05)27
- [字节豆包] otal = ① days = int(input("这个月有多少天?")) for i in range(②): ex= float(input(f"第{i+1}天的花费:")) total += ③ ave=④ print("月总开支:",total,"元") print("日均花费:",ave,"元")(442点数解答 | 2026-01-08 15:06:06)21
- [字节豆包] import ① def area(n): s=math.pi*② return s r=float(input("请输入圆的半径:")) print(③)(475点数解答 | 2026-01-08 14:44:40)11
- [字节豆包] total = days = int(input("这个月有多少天?")) for i in range(②): ex= float(input(f"第{i+1}天的花费:")) total += ③ ave=④ print("月总开支:",total,"元") print("日均花费:",ave,"元") (311点数解答 | 2026-01-08 14:42:12)28