根据下面内容写个模拟登录 get /kgamebox/securities/status?channel=official&phonenum=18437835222&useridentity=ebad5652e85739b22a9578908044061f http/1.1 pcode: 309021 ptype: 1 blackbox: ngphs1729846493rn6dky1fz81 signkey: n***aae*********ag***n0ivysqpq5piqwblpjrmnpewzga6hlgn4/7z3mn+rhtm***agxvz39mpkkl6dunx3lu6i/dfrehx4asuodbawpqjv1npkhzgp4gcnm/ppm2y7lv4i***adhif3r+jwbumjcmrgszhb7zwoctcozmmx0usr5w/ynjh***ac+cfvljc9nx+dufccinyiogkyi3ukxjxwzdutn+t3xwa== signtime: 1729846616118 nonce: 203176324 signversion: 9 host
下面是一个简单的模拟登录请求示例,基于您提供的信息: ```python import requests import time import hashlib # 设置基本参数 url = "http://example.com/kgamebox/securities/status" # 替换为实际的 URL params = { 'channel': 'official', 'phonenum': '18437835222', 'useridentity': 'ebad5652e85739b22a9578908044061f' } headers = { 'Host': 'example.com', # 替换为实际的 Host 'pcode': '309021', 'ptype': '1', 'blackbox': 'ngphs1729846493rn6dky1fz81', 'signkey': 'n*aae*ag*n0ivysqpq5piqwblpjrmnpewzga6hlgn4/7z3mn+rhtm*agxvz39mpkkl6dunx3lu6i/dfrehx4asuodbawpqjv1npkhzgp4gcnm/ppm2y7lv4i*adhif3r+jwbumjcmrgszhb7zwoctcozmmx0usr5w/ynjh*ac+cfvljc9nx+dufccinyiogkyi3ukxjxwzdutn+t3xwa==', 'signtime': str(int(time.time() * 1000)), # 当前时间戳(以毫秒为单位) 'nonce': '203176324', 'signversion': '9' } # 发送请求 response = requests.get(url, params=params, headers=headers) # 打印响应 print(response.status_code) print(response.text) ``` 注意事项: 1. 将 `http://example.com` 替换为实际的 API URL。 2. 根据 API 的具体要求,检查是否需要其他的请求参数和 headers。 3. 在可能的情况下,确保敏感信息(如 `signkey` 和 `blackbox`)以安全的方式处理。 4. 该代码使用 `requests` 库,需要安装 `requests` 库(可以使用 `pip install requests` 命令)来运行。 [2024-10-25 17:16:54 | AI写代码神器 | 872点数解答]
- [GPT] 根据下面内容写个模拟登录 get /kgamebox/securities/status?channel=official&phonenum=18437835222&useridentity=ebad5652e85739b22a9578908044061f http/1.1 pcode: 309021 ptype: 1 blackbox: ngphs1729846493rn6dky1fz81 signkey: n***aae*********ag***n0ivysqpq5piqwblpjrmnpewzga6hlgn4/7z3mn+rhtm***agxvz39mpkkl6dunx3lu6i/dfrehx4asuodbawpqjv1npkhzgp4gcnm/ppm2y7lv4i***adhif3r+jwbumjcmrgszhb7zwoctcozmmx0usr5w/ynjh***ac+cfvljc9nx+dufccinyiogkyi3ukxjxwzdutn+t3xwa== signtime: 1729846616118 nonce: 203176324 signversion: 9 host(872点数解答 | 2024-10-25 17:16:54)105
- [字节豆包] <buff id="10022" moment="64" desc="白天海军单位继续攻击"> <conditions> <area host="0" field="time" data="0"/> <legion host="0" field="excbuff" data="10023" /> <legion host="0" field="tag" rule="ba" data="4"/> <legion host="0" field="marchdistance" rule="lt" data="1"/> </conditions> <results> <legion host="0" func="canattack=" args="1"/> <legion host="0" func="appendbuff=" args="10023" /> </results> </buff>(59点数解答 | 2024-11-26 14:22:04)245
- [阿里通义] 分析 <buff id="10022" moment="64" desc="白天海军单位继续攻击"> <conditions> <area host="0" field="time" data="0"/> <legion host="0" field="excbuff" data="10023" /> <legion host="0" field="tag" rule="ba" data="4"/> <legion host="0" field="marchdistance" rule="lt" data="1"/> </conditions> <results> <legion host="0" func="canattack=" args="1"/> <legion host="0" func="appendbuff=" args="10023" /> </results> </buff> <buff id="10023" moment="0" round="1" >(566点数解答 | 2024-11-26 14:24:12)241
- [字节豆包] <buff id="42505" moment="32" desc=""> <conditions> <legion host="1" field="general.id" rule="gt" data="0"/> <legion host="0" field="tag" rule="ba" data="4"/> <legion host="0" field="contrastareadistance" rule="eq" data="1"/> <legion host="1" field="neighboringfriends" data="0" /> <legion host="0" field="random100" rule="lte" data="25" corrections="0,2,100,1,3,-100"/> </conditions> <results> <legion host="1" func="replacebuff=" args="32012" />(54点数解答 | 2024-12-12 13:23:24)210
- [阿里通义] <buff id="42505" moment="32" desc=""> <conditions> <legion host="1" field="general.id" rule="gt" data="0"/> <legion host="0" field="tag" rule="ba" data="4"/> <legion host="0" field="contrastareadistance" rule="eq" data="1"/> <legion host="1" field="neighboringfriends" data="0" /> <legion host="0" field="random100" rule="lte" data="25" corrections="0,2,100,1,3,-100"/> </conditions> <results> <legion host="1" func="replacebuff=" args="32012" />(497点数解答 | 2024-12-12 13:24:26)220
- [GPT] <buff id="42505" moment="32" desc=""> <conditions> <legion host="1" field="general.id" rule="gt" data="0"/> <legion host="0" field="tag" rule="ba" data="4"/> <legion host="0" field="contrastareadistance" rule="eq" data="1"/> <legion host="1" field="neighboringfriends" data="0" /> <legion host="0" field="random100" rule="lte" data="25" corrections="0,2,100,1,3,-100"/> </conditions> <results> <legion host="1" func="replacebuff=" args="32012" />(332点数解答 | 2024-12-12 13:26:06)236
- [阿里通义] <buff id="35501" moment="1" desc="二刀流"> <results> <legion host="0" func="ReplaceBuff=" args="35511"/> </results> </buff> <buff id="35511" moment="64" index="1" round="2" type="1" display="35501"> <conditions> <legion host="0" field="Tag" rule="ba" data="4"/> <global host="1" field="ObjType" data="3"/> <area host="0" field="ExcTerrainType" data="10100" /> </conditions> <results> <legion host="0" func="CastSkillToSelf=" args="355210,100007"/(651点数解答 | 2025-03-17 13:52:25)195
- [讯飞星火] fn decode(encrypt_data: &str) { // 截取前32个字节作为key let key = hex::decode("fc27253dcc7b6d4f42f69f151d6c8c574745194b0e7609bec3fa42c644da1caf").unwrap(); // 转换key let key = key::<aes256gcm>::from_slice(&key); let encrypt_data = hex::decode(encrypt_data).unwrap(); // iv 0-12 let iv = &encrypt_data[0..12]; // 转换为 nonce let iv = nonce::from_slice(&iv); // tag 12 - 28 // let tag = &encrypt_data[12..28]; // 转换为tag // let tag = nonce::from_s(379点数解答 | 2024-07-07 01:05:44)290
- [GPT] 编写一个爬虫实现深度优先爬虫,爬取的网站为 www.baidu.com。使其输出预期为:Add the seeds url ['http://www.baidu.com'] to the unvisited url list Pop out one url "http://www.baidu.com" from unvisited url list Get 10 new links Visited url count: 1 Visited deepth: 1 10 unvisited links: Pop out one url "http://news.baidu.com" from unvisited url list Get 52 new links Visited url count: 2 Visited deepth: 2 Pop out one url "http://www.hao123.com" from unvisited url list Get 311 new links Visited url count: 3 Visited deepth: 2 Pop out(2142点数解答 | 2025-05-13 15:54:49)274
- [字节豆包] 给以下代码进行注释: fn czzb a b c=(--已知三点a、b、c,求c点在ab直线上的垂足坐标 ab=b-a; ac=c-a; lab=length ab; lac=length ac; cosct=((dot ab ac)/(lab*lac));--求出cosct abxl=if cosct>=0 then ab/lab;else -1*(ab/lab)--ab的单位向量 lty=abs (lac*cosct);--求出投影长度 xl=lty*abxl;--求出偏移向量 return (a+xl);--返回垂足坐标 ) -- fn qiumianji v1 v2 v3=( -- local chang=length (v3-v1); -- local v0=czzb v1 v3 v2; -- local gao=length (v0-v2) -- local mj=0.5*chang*gao; -- return mj; -- ) fn qiumianji v1 v2 v3=( local a=length (v1-v2); local(324点数解答 | 2024-10-16 18:51:32)289
- [百度文心] 作为golang开发,golong中无缓冲的 channel 和 有缓冲的 channel 的区别?(244点数解答 | 2023-11-09 18:14:15)133
- [字节豆包] 在易语言中实现高并发的 HTTP 操作是一个具有一定复杂性和挑战性的任务。 为了处理高并发的 HTTP 请求,可能需要考虑以下几个方面: 1. 多线程:使用多线程技术,让多个线程同时处理不同的 HTTP 请求,以提高并发处理能力。 2. 线程池:管理和复用线程,避免频繁创建和销毁线程带来的性能开销。 3. 异步操作:利用异步方式进行 HTTP 请求,使得在等待响应的过程中可以处理其他任务。 4. 连接池:对于 HTTP 连接进行管理和复用,减少创建连接的时间开销。(849点数解答 | 2025-06-03 23:17:33)228