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Python编程:实现名字与年份密码按手机字母规则变换

```python def transform_password(password): result = "" for char in password: if char.islower(): if char in 'abc': result += '2' elif char in 'def': result += '3' elif char in 'ghi': result += '4' elif char in 'jkl': result += '5' elif char in'mno': result += '6' elif char in 'pqrs': result += '7' elif char in 'tuv': result += '8' elif char in 'wxyz': result += '9' elif char.isupper(): lower_char = char.lower() if lower_char == 'z': result += 'a' elif lower_char == 'y': result += 'b' elif lower_char == 'x': result += 'c' elif lower_char == 'w': result += 'x' elif lower_char == 'v': result += 'w' elif lower_char == 'u': result += 'v' elif lower_char == 't': result += 'u' elif lower_char =='s': result += 't' elif lower_char == 'r': result +='s' elif lower_char == 'q': result += 'r' elif lower_char == 'p': result += 'q' elif lower_char == 'o': result += 'p' elif lower_char == 'n': result += 'o' elif lower_char =='m': result += 'n' elif lower_char == 'l': result +='m' elif lower_char == 'k': result += 'l' elif lower_char == 'j': result += 'k' elif lower_char == 'i': result += 'j' elif lower_char == 'h': result += 'i' elif lower_char == 'g': result += 'h' elif lower_char == 'f': result += 'g' elif lower_char == 'e': result += 'f' elif lower_char == 'd': result += 'e' elif lower_char == 'c': result += 'd' elif lower_char == 'b': result += 'c' elif lower_char == 'a': result += 'b' else: result += char return result original_password = "yuanzhi1987" new_password = transform_password(original_password) print(new_password) ``` ######[AI写代码神器 | 624点数解答 | 2024-10-23 17:55:04]

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