C++ 实现：判断拉面面料能否满足需求及最小消耗计算

以下是使用 C++ 解决此问题的代码： ```cpp #include <iostream> #include <vector> #include <algorithm> bool canMeetRequirement(int n, int u, std::vector<int>& ai, int m) { int totalLength = n * u; for (int len : ai) { totalLength += len; } return totalLength >= m; } int minConsumption(int n, int u, std::vector<int>& ai, int m) { std::sort(ai.begin(), ai.end(), std::greater<int>()); int totalLength = n * u; int consumption = 0; int i = 0; while (totalLength < m && i < ai.size()) { if (totalLength + ai[i] >= m) { consumption += m - totalLength; break; } else { totalLength += ai[i]; consumption += ai[i]; i++; } } return consumption; } int main() { int n, u, k, m; std::cin >> n >> u >> k >> m; std::vector<int> ai(k); for (int i = 0; i < k; i++) { std::cin >> ai[i]; } if (canMeetRequirement(n, u, ai, m)) { std::cout << minConsumption(n, u, ai, m) << std::endl; } else { std::cout << "无法满足要求" << std::endl; } return 0; } ``` 这段代码首先定义了一个函数`canMeetRequirement`来判断现有的面料是否能满足小朋友的要求。然后定义了`minConsumption`函数来计算满足要求时的最小消耗面料长度之和。在`main`函数中读取输入，并根据情况输出结果。 ######[AI写代码神器 | 441点数解答 | 2024-09-28 11:31:36]