C语言实现：从含搜索概率的关键字序列构建最优二叉查找树并计算平均访问结点数

解析：首先需要计算每个关键字和虚拟键的搜索概率，然后根据这些概率构建最优二叉查找树，最后计算平均搜索每个结点的访问结点数的值。 代码如下： ```c #include <stdio.h> #include <stdlib.h> typedef struct Node { float key; float prob; struct Node *left, *right; } Node; Node* newNode(float key, float prob) { Node* node = (Node*)malloc(sizeof(Node)); node->key = key; node->prob = prob; node->left = node->right = NULL; return node; } Node* insert(Node* root, float key, float prob) { if (root == NULL) return newNode(key, prob); if (key < root->key) root->left = insert(root->left, key, prob); else if (key > root->key) root->right = insert(root->right, key, prob); return root; } void inorderTraversal(Node* root, float* sum_prob, int* count) { if (root != NULL) { inorderTraversal(root->left, sum_prob, count); *sum_prob += root->prob; (*count)++; inorderTraversal(root->right, sum_prob, count); } } int main() { int n; scanf("%d", &n); float p[n]; for (int i = 0; i < n; i++) scanf("%f", &p[i]); float d[n + 1]; for (int i = 0; i < n + 1; i++) scanf("%f", &d[i]); Node* root = NULL; for (int i = 0; i < n; i++) { root = insert(root, p[i], d[i]); } for (int i = 0; i < n + 1; i++) { root = insert(root, d[i], d[i]); } float sum_prob = 0; int count = 0; inorderTraversal(root, &sum_prob, &count); printf("%.2f ", sum_prob / count); return 0; } ``` 输入样例： ``` 4 15 0.1 0.05 0.1 0.2 0.05 0.1 0.05 0.05 0.05 0.1 ``` 输出样例： ``` 0.08 ``` ######[AI写代码神器 | 666点数解答 | 2024-05-30 18:04:53]