Python实现：输入学生数量计算各科成绩平均分、标准差与中位数

首先，我们需要导入所需的库，然后定义一个函数来计算各科成绩的平均分、标准差和中位数。根据输入的学生数量n，生成学生学号及各科成绩，并调用函数计算输出结果。 解析： 1. 导入random库 2. 定义一个函数calculate_statistics，输入为各科成绩列表，输出为平均分、标准差和中位数 3. 获取输入的学生数量n 4. 生成学生学号及各科成绩 5. 调用calculate_statistics函数计算各科成绩的统计值 6. 输出结果 代码如下： ```python import random def calculate_statistics(scores): n = len(scores) average = sum(scores) / n variance = sum([(x - average) 2 for x in scores]) / n std_dev = variance 0.5 sorted_scores = sorted(scores) median = (sorted_scores[n // 2] + sorted_scores[-(n // 2 + 1)]) / 2 return round(average, 2), round(std_dev, 2), round(median, 2) n = int(input("请输入学生数量：")) random.seed(10) students = [['学号', '语文', '数学', '外语']] for i in range(n): student_id = 2023101 + i chinese = random.randint(60, 100) math = random.randint(60, 100) english = random.randint(60, 100) students.append([student_id, chinese, math, english]) print(students) chinese_scores = [x[1] for x in students[1:]] math_scores = [x[2] for x in students[1:]] english_scores = [x[3] for x in students[1:]] chinese_avg, chinese_std_dev, chinese_median = calculate_statistics(chinese_scores) math_avg, math_std_dev, math_median = calculate_statistics(math_scores) english_avg, english_std_dev, english_median = calculate_statistics(english_scores) print("语文平均分：", chinese_avg, "语文标准差：", chinese_std_dev, "语文中位数：", chinese_median) print("数学平均分：", math_avg, "数学标准差：", math_std_dev, "数学中位数：", math_median) print("英语平均分：", english_avg, "英语标准差：", english_std_dev, "英语中位数：", english_median) ``` 运行上述代码，输入学生数量n，即可得到各科成绩的平均分、标准差和中位数。 ######[AI写代码神器 | 715点数解答 | 2024-05-08 11:20:09]