Verilog HDL在Quartus - II基于FPGA实现八人抢答系统：附完整代码及功能解析

首先，我们需要设计一个Verilog模块，该模块包含以下功能： 1. 主持人按钮输入检测 2. 抢答选手按钮输入检测 3. 最先抢答的选手显示在七段数码管上 以下是完整的Verilog代码： ```verilog module quiz_system( input wire clk, input wire reset, input wire host_button, input wire [7:0] player_buttons, output reg [6:0] seg, output reg [3:0] an ); // 主持人按钮状态 reg host_button_pressed; // 抢答选手按钮状态 reg [7:0] player_buttons_pressed; // 最先抢答的选手编号 reg [2:0] first_player; // 时钟分频器 reg [25:0] clk_divider; always @(posedge clk or posedge reset) begin if (reset) begin clk_divider <= 26'b0; end else begin clk_divider <= clk_divider + 1; end end // 主持人按钮检测 always @(posedge clk or posedge reset) begin if (reset) begin host_button_pressed <= 1'b0; end else if (clk_divider[25]) begin host_button_pressed <= host_button; end end // 抢答选手按钮检测 always @(posedge clk or posedge reset) begin if (reset) begin player_buttons_pressed <= 8'b0; end else if (host_button_pressed) begin player_buttons_pressed <= player_buttons; end end // 最先抢答的选手编号 always @(posedge clk or posedge reset) begin if (reset) begin first_player <= 3'b0; end else if (host_button_pressed) begin first_player <= 3'b0; for (integer i = 0; i < 8; i++) begin if (player_buttons_pressed[i]) begin first_player <= i; break; end end end end // 七段数码管显示 reg [3:0] bcd; always @(posedge clk or posedge reset) begin if (reset) begin bcd <= 4'b0; end else if (host_button_pressed) begin bcd <= first_player; end end // 七段数码管驱动 always @(posedge clk or posedge reset) begin if (reset) begin an <= 4'b1110; end else if (clk_divider[25]) begin case (bcd) 4'b0000: seg <= 7'b1000000; // 0 4'b0001: seg <= 7'b1111001; // 1 4'b0010: seg <= 7'b0100100; // 2 4'b0011: seg <= 7'b0110000; // 3 4'b0100: seg <= 7'b0011001; // 4 4'b0101: seg <= 7'b0010010; // 5 4'b0110: seg <= 7'b0000010; // 6 4'b0111: seg <= 7'b1111000; // 7 4'b1000: seg <= 7'b0000000; // 8 4'b1001: seg <= 7'b0010000; // 9 default: seg <= 7'b1111111; // 空白 endcase an <= 4'b1110; end end endmodule ``` 这个代码实现了一个简单的抢答系统，主持人按下按钮后，最先抢答的选手的编号会显示在七段数码管上。注意，这个代码没有考虑按键消抖和显示刷新的问题，你可以根据实际需求进行优化。 ######[AI写代码神器 | 1099点数解答 | 2024-05-02 10:55:38]