Python 实现从 scores.txt 读取信息，精准计算三人平均成绩与三科平均成绩

可以使用以下代码实现从scores.txt文件读取信息，并计算三个人的平均成绩和三个科目的平均成绩： ```python def read_scores_file(file_path): # 读取文件并返回一个包含所有成绩的列表 scores = [] with open(file_path, 'r') as file: for line in file: line = line.strip() scores.append(list(map(float, line.split()))) return scores def calculate_student_avg(scores): # 计算每个学生的平均成绩并返回一个包含平均成绩的列表 student_avg = [] for student in scores: avg = sum(student) / len(student) student_avg.append(avg) return student_avg def calculate_subject_avg(scores): # 计算每个科目的平均成绩并返回一个包含平均成绩的列表 subject_avg = [] num_subjects = len(scores[0]) for i in range(num_subjects): subject_scores = [student[i] for student in scores] avg = sum(subject_scores) / len(subject_scores) subject_avg.append(avg) return subject_avg # 文件路径 file_path = 'scores.txt' # 从文件中读取信息 scores = read_scores_file(file_path) # 计算每个学生和每个科目的平均成绩 student_avg = calculate_student_avg(scores) subject_avg = calculate_subject_avg(scores) # 输出结果 for i, avg in enumerate(student_avg): print(f'Student {i+1} average score: {avg}') for i, avg in enumerate(subject_avg): print(f'Subject {i+1} average score: {avg}') ``` 请确保文件`scores.txt`存在，并按照每行一个学生的成绩，每个成绩之间使用空格分隔的格式存储信息。 ######[AI写代码神器 | 1280点数解答 | 2024-04-21 16:01:42]