valueerror: length mismatch: expected axis has 3 elements, new values have 4 elements


The error message "ValueError: length mismatch: expected axis has 3 elements, new values have 4 elements" in Python typically occurs when you're trying to assign or concatenate arrays (such as numpy arrays) with different shapes along a particular axis. In this specific case, it suggests that somewhere in your code, you're attempting to fit an array with 4 dimensions into a structure expecting an array with 3 dimensions. For instance, if you have a 3D array (with 3 axes/dimensions) and you're trying to add or insert a 4D array into one of its axes, this kind of error would be raised because the dimensionality does not match. To fix this issue, ensure that the dimensions of both arrays are compatible. You might need to reshape or slice the array before assigning it, so that both arrays have matching numbers of dimensions and sizes along each axis. Here's a simple example: ```python import numpy as np # Let's say we have a 3D array: array_3d = np.zeros((2, 2, 2)) # And we try to assign a 4D array to it: array_4d = np.ones((2, 2, 2, 2)) # This would raise the ValueError: array_3d[0] = array_4d # To resolve the issue, we could reshape the 4D array to match the 3D shape: array_4d_flat = array_4d.reshape(2, 2, 4) # Now, if the new shape is suitable for assignment along the target axis, the operation can proceed. ``` Please refer to your specific situation to understand how to correctly reshape or manipulate your data. [2024-01-12 16:50:44 | AI写代码神器 | 361点数解答]
- valueerror: length mismatch: expected axis has 3 elements, new values have 4 elements(56点数解答 | 2024-01-12 16:50:26)283
- valueerror: length mismatch: expected axis has 3 elements, new values have 4 elements(361点数解答 | 2024-01-12 16:50:44)282
- python data = {'10月':{'a': 23.1, 'b': 21.9}, '11月': {'a': 1, 'b': 3}, '12月': {'a': 2, 'b': 8}}写入到excel中,自定义表头 [‘产品’,‘10月’,‘‘12月’,‘‘12月’] valueerror: length mismatch: expected axis has 3 elements, new values have 4 elements(401点数解答 | 2024-01-12 17:24:16)281
- python data = {'10月':{'a': 23.1, 'b': 21.9}, '11月': {'a': 1, 'b': 3}, '12月': {'a': 2, 'b': 8}}写入到excel中,自定义表头 [‘产品’,‘10月’,‘‘12月’,‘‘12月’] valueerror: length mismatch: expected axis has 3 elements, new values have 4 elements(288点数解答 | 2024-01-12 17:24:54)260
- python data = {'10月':{'a': 23.1, 'b': 21.9}, '11月': {'a': 1, 'b': 3}, '12月': {'a': 2, 'b': 8}}写入到excel中,自定义表头 [‘产品’,‘10月’,‘‘12月’,‘‘12月’] valueerror: length mismatch: expected axis has 3 elements, new values have 4 elements(286点数解答 | 2024-01-12 17:26:30)242
- 继承以上rect类,设计一个newrect类,要求添加一个数据成员,用以存放矩形位置, 位置坐标通常为矩形左上角坐标,用元组表示,例如(x,y),然后 修改构造方法; 设计move()方法,将矩形从一个位置移动到另一个位置; 设计size()方法改变矩形大小; 设计where()返回矩形左上角的坐标值。 class rect: def __init__(self,length,width): self.length=length self.width=width def perimeter(self): return 2*(self.length+self.width) def area(self): return self.length*self.width def show(self): print("该矩形的信息如下:") print("长=",self.length,end=",") p(110点数解答 | 2025-01-02 23:42:09)173
- 继承以上rect类,设计一个newrect类,要求添加一个数据成员,用以存放矩形位置, 位置坐标通常为矩形左上角坐标,用元组表示,例如(x,y),然后 修改构造方法; 设计move()方法,将矩形从一个位置移动到另一个位置; 设计size()方法改变矩形大小; 设计where()返回矩形左上角的坐标值。 class rect: def __init__(self,length,width): self.length=length self.width=width def perimeter(self): return 2*(self.length+self.width) def area(self): return self.length*self.width def show(self): print("该矩形的信息如下:") print("长=",self.length,end=",") p(94点数解答 | 2025-01-02 23:42:11)163
- 继承以上rect类,设计一个newrect类,要求添加一个数据成员,用以存放矩形位置, 位置坐标通常为矩形左上角坐标,用元组表示,例如(x,y),然后 修改构造方法; 设计move()方法,将矩形从一个位置移动到另一个位置; 设计size()方法改变矩形大小; 设计where()返回矩形左上角的坐标值。 class rect: def __init__(self,length,width): self.length=length self.width=width def perimeter(self): return 2*(self.length+self.width) def area(self): return self.length*self.width def show(self): print("该矩形的信息如下:") print("长=",self.length,end=",") p(94点数解答 | 2025-01-02 23:42:12)183
- void createlist(listnode* &phead) { phead - new listnode(0): listnodc*p= phcad; for (inti-1;i<10;i++){ listnode*ptmp= new listnode(i); p->next-ptmp; p-ptmp; 创建循环链表 void createlooplist(listnode*&phead) phead-new listnode(0); listnode*p=phead: int length-10; listnode* loopstart-null: for (int i=1: i <length:i++) { listnode *ptmp-new listnode(i): p->next-ptmp; p-ptmp. it (i6i loopstart=ptmp; p->next-loopstart; int lengthofcop(listnode*phead /todo:实现此函数,返回环形链表的环的长度,如果静表无环,返回0 return 0; intmaino t l(193点数解答 | 2024-10-09 16:49:52)166
- void createlist(listnode* &phead) { phead - new listnode(0): listnodc*p= phcad; for (inti-1;i<10;i++){ listnode*ptmp= new listnode(i); p->next-ptmp; p-ptmp; 创建循环链表 void createlooplist(listnode*&phead) phead-new listnode(0); listnode*p=phead: int length-10; listnode* loopstart-null: for (int i=1: i <length:i++) { listnode *ptmp-new listnode(i): p->next-ptmp; p-ptmp. it (i6i loopstart=ptmp; p->next-loopstart; int lengthofcop(listnode*phead /todo:实现此函数,返回环形链表的环的长度,如果静表无环,返回0 return 0; 确定环的起始位置 int(519点数解答 | 2024-10-09 17:31:13)188
- void createlist(listnode* &phead) { phead - new listnode(0): listnodc*p= phcad; for (inti-1;i<10;i++){ listnode*ptmp= new listnode(i); p->next-ptmp; p-ptmp; 创建循环链表 void createlooplist(listnode*&phead) phead-new listnode(0); listnode*p=phead: int length-10; listnode* loopstart-null: for (int i=1: i <length:i++) { listnode *ptmp-new listnode(i): p->next-ptmp; p-ptmp. it (i6i loopstart=ptmp; p->next-loopstart; 实现此函数,返回环形链表的起始位置(438点数解答 | 2024-10-09 17:37:28)194
- 给以下代码进行注释: fn czzb a b c=(--已知三点a、b、c,求c点在ab直线上的垂足坐标 ab=b-a; ac=c-a; lab=length ab; lac=length ac; cosct=((dot ab ac)/(lab*lac));--求出cosct abxl=if cosct>=0 then ab/lab;else -1*(ab/lab)--ab的单位向量 lty=abs (lac*cosct);--求出投影长度 xl=lty*abxl;--求出偏移向量 return (a+xl);--返回垂足坐标 ) -- fn qiumianji v1 v2 v3=( -- local chang=length (v3-v1); -- local v0=czzb v1 v3 v2; -- local gao=length (v0-v2) -- local mj=0.5*chang*gao; -- return mj; -- ) fn qiumianji v1 v2 v3=( local a=length (v1-v2); local(324点数解答 | 2024-10-16 18:51:32)192