使用C++计算麻醉炮弹麻醉连续k个人的最大危险程度总和

```cpp #include <iostream> using namespace std; const int MAXN = 100000; int a[MAXN + 1]; int main() { int n, k; // 读取n和k的值 cin >> n >> k; for (int i = 1; i <= n; ++i) { // 读取每个守卫的危险程度 cin >> a[i]; } int currentSum = 0; // 计算前k个人的危险程度总和 for (int i = 1; i <= k; ++i) { currentSum += a[i]; } int maxSum = currentSum; // 滑动窗口计算连续k个人的最大危险程度总和 for (int i = k + 1; i <= n; ++i) { // 减去窗口最左边的值，加上窗口最右边的值 currentSum = currentSum - a[i - k] + a[i]; if (currentSum > maxSum) { // 更新最大危险程度总和 maxSum = currentSum; } } // 输出结果 cout << maxSum << endl; return 0; } ``` ######[AI问答 | 308点数解答 | 2026-05-30 19:37:31]