《C++计算护盾防御力值在平均值以下的护盾个数》

```cpp #include <iostream> using namespace std; int main() { int n; cin >> n; int a[101][101]; int sum = 0; for (int i = 0; i < n; i++) { for (int j = 0; j < n; j++) { cin >> a[i][j]; sum += a[i][j]; } } double average = (double)sum / (n * n); int count = 0; for (int i = 0; i < n; i++) { for (int j = 0; j < n; j++) { if (a[i][j] < average) { count++; } } } cout << count << endl; return 0; } ``` ######[AI问答 | 229点数解答 | 2026-05-23 20:28:41]