作为dba,简述select for update ?
"SELECT FOR UPDATE" 是一种在数据库中使用的锁定机制,特别是在事务处理中。它允许一个事务在读取数据的同时对其进行锁定,以防止其他事务对该数据进行修改。 以下是 "SELECT FOR UPDATE" 的一些详细说明: 1. 锁定数据:当使用 "SELECT FOR UPDATE" 语句时,数据库会锁定选定的数据行,以防止其他事务对这些数据进行修改。这种锁定持续到当前事务结束为止。 2. 阻塞:如果一个事务正在对数据进行 "SELECT FOR UPDATE",其他事务将无法对这些数据进行修改,直到第一个事务结束。这可能会导致一些并发性能问题。 3. 性能影响:"SELECT FOR UPDATE" 会对数据库性能产生影响。首先,锁定数据行需要消耗资源。如果有很多事务试图同时 "SELECT FOR UPDATE",可能会导致死锁或其他并发问题。 4. 乐观锁与悲观锁:"SELECT FOR UPDATE" 是一种悲观锁,它假设其他事务会对选定的数据进行修改。与之相对的是乐观锁,它假设其他事务不会修改选定的数据,只在数据被修改时才进行锁定。 5. 使用场景:通常在需要防止其他事务修改某些数据行的情况下使用 "SELECT FOR UPDATE"。例如,在进行长期处理或需要保证数据一致性的场景中,可以使用此语句。 6. 解锁:在事务结束时,数据库会自动解锁所锁定的数据行。如果事务中发生错误或回滚,数据库也会解锁这些数据行。 "SELECT FOR UPDATE" 是与特定的数据库管理系统(如Oracle、MySQL等)相关的。不同的数据库管理系统可能具有不同的语法和行为。 [2023-11-09 18:07:00 | AI写代码神器 | 342点数解答]
相关提问
- [阿里通义] yum update iwl135-firmware yum update iwl105-firmware yum update iwl2030-firmware yum update iwl1000-firmware yum update iwl100-firmware yum update iwl3945-firmware yum update iwl4965-firmware yum update iwl5000-firmware 对系统有什么影响(258点数解答 | 2024-04-01 10:01:54)336
- yum update iwl135-firmware yum update iwl105-firmware yum update iwl2030-firmware yum update iwl1000-firmware yum update iwl100-firmware yum update iwl3945-firmware yum update iwl4965-firmware yum update iwl5000-firmware(144点数解答 | 2024-04-01 10:02:04)371
- [讯飞星火] yum update iwl135-firmware yum update iwl105-firmware yum update iwl2030-firmware yum update iwl1000-firmware yum update iwl100-firmware yum update iwl3945-firmware yum update iwl4965-firmware yum update iwl5000-firmware 执行更新会有什么影响(193点数解答 | 2024-04-01 10:02:37)381
- [阿里通义] if (@code2 like 'item_ch_' + @itemcodeprefix + '_a_rare' and @optlevel >= 1 - @ck and @cl1 = 24670 and @cl2 = 24669 and @clsl1 > 1 and @clsl2 > 1) begin select @charname = charname16 from _char where charid = @charid; update _inventory set itemid=0 where charid=@charid and slot=13 update sro_vt_shard.._items set data=data-1 where id64 in (select itemid from sro_vt_shard.._inventory where slot=14and charid=@charid) update sro_vt_shard.._items set data=data-1 where id64 in (select itemid from sro_(969点数解答 | 2024-10-22 11:26:02)327
- [GPT] if (@code2 like 'item_ch_' + @itemcodeprefix + '_a_rare' and @optlevel >= 1 - @ck and @cl1 = 24670 and @cl2 = 24669 and @clsl1 > 1 and @clsl2 > 1) begin select @charname = charname16 from _char where charid = @charid; update _inventory set itemid=0 where charid=@charid and slot=13 update sro_vt_shard.._items set data=data-1 where id64 in (select itemid from sro_vt_shard.._inventory where slot=14and charid=@charid) update sro_vt_shard.._items set data=data-1 where id64 in ((51点数解答 | 2024-10-22 11:24:35)275
- [GPT] 帮我优化一下这个sql, 得到的结果是一样的 select to_char(sysdate, 'yyyymmdd') from dual union select to_char(sysdate-1, 'yyyymmdd') from dual union select to_char(sysdate-2, 'yyyymmdd') from dual union select to_char(sysdate-3, 'yyyymmdd') from dual union select to_char(sysdate-5, 'yyyymmdd') from dual(357点数解答 | 2024-08-14 20:08:27)394
- [GPT] 我想得到最近30天内的日期, 比如这样的sql, 但太冗余了, 有没有简化的办法, oracle库里执行: select to_char(sysdate, 'yyyymmdd') from dual union select to_char(sysdate-1, 'yyyymmdd') from dual union select to_char(sysdate-2, 'yyyymmdd') from dual union select to_char(sysdate-3, 'yyyymmdd') from dual union select to_char(sysdate-5, 'yyyymmdd') from dual(320点数解答 | 2024-08-14 20:11:26)247
- [字节豆包] 用c语言实现一个64位地址— select [0] = (6^11^16^…^51) — select [1] = (7^12^17^…^47) — select [2] = (8^13^18^…^48) — select [3] = (9^14^19^…^49) — select [4] = (10^15^20^…^50)(312点数解答 | 2024-11-19 15:34:19)212
- [字节豆包] .假设自动售货机出售4种商品,薯片(crisps)、爆米花(popcorn)、巧克力(chocolate)和可乐(cola),售价分别是每份3.0、2.5、4.0和3.5元。在屏幕上显示以下菜单,用户可以连续查询商品的价格,当查询次数超过5次时,自动退出查询;不到5次时,用户可以选择退出。当用户输入编号1~4,显示相应商品的价格;输入0,退出查询;输入其他编号,显示价格为0。 [1] Select crisps [2] Select popcorn [3] Select chocolate [4] Select cola [0] Exit (403点数解答 | 2025-11-24 00:18:28)27
- select c.table_name, c.constraint_name, c.constraint_type, c.status, c.r_owner, c.r_constraint_name, (select rc.table_name from all_constraints rc where rc.owner = c.r_owner and rc.constraint_name = c.r_constraint_name) as r_table_name, c.delete_rule, ( select listagg(column_name || ':' || position,',') within group (order by "position") from all_cons_columns col where col.owner =:1 and col.table_name = :2 and col.constraint_n(25点数解答 | 2024-01-17 17:17:40)327
- [阿里通义] select distinct t.id_card,t.`start`,t.`end` from ((select distinct(person_name), id_card , date_format( curdate(), "%y-%m-%d 00:00:00" ) start , date_format( curdate(), "%y-%m-%d 23:59:59" ) end, '1' ordertype, '-1' pass from t_contractor_people where person_name in ( select distinct ( b.executor ) from t_task_work_order a left join t_task_work_person b on a.sheet_id = b.hot_work_id where a.valid = '1' and a.work_start_time > date_format( curdate(), "%y-%m-%d 00:00:00(342点数解答 | 2024-12-05 12:31:57)223
- [GPT] select distinct t.id_card,t.`start`,t.`end` from ((select distinct(person_name), id_card , date_format( curdate(), "%y-%m-%d 00:00:00" ) start , date_format( curdate(), "%y-%m-%d 23:59:59" ) end, '1' ordertype, '-1' pass from t_contractor_people where person_name in ( select distinct ( b.executor ) from t_task_work_order a left join t_task_work_person b on a.sheet_id = b.hot_work_id where a.valid = '1' and a.work_start_time > date_format( curdate(), "%y-%m-%d 00:00:00(24点数解答 | 2024-12-05 12:32:54)247