C++ 实现：统计 1 到 n 所有整数中数字 1 的出现个数

```cpp #include <iostream> using namespace std; int main() { int n, count = 0; cin >> n; for (int i = 1; i <= n; i++) { int num = i; while (num > 0) { if (num % 10 == 1) { count++; } num /= 10; } } cout << count; return 0; } ``` ######[AI问答 | 118点数解答 | 2026-01-14 22:06:25]