阅读下列程序，当输入是 5 5 时，输出是？ 复制 int n, res = 0; cin >> n; for(int i = 1; i <= n; i++) { res *= i; } cout << res; 回答篇幅：简单明了
此程序功能是计算 `res` 依次乘以 1 到 `n` 的结果。初始 `res` 为 0，任何数乘 0 都为 0，所以无论输入 `n` 为多少，输出都是 0。输入 5 时，输出是 0。 [2025-12-21 19:14:01 | AI问答 | 68点数解答]
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