C++：轻松计算n个整数中能整除总和的数的个数

```cpp #include <iostream> using namespace std; int main() { int n; cin >> n; int arr[10]; int sum = 0; for (int i = 0; i < n; i++) { cin >> arr[i]; sum += arr[i]; } int count = 0; for (int i = 0; i < n; i++) { if (sum % arr[i] == 0) { count++; } } cout << count << endl; return 0; } ``` ######[AI问答 | 145点数解答 | 2025-12-06 19:58:57]